Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x 10 -5 K a2 = 5.0 x 10 -9.

Slides:



Advertisements
Similar presentations
Acids & Bases Acids: acids are sour tasting
Advertisements

Acid-Base Equilibria pH and pOH Relationship of Conjugate Pair acid-base strength. When acids or bases control pH:  determine K  predict pH When pH controls.
Acids, Bases, and Salts CHM 1010 PGCC Barbara A. Gage.
Chapter 15 Applications of Aqueous Equilibria. The Common-Ion Effect Common-Ion Effect: The shift in the position of an equilibrium on addition of a substance.
Chapter 17 Equilibrium in the Aqueous Phase. Clickers in Action © 2009 W. W. Norton & Company, Inc.2 What are the major species present in an aqueous.
Acid-Base Equilibria pH and pOH Relationship of Conjugate Pair acid-base strength. When acids or bases control pH:  determine K  predict pH When pH controls.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 14 Acids and Bases 14.9 Acid-Base Properties of Salt Solutions.
Drill: A M solution of HZ ionizes 20.0 %. Calculate: K aHZ.
Part 2 Chapter 17. Salt Solutions We will look at the cation and the anion separately, and then combine the result to determine whether the solution is.
Ba(OH) 2. 8H 2 O + 2NH 4 SCN  Ba(SCN) 2 + 2NH H 2 O What is the sign of  G in this reaction? What is the sign of  G in this reaction? What is.
Unit 6 - Chpt 14&15 - Acid/Base Acid basics, strengths, etc. pH scale, calculations Base basics Polyprotic acids, Acid/Base properties of salts, hydrolysis,
14.1 Intro to Acids and Bases 14.2 Acid Strength 14.3 pH Scale
Acids and Bases.
Part II. Polyprotic acid H 2 CO 3 H + + HCO 3 - Ka 1 = 4.3 x H 2 CO 3 H + + HCO 3 - Ka 1 = 4.3 x HCO 3 - H + + CO 3 -2 Ka 2 = 4.3 x
10/12/2015Lecture PLUS Timberlake1 Chapter 9 Acids and Bases Acid-Base Neutralization Buffers Acid-Base Titration.
Acids and Bases Unit 18 Acid-Base Equilibria: Buffers & Hydrolysis Dr. Jorge L. Alonso Miami-Dade College – Kendall Campus Miami, FL CHM 1046: General.
Identifying Acids and Bases Acids Acid (anhydrides) Bases Base (anhydrides) Salts contains H+ ions as the cation, with and other element as the anion.
Acid/Base Chemistry Part II CHEM 2124 – General Chemistry II Alfred State College Professor Bensley.
Unit 7 Chapter 16 and 17. Review of Acids and Bases.
Hydrolysis and Neutralization
Drill: A M solution of HZ ionizes 20.0 %. Calculate: K aHZ.
Drill: Determine the pH of 0.25 M HZ. K aHZ = 2.5 x
19.1 Acid-Base Theories> 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 1. Lactic acid, HC 3 H 5 O 3, has one acidic hydrogen.
C H E M I S T R Y Chapter 15 Applications of Aqueous Equilibria.
19.1 Acid-Base Theories> 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. Day The pH for a 0.10 M solution of a.
IX.Salts and Hydrolysis  Salts are simply ionic compounds.  Salts can be formed by: 1.A metal reacting with a non-metal. 2 Na (s) + Cl 2(g)  2 NaCl.
Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x K a2 = 5.0 x
Salts. Salt Solutions The salts of weak acids can recombine with water producing basic solutions.
Acid-Base Equilibria pH and pOH Relationship of Conjugate Pair acid-base strength. When acids or bases control pH:  determine K  predict pH When pH controls.
Salts. Salt Solutions The salts of weak acids can recombine with water producing basic solutions.
Hydrolysis and Neutralization
ACIDS AND BASES ACID – A compound that produces hydrogen ions in a water solution HCl (g) → H + (aq) + Cl - (aq) BASE – A compound that produces hydroxide.
ACIDS and BASES Chapter 18. Acids and Bases: An Introduction Acidic solution – contains more hydrogen ions than hydroxide ions. [H + ]>[OH - ] Acidic.
Acid-Base Chemistry Review Unit 6 Chapters 4, 15, 16.
Chapter 15 Applications of Aqueous Equilibria
Acids and Bases Acid-Base Neutralization Buffers Acid-Base Titration.
Acids, Bases, & Salts Acid/Base Equilibrium
Acid/Base Properties of Salt Solutions Salts Ionic compounds When dissolved in water, salts may behave as acids, bases.
Drill: Calculate the pH of 2.0 x M HI. Calculate the pH of 3.3 x M HI.
Applications of Aqueous Equilibria
Arrhenius Theory Acids release hydrogen ions (H + ) Acids release hydrogen ions (H + ) HCl → H + + Cl - HCl → H + + Cl - Bases release hydroxide ions.
19.1 Acid-Base Theories> 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. 2. HNO 3 is a strong acid – assume it completely.
Acid-Base Reactions and Titrations Chemistry. Examples of Acid-Base Rxns HNO 3 + KOH  H 2 O + KNO 3 H 2 SO NH 4 OH  (NH 4 ) 2 SO H 2 O LiOH.
Calculate the pH of 2.0 x M HI. Acid-Base Equilibria.
Salt Hydrolysis. Salts Ionic compound made up of CATION and ANION Has acidic and basic properties Based on ions produced when salts dissociate No acid/base.
Drill: Calculate the pH of 2.0 x M HI. Calculate the pH of 3.3 x M HI.
Drill: Calculate the pH of: 3.0 x M H x M HI.
Chapter Ten Acids and Bases Fundamentals of General, Organic and Biological Chemistry 6th Edition James E. Mayhugh Copyright © 2010 Pearson Education,
Acid-Base Equilibria and Solubility Equilibria Chapter 16.
ACIDS AND BASES ACID – A compound that produces hydrogen ions in a water solution HCl (g) → H + (aq) + Cl - (aq) BASE – A compound that produces hydroxide.
Acids and Bases Chapter 19. Arrhenius Acids- hydrogen containing compounds that ionize to yield H + ions in an aqueous solution Begins with H Bases- compounds.
1 Chapter 14 Acids and Bases 14.9 Acid-Base Properties of Salt Solutions Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
Drill: A M solution of HZ ionizes 20.0 %. Calculate: KaHZ
Drill: Determine the KQ/HQ ratio to make a buffer solution with a pH of 4.70 Ka for HQ = 3.0 x 10-5.
Acid Base Reactions & Theories
Drill: A M solution of HZ ionizes 20.0 %. Calculate: KaHZ
Drill: A M solution of HZ ionizes 20.0 %. Calculate: KaHZ
Strength of Acids and Bases
1A + 1B  1C + 1D Calculate the equilibrium concentrations of each species when 150 ml 2.0 M A is mixed with ml 2.0 M B. Kc = 0.25.
Acids, Bases, and Salts.
Acids, Bases, and Salts CHM 1010 PGCC Barbara A. Gage.
Salts product of neutralization reaction strong base strong acid
Polyprotic Acids.
Salts product of neutralization reaction strong base strong acid
Acid-Base Equilibria pH and pOH
Chapter 3.4 Acids and Bases
1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with mL 2.5 M B. Kc = 2.0 x
Chapter 9 Acids and Bases
Drill: Calculate the pH of M H2Z in M KHZ. Ka1 = 2
Descriptions & Reactions
Presentation transcript:

Drill: Calculate the pH of 0.10 M H 2 Z in 0.50 M KHZ. K a1 = 2.0 x K a2 = 5.0 x 10 -9

Review Drill & Check HW

CHM II HW Review PP-24. Complete the attached assignment & turn it in tomorrow.

Salt or Hydrolysis Reactions

Hydrolysis Any reaction in which water is decomposed with all or part of its decomposition portions combining with the products

Hydrolysis Water is added to decompose something

Hydrolysis MX + HOH HX + MOH

Salts

Ionic compounds that dissolve ~ 100 % in water

Salts of Acids Salts of acids are negative (A - )

Salts of Bases Salts of bases are Positive (M + or B + )

Salt Solutions When salts dissolve, their ions can recombine with water

Salt Solutions The salts of weak acids can recombine with water producing basic solutions

Salt Solutions The salts of weak bases can recombine with water producing acidic solutions

Salt Solutions A - + H 2 O HA + OH - B + + H 2 O H + + BOH

Drill: Calculate the salt/acid ratio of a solution of benzoic acid & sodium benzoate at a pH of K a HBz = 6.4 x 10 -5

Salt or Hydrolysis Problems

Drill: Calculate the pH of a solution of 0.10 M NH 3 in 0.20 NH 4 Cl. K b NH 3 = 1.8 x 10 -5

Salt Problem Calculate the pH of a 0.20 M solution of NaBz K a HBz = 6.4 x 10 -5

Salt Problem Calculate the pH of a 0.10 M solution of R-NH 3 Cl K b R-NH 2 = 2.5 x 10 -5

