1 Echelon Method Problem 2.2 # 29 Prepared by E. Gretchen Gascon.

Slides:



Advertisements
Similar presentations
Least Squares Equation / Coefficient of Correlation
Advertisements

1 Slope & Equations of a Line Section 1.1 Prepared by E. Gretchen Gascon.
Echelon Method Problem 2.1 # 23 Prepared by E. Gretchen Gascon.
Gauss-Jordan Method. How To complete Problem 2.2 # 57 Produced by E. Gretchen Gascon.
1 Section 1.2 Linear Functions Prepared by E. Gretchen Gascon.
Solving a System with Three Variables and Three Unknowns.
– ALGEBRA I – Unit 1 – Section 2 Consecutive
3.5 Solving systems of equations in 3 variables
7.3B – Solving with Gauss Elimination GOAL: Create Row echelon form and solve with back substitution. Row operations to create Row echelon form – 1.) Switch.
Solving Linear Equations
9.2 Solving Systems of Linear Equations by Addition BobsMathClass.Com Copyright © 2010 All Rights Reserved. 1 Step 1.Write both equations in the form Ax.
3x – 5y = 11 x = 3y + 1 Do Now. Homework Solutions 2)2x – 2y = – 6 y = – 2x 2x – 2(– 2x) = – 6 2x + 4x = – 6 6x = – 6 x = – 1y = – 2x y = – 2(– 1) y =
Dr. Fowler CCM Solving Systems of Equations By Elimination – Easier.
Elimination Day 2. When the two equations don’t have an opposite, what do you have to do? 1.
3.5 – Solving Systems of Equations in Three Variables.
9.5 Multiplication with the Addition- or-Subtraction Method Purpose: To use multiplication on linear equations before you add or subtract. Homework: p.
1.3 The Intersection Point of Lines System of Equation A system of two equations in two variables looks like: – Notice, these are both lines. Linear Systems.
We will use Gauss-Jordan elimination to determine the solution set of this linear system.
Another method for solving systems of equations is elimination
Bell Ringer October 14, 2010 y = 7 – 2x 4x + y = 5 Step 1: Put the equations in Standard Form. 2x + y = 7 4x + y = 5 Step 2: Determine which variable to.
Systems of Equations: Elimination, Part II Unit 7, Lesson 5b.
SOLVING SYSTEMS ALGEBRAICALLY SECTION 3-2. SOLVING BY SUBSTITUTION 1) 3x + 4y = 12 STEP 1 : SOLVE ONE EQUATION FOR ONE OF THE VARIABLES 2) 2x + y = 10.
Warm up Simplify: -(2x + 3) + 4(x + 2) A – 2 – ( 3 + a) Solve: 13m – 22 = 9m -6.
Solving Systems of Equations by Elimination (Addition) Section 3.2, Part II.
Solving by Elimination Example 1: STEP 2: Look for opposite terms. STEP 1: Write both equations in Standard Form to line up like variables. STEP 5: Solve.
Solving by Substitution Method or Elimination (Addition) Method
Solve the following system using the elimination method.
Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination Method Solving Systems of Equations: The Elimination.
Notes – 2/13 Addition Method of solving a System of Equations Also called the Elimination Method.
Elimination Method: Solve the linear system. -8x + 3y=12 8x - 9y=12.
 In this lesson we will go over how to solve a basic matrix equation such as the following: These are matrices, not variables.
5.4 Third Order Determinants and Cramer’s Rule. Third Order Determinants To solve a linear system in three variables, we can use third order determinants.
Solve Systems of Equations Using Elimination Section 6.3.
Elimination Method Day 2 Today’s Objective: I can solve a system using elimination.
Solving Systems by Elimination 5.4 NOTES, DATE ____________.
Solving a System of Equations by Elimination SYSTEMS1.2- I can solve a system of equation by elimination.
Solve Linear Systems by Elimination February 3, 2014 Pages
Objective solve systems of equations using elimination.
3-2: Solving Linear Systems. Solving Linear Systems There are two methods of solving a system of equations algebraically: Elimination Substitution.
The solution will be one of three cases: 1. Exactly one solution, a point (x, y, z) 2. A dependent system with infinitely many solutions 3. No solution.
Elimination Method - Systems. Elimination Method  With the elimination method, you create like terms that add to zero.
8.3 Solving Systems of Equations by ELIMINATION (addition) ESSENTIAL QUESTION: How can you solve a system of equations by adding?
3.5 Solving systems of equations in three variables Main