CMSC 104, Version 8/061L10ArithmeticOps.ppt Arithmetic Operators Topics Arithmetic Operators Operator Precedence Evaluating Arithmetic Expressions In-class Project Incremental Programming Reading Section 2.5

CMSC 104, Version 8/062L10ArithmeticOps.ppt Arithmetic Operators in C Name Operator Example Addition +num1 + num2 Subtraction -initial - spent Multiplication *fathoms * 6 Division /sum / count Modulus %m % n

CMSC 104, Version 8/063L10ArithmeticOps.ppt Division If both operands of a division expression are integers, you will get an integer answer. The fractional portion is thrown away. Examples : 17 / 5 = 3 4 / 3 = 1 35 / 9 = 3

CMSC 104, Version 8/064L10ArithmeticOps.ppt Division (con’t) Division where at least one operand is a floating point number will produce a floating point answer. Examples : 17.0 / 5 = / 3.2 = / 9.1 = What happens? The integer operand is temporarily converted to a floating point, then the division is performed.

CMSC 104, Version 8/065L10ArithmeticOps.ppt Division By Zero Division by zero is mathematically undefined. If you allow division by zero in a program, it will cause a fatal error. Your program will terminate execution and give an error message. Non-fatal errors do not cause program termination, just produce incorrect results.

CMSC 104, Version 8/066L10ArithmeticOps.ppt Modulus The expression m % n yields the integer remainder after m is divided by n. Modulus is an integer operation -- both operands MUST be integers. Examples :17 % 5 = 2 6 % 3 = 0 9 % 2 = 1 5 % 8 = 5

CMSC 104, Version 8/067L10ArithmeticOps.ppt Uses for Modulus Used to determine if an integer value is even or odd 5 % 2 = 1 odd 4 % 2 = 0 even If you take the modulus by 2 of an integer, a result of 1 means the number is odd and a result of 0 means the number is even. The Euclid’s GCD Algorithm (done earlier)

CMSC 104, Version 8/068L10ArithmeticOps.ppt Arithmetic Operators Rules of Operator Precedence Operator(s) Precedence & Associativity ( )Evaluated first. If nested (embedded), innermost first. If on same level, left to right. * / % Evaluated second. If there are several, evaluated left to right. + -Evaluated third. If there are several, evaluated left to right. =Evaluated last, right to left.

CMSC 104, Version 8/069L10ArithmeticOps.ppt Using Parentheses Use parentheses to change the order in which an expression is evaluated. a + b * cWould multiply b * c first, then add a to the result. If you really want the sum of a and b to be multiplied by c, use parentheses to force the evaluation to be done in the order you want. (a + b) * c Also use parentheses to clarify a complex expression.

CMSC 104, Version 8/0610L10ArithmeticOps.ppt Extended Example Given integer variables a, b, c, d, and e, where a = 1, b = 2, c = 3, d = 4, evaluate the following expression: e = b % d / c * b – a e = ( b % d ) / c * b – a e = ( ( b % d ) / c ) * b – a e = ( ( ( b % d ) / c ) * b ) – a e = ( ( ( ( b %d ) / c ) * b ) – a ) e = ( ( ( ( 2 % 4 ) / 3 ) * 2 ) – 1 )

CMSC 104, Version 8/0611L10ArithmeticOps.ppt Extended Example (cont’d) e = ( ( ( ( 2 % 4 ) / 3 ) * 2 ) – 1 ) e = ( ( ( ( 2 ) / 3 ) * 2 ) – 1 ) e = ( ( ( 2 / 3 ) * 2 ) – 1 ) e = ( ( ( 0 ) * 2 ) – 1 ) e = ( ( 0 * 2 ) – 1 ) e = ( ( 0 ) – 1 ) e = ( 0 – 1 ) e = – 1 Note: Always use parenthesis when you have more than two operators!

CMSC 104, Version 8/0612L10ArithmeticOps.ppt Good Programming Practices Always use parenthesis when you have more than two operators!

