Descriptive Inorganic Chemistry Chem 241 9-10 M, W, F Bill Vining 232 Physical Sciences Building 436-2698

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Presentation transcript:

Descriptive Inorganic Chemistry Chem M, W, F Bill Vining 232 Physical Sciences Building

Inorganic Chemistry One of the three descriptive chemistries: – Organic Chemistry – Biochemistry – Inorganic Chemistry  Theoretical and Practical Chemistries:  Physical Chemistry  Analytical Chemistry

Inorganic Chemistry: Chemistry for the rest of the elements.

Inorganic Chemistry Transition metal chemistry: – Metal-ligand complexes Main group and metal-based materials science

What we’ll cover: Nuclear chemistry Redox chemistry Descriptive main group chemistry Theoretical and descriptive transition metal chemistry

What we’ll cover: Breadth of topics and you.

First Assignment: Find the best periodic table website. Bring URL and list of why you think it is the best (and any drawbacks). Hand in paper at start of class Friday.

Official Stuff Course Website: Text: Descriptive Inorganic Chemistry, 5 th Ed., Rayner-Canham and Overton Grading: Three exams300 points Homework/In-Class Quizes100 points Project100 points Homework: some OWL Starting Next Week + hand in

First Topic Where do all these elements come from? How are they made? Are they made?

What aspects of this should we explain?

What will our explanations depend on? Thermodynamics: relative stability Kinetics: rate and mechanism

General Decrease in Abundance with Atomic Number

Even > Odd

Peak at Fe

Peak at Pb

Trough at Be

Missing Tc and Pm and Above N = 83

Nuclear equations

Nucleosynthesis of the Elements Hydrogen Burning 1 H + 1 H  2 H + e + + v e­ 2 H + 1 H  3 He +  3 He + 3 He  4 He +2 1 H Why does this happen only in stars? 4 1 H  4 He + 2e + + 2v e

Helium Burning 4 He + 4 He  8 Be 8 Be + 4 He  12 C*  12 C +  3 4 He  12 C +  Is this easier or harder than hydrogen burning?

Carbon Burning, etc. 12 C + 4 He  16 O +  16 O + 4 He  20 Ne +  20 Ne + 4 He  24 Mg +  12 C + 12 C  24 Mg +  12 C + 12 C  23 Na + 1 H 12 C + 12 C  20 Ne + 4 He Go back to initial Questions. Can we answer any?

The  -Process 20 Ne +   16 O + 4 He 20 Ne + 4 He  24 Mg +  2 20 Ne  16 O + 24 Mg +  40 Ca + 4 He  44 Ti* +  44 Ti* + e -  44 Sc* + v + 44 Sc*  44 Ca +  + + v + 44 Ca + 4 He  48 Ti + 

Neutron Capture-Beta Decay