Direct Variation What is it and how do I know when I see it?

When we talk about a direct variation, we are talking about a relationship where as x increases, y increases or x decreases, y decreases at a CONSTANT RATE. Direct Variation

Definition: A direct variation involving x and y is a function in which the ratio is a nonzero constant. Another way of writing this is k = k is the constant of variation also known as the slope of the function.

Definition: y varies directly as x means that y = kx where k is the constant of variation. (see any similarities to y = mx + b?) In other words: * the constant of variation (k) in a direct variation is the constant (unchanged) ratio of two variable quantities.

Examples of Direct Variation: Note: X increases, 6, 7, 8 And Y increases. 12, 14, 16 What is the constant of variation of the table above? Since y = kx we can say Therefore: 12/6=k or k = 214/7=k or k = 2 16/8=k or k =2Note k stays constant. y = 2x is the equation! y = kx

Note: X decreases, 10, 5, 3 And Y decreases. 30, 15, 9 What is the constant of variation of the table above? Since y = kx we can say Therefore: 30/10=k or k = 315/5=k or k = 3 9/3=k or k =3Note k stays constant. y = 3x is the equation! Examples of Direct Variation:

Note: X decreases, -4, -16, -40 And Y decreases. -1,-4,-10 What is the constant of variation of the table above? Since y = kx we can say Therefore: -1/-4=k or k = ¼-4/-16=k or k = ¼ -10/-40=k or k = ¼Note k stays constant. y = ¼ x is the equation! Examples of Direct Variation:

What is the constant of variation for the following direct variation? Answer Now ½ 4. ½

Is this a direct variation? If yes, give the constant of variation (k) and the equation. Yes! k = 6/4 or 3/2 k = 12/8 or 3/2 k = 18/12 or 3/2 k = 27/18 or 3/2 Equation? y = 3/2 x

Yes! k = 25/10 or 5/2 K = 15/6 or 5/2 k = 10/4 or 5/2 k = 5/2 Equation? y = 5/2 x Is this a direct variation? If yes, give the constant of variation (k) and the equation.

No! k = 5/15 or 1/3 k = 75/1 or 75 The k values are different! Is this a direct variation? If yes, give the constant of variation (k) and the equation.

Which of the following is a direct variation? 1. A 2. B 3. C 4. D Answer Now

Which is the equation that describes the following table of values? 1. y = -2x 2. y = 2x 3. y = ½ x 4. xy = 200 Answer Now

Using Direct Variation When x is 2 and y is 4, find an equation that shows x and y vary directly. 2 Step Process 1 st Find the constant variation k = or k = 4/2 = 2 k=2 2nd Use y = kx. y = 2x

Using Direct Variation When x is 3 and y is 12, find an equation that shows x and y vary directly. 2 Step Process 1 st Find the constant variation k = y/x or k = 12/3 = 4 k=4 2nd Use y = kx. y = 4x

Using Direct Variation to find unknowns (y = kx) Given that y varies directly with x, and y = -30 when x=- 3, Find y when x = 8. HOW??? 2 step process 1. Find the constant variation k = y/x or k = -30/-3 = 10 k=10 2. Use y = kx. Find the unknown (x). y = 10x so y= 10(8) y= 80 Therefore: x = 8 when y = 80

Using Direct Variation to find unknowns (y = kx) Given that y varies directly with x, and y = 20 when x=4, Find y when x = 10. HOW??? 2 step process 1. Find the constant variation k = y/x or k = 20/4 = 5 k=5 2. Use y = kx. Find the unknown (x). y = 5x so y= 5(10) y= 50 Therefore: x = 10 when y = 50

Using Direct Variation to solve word problems Problem: To make mango salsa, you need 3 mangoes for 2 recipes (2 recipes = 8 serving). Write an equation relating the number of servings y to the number of mangoes x given so that y varies directly with x. How many servings of salsa can you make if you have 5 mangoes? Step One: Find points in table Step Two: Find the constant variation and equation: k = y/x or k = 8/3 y = 8/3 x Step Three: Use the equation to find the unknown. y = 8/3x y = 8/3(5) y = 40/3 y = 13.3

Using Direct Variation to solve word problems Problem: To make mango salsa, you need 3 mangoes for 2 recipes (2 recipes = 8 serving). Write an equation relating the number of servings y to the number of mangoes x given so that y varies directly with x. How many servings of salsa can you make if you have 5 mangoes? Step One: Find points in table Use a proportion to solve. 40=3y 8(5) = 3y 40 = 3y Y = 13.3 Y = 13.3 servings

Using Direct Variation to solve word problems Problem: The length that a spring will stretch S varies directly with the weight w attached to the spring. If a spring stretches 1.4 inches when a 20 pound weight is attached, how far will it stretch when a 10 pound weight is attached? Step One: Find points in table Step Two: Find the constant variation and equation: k = y/x or k = 1.4/20 y = 0.07 x Step Three: Use the equation to find the unknown. y = 0.07x y = 0.07(10) y = 0.7 y = 0. 7inches

Using Direct Variation to solve word problems Problem: The length that a spring will stretch S varies directly with the weight w attached to the spring. If a spring stretches 1.4 inches when a 20 pound weight is attached, how far will it stretch when a 10 pound weight is attached? Step One: Find points in table Use a proportion to solve. 1.4(10) = 20y 14 = 20y y = 0.7 y = 0.7 inches

Direct Variation and its graph y = mx +b, m = slope and b = y-intercept With direction variation the equation is y = kx Note: m = k or the constant and b = 0 therefore the graph will always go through…

the ORIGIN!!!!!

Tell if the following graph is a Direct Variation or not. No Yes- the line passes through the origin. No

Yes- the line passes through the origin No Tell if the following graph is a Direct Variation or not.

Summary An equation is a direct variation if: Its graph is a line that passes through zero OR The equation can be written in the form y = kx