Physics 101: Lecture 9, Pg 1 Physics 101: Lecture 11 Momentum and Impulse l Today’s lecture will cover Textbook Sections Exam II

Physics 101: Lecture 9, Pg 2 Key Ideas l Last Time: Work-Energy   F = m a multiply both sides by d   F d= m a d (note a d = ½  v 2 )   F d= ½ m  v 2   W =  KE Define Work and Kinetic Energy l This Time: Impulse-Momentum   F = m a multiply both sides by  t   F  t= m a  t (note a  t =  v)   F  t= m  v   I =  p Define Impulse and Momentum

Physics 101: Lecture 9, Pg 3 Preflight 1 A magician yanks a tablecloth out from under some dishes. Miraculously, the dishes remain on the table where they were. Briefly explain why the dishes were not given much impulse by the tablecloth. because the time of force was so small, the impulse by the tablecloth was negligible. A magician can not reveal his secrets. due to the smoothness of the tablecloth - little friction present I don't really know... thats why its called MAGIC!

Physics 101: Lecture 9, Pg 4 ACT Two identical balls are dropped from the same height onto the floor. In each case they have velocity v downward just before hitting the floor. In case 1 the ball bounces back up, and in case 2 the ball sticks to the floor without bouncing. In which case is the magnitude of the impulse given to the ball by the floor the biggest? A. Case 1 B. Case 2 C. The same correct Bouncing Ball |I| = |  p| = |mv final – m v initial | = |m( v final -v initial )| = 2 m v Sticky Ball |I| = |  p| = |mv final – m v initial | = |m( 0-v initial )| = m v V i = -5 m/s V f = +5 m/s

Physics 101: Lecture 9, Pg 5 ACT In both cases of the above question, the direction of the impulse given to the ball by the floor is the same. What is this direction? A. Upward B. Downward time correct

Physics 101: Lecture 9, Pg 6 You drop an egg onto 1) the floor 2) a thick piece of foam rubber. In both cases, the egg does not bounce. In which case is the impulse greater? A) Floor B) Foam C) the same In which case is the average force greater A) Floor B) Foam C) the sameACTs I =  P Same change in momentum  p = F  t F =  p/  t Smaller  t = large F

Physics 101: Lecture 9, Pg 7 Pushing Off… Fred (75 kg) and Jane (50 kg) are at rest on skates facing each other. Jane then pushes Fred w/ a constant force F = 45 N for a time  t=3 seconds. Who will be moving fastest at the end of the push? A) FredB) SameC) Jane Fred F = +45 N (positive direct.) I = +45 (3) N-s = 135 N-s  =  p = mv f – mv i  /m = v f - v i v f = 135 N-s / 75 kg = 1.8 m/s Jane F = -45 N Newton’s 3 rd law I = -45 (3) N-s = -135 N-s  =  p = mv f – mv i  /m = v f - v i v f = -135 N-s / 50 kg = -2.7 m/s Note: P fred + P jane = (1.8) 75 + (-2.7) 50 = 0!

Physics 101: Lecture 9, Pg 8 Momentum is Conserved l Momentum is “Conserved” meaning it can not be created nor destroyed  Can be transferred l Total Momentum does not change with time. l This is a BIG deal!

Physics 101: Lecture 9, Pg 9 Impulse and Momentum Summary F ave  t  I = p f - p i =  p l For single object….  F = 0  momentum conserved (  p = 0) l For collection of objects …   F ext = 0  total momentum conserved (  P tot = 0)  F ext = m total a

Physics 101: Lecture 9, Pg 10 Momentum ACT A car w/ mass 1200 kg is driving north at 40 m/s, and turns east driving 30 m/s. What is the magnitude of the car’s change in momentum? A) 0B) 12,000 C) 36,000D) 48,000E) 60,000 P initial = m v initial = (1200 Kg) x 40 m/s = 48,000 kg m/s North P final = m v final = (1200 Kg) x 30 m/s = 36,000 kg m/s East North-South: P final – P initial = (0 – 48000) = -48,000 kg m/s East-West: P final – P initial = ( ) = +36,000 kg m/s Magnitude : Sqrt(P 2 North + P 2 East ) = 60,000 kg m/s 40 m/s 30 m/s

Physics 101: Lecture 9, Pg 11 Preflight 2 & 3 Is it possible for a system of two objects to have zero total momentum while having a non-zero total kinetic energy? 1. YES 2. NO “Two cars Crashing together and both coming to a complete stop.” correct “Momentum is a vector while kinetic energy is a scalar. If two objects of the same mass are moving at the same speed in opposite directions, the total momentum is zero. However, the total kinetic energy is non-zero.” “An EXPLOSION!!!.”

Physics 101: Lecture 9, Pg 12 ACT Movies often show someone firing a gun loaded with blanks. In a blank cartridge the lead bullet is removed and the end of the shell casing is crimped shut to prevent the gunpowder from spilling out. When a gun fires a blank, is the recoil greater than, the same as, or less than when the gun fires a standard bullet? A. greater than B. same as C. less than If there is no bullet then p bullet = 0 so p gun = 0 correct p gun = -p bullet As if ice skater had no one to push…

Physics 101: Lecture 9, Pg 13 Summary  Impulse I = F  t »Gives change in momentum I =  p  Momentum p = mv »Momentum is VECTOR »Momentum is conserved (when  F = 0)  mv initial =  mv final  Chapter 7, problems 1, 5, 7, 9