Drill: Calculate the pH of a 0.18 M solution of KC 2 H 3 O 2 K a = 1.8 x 10 -5

Review Drill & Check HW

Collect Labs

CHM II HW Study for a quiz tomorrow Test Monday

AP CHM HW Read: Chapter 14 Problems: 43 Page: 422

CHM II HW Read: Chapter 18 Problems: 83 Page: 790

Salt Applications Salts of strong acids & weak bases make acidic solutions

Salt Applications Salts of strong bases & weak acids make basic solutions

Salt Applications Salts of strong acids & strong bases make neutral solutions

Predict Relative pH NaAcMnCl 2 KNO 3 NH 4 Br KHSO 4 NH 4 Ac

Predict Relative pH KAcNaCl KClO 2 NH 4 Cl K 2 SO 4 NaI

Anhydrides Compounds without water; that when added to water, form other compounds

Acid Anhydrides Non-metal oxides that form acids when added to water

Basic Anhydrides Metal oxides that form bases when added to water

Predict Relative pH Na 2 OSO 2 NO 2 CO 2 CaOAl 2 O 3

Calculate the pH of a 0.16 M solution of KC 7 H 5 O 2 K a = 6.4 x 10 -5

Calculate the pH of a solution of M KQ. K a HQ = 3.0 x 10 -5

AP CHM HW Read: Chapter 14 Problems: 35 Page: 422

CHM II HW Read: Chapter 18 Problems: 67 & 75 Page:

Drill: Calculate the pH of a 0.72 M NH 4 NO 3 solution. K b NH3 = 1.8 x 10 -5

A/B eq, Buffer & Salt Hydrolysis Problems

AP Test Thursday

11.2 g of KOH was added to 2.0 L of M H 2 CO 3. Calculate the molarity of all ions present in the solution. K a1 = 4.4 x K a2 = 4.8 x

You need to make a buffer solution with its greatest buffering capacity at pH ~ 5.4. In general terms, describe what acid or base you would chose, & how you would make the buffer.

Calculate the pH of 0.10 M HF. K a HF = 6.5 x 10 -4

Calculate [H 3 PO 4 ], [H 2 PO 4 -1 ], [HPO 4 -2 ], [PO 4 -3 ], [K + ], [H + ], & pH of 1.0 M KH 2 PO 4 in 0.50 M K 2 HPO 4. K a1 = 7.5 x K a2 = 6.2 x K a3 = 4.2 x

Calculate the pH of 0.10 M HF in 0.20 M NaF. K a HF = 6.5 x 10 -4

Calculate the pH of 5.0 M KCN. K aHCN = 5.0 x

Calculate pH of: 0.20 M MOH in 0.50 M MCl K b = 5.0 x 10 -5

Calculate pH of: 0.20 M MCl K b = 5.0 x 10 -5

Drill: Calculate the pH of 0.20 M KQ. K a HQ = 8.0 x 10 -5

Predict Relative pH KAcNaCl KClO 2 NH 4 Cl K 2 SO 4 NaI

Predict Relative pH K 2 OMgO ClO 2 (NH 4 ) 2 O SO 3 N 2 O 3

Calculate pH of: 0.20 M HNO 2 K a = 2.0 x 10 -4

Calculate pH of: 3.0 M HZ in 2.0 M KZ K a HZ = 3.0 x 10 -5

Calculate pH of: 0.20 M KR K a HR = 2.0 x 10 -5

Calculate pH of: 2.0 M HQ K a = 2.0 x 10 -6

Calculate pH of: 0.60 M HZ in 0.90 M KZ K a HZ = 3.0 x 10 -5

Calculate pH of: 0.20 M KQ K a HQ = 2.0 x 10 -7

1.5 L of 0.25 M Ba(OH) 2 was added to 1.0 L of 0.60 M H 2 SO 3. Calculate [H 2 SO 3 ], [HSO 3 - ], [SO 3 -2 ], [H + ], [OH - ], & pH of the solution. K a1 = 1.7 x K a2 = 6.0 x 10 -8

Review of Acid/Base descriptions and Acid/Base, Buffer, & Salt Equilibria

Arhenius, Bronsted- Lowry, & Lewis Acids & Bases

Strong Acids Strong Bases

Acid rxns Base rxns

A/B Equilibrium Constants K W, K A, K B, & pH

Calculate pH of: M HNO M KOH

150 mL of 0.10 M KOH was added to mL of 0.10 M H 2 CO 3. Calculate [H 2 CO 3 ], [HCO 3 - ], [CO 3 -2 ], [H + ], [OH - ], & pH of the solution. K a1 = 4.4 x K a2 = 4.7 x

Calculate [H 3 A], [H 2 A -1 ], [HA -2 ], [A -3 ], [K + ], [H + ], [OH - ], & pH of 2.0 M KH 2 A. K a1 = 4.0 x K a2 = 5.0 x K a3 = 2.5 x