CMSC 104, Version 8/0613L10ArithmeticOps.ppt Extended Example Given integer variables a, b, c, d, and e, where a = 1, b = 2, c = 3, d = 4, evaluate the following expression: e = b % d / c * b – a e = ( b % d ) / c * b – a e = ( ( b % d ) / c ) * b – a e = ( ( ( b % d ) / c ) * b ) – a e = ( ( ( ( b %d ) / c ) * b ) – a ) e = ( ( ( ( 2 % 4 ) / 3 ) * 2 ) – 1 )

CMSC 104, Version 8/0614L10ArithmeticOps.ppt Another Extended Example Given integer variables a, b, c, d, and e, where a = 1, b = 2, c = 3, d = 4, evaluate the following expression: d = e = 1 + a + b * d % c d = e = 1 + a + ( b * d ) % c d = e = 1 + a + ( ( b * d ) % c ) d = e = ( 1 + a ) + ( ( b * d ) % c ) d = e = ( ( 1 + a ) + ( ( b * d ) % c ) ) d = ( e = ( ( 1 + a ) + ( ( b * d ) % c ) ) ) d = ( e = ( ( ) + ( ( 2 * 4 ) % 3 ) ) )

CMSC 104, Version 8/0615L10ArithmeticOps.ppt Another Extended Example (cont’d) d = ( e = ( ( ) + ( ( 2 * 4 ) % 3 ) ) ) d = ( e = ( ( ) + ( ( 8 ) % 3 ) ) ) d = ( e = ( ( ) + ( 8 % 3 ) ) ) d = ( e = ( ( ) + ( 2 ) ) ) d = ( e = ( ( ) + 2 ) ) d = ( e = ( ( 2 ) + 2 ) ) d = ( e = ( ) ) d = ( e = ( 4 ) ) d = ( e = 4 ) d = 4 /* e is now set to 4 and so is d */

CMSC 104, Version 8/0616L10ArithmeticOps.ppt Practice With Evaluating Expressions Given integer variables a, b, c, d, and e, where a = 1, b = 2, c = 3, d = 4, evaluate the following expressions: a + b - c + d a * b / c 1 + a * b % c a + d % b - c e = b = d + c / b - a

CMSC 104, Version 8/0617L10ArithmeticOps.ppt A Sample Project Let’s write a program that computes and displays the volume and surface area of a box. (I’ll help with prompting the user and displaying the results.) Procedure: o Use the pseudocode that we developed in “Algorithms, Part 3 of 3” o Convert the algorithm to code o Clean up the code (spacing, indentation, commenting)

CMSC 104, Version 8/0618L10ArithmeticOps.ppt The Box - Pseudocode Display “Enter the height: “ Read While ( <= 0 ) Display “The height must be > 0” Display “Enter the height: “ Read End_while

CMSC 104, Version 8/0619L10ArithmeticOps.ppt The Box - Pseudocode (con’t) Display “Enter the width: “ Read While ( <= 0 ) Display “The width must be > 0” Display “Enter the width: “ Read End_while

CMSC 104, Version 8/0620L10ArithmeticOps.ppt The Box - Pseudocode (con’t) Display “Enter the depth: “ Read While ( <= 0 ) Display “The depth must be > 0” Display “Enter the depth: “ Read End_while

CMSC 104, Version 8/0621L10ArithmeticOps.ppt The Box - Pseudocode (con’t) = X X = X = 2 X ( + + )

CMSC 104, Version 8/0622L10ArithmeticOps.ppt The Box - Pseudocode (con’t) Display “Height = “, Display “Width = “, Display “Depth = “, Display “Volume = “, Display “Surface Area = “,

CMSC 104, Version 8/0623L10ArithmeticOps.ppt Good Programming Practice It is best not to take the “big bang” approach to coding. Use an incremental approach by writing your code in incomplete, yet working, pieces. For example, for your projects, o Don’t write the whole program at once. o Just write enough to display the user prompt on the screen. o Get that part working first (compile and run). o Next, write the part that gets the value from the user, and then just print it out.

CMSC 104, Version 8/0624L10ArithmeticOps.ppt Good Programming Practice (con’t) o Get that working (compile and run). o Next, change the code so that you use the value in a calculation and print out the answer. o Get that working (compile and run). o Continue this process until you have the final version. o Get the final version working. Bottom line: Always have a working version of your program!

CMSC 104, Version 8/0625L10ArithmeticOps.ppt Using the Incremental Approach Let’s think about how we could have developed the volume and surface area program incrementally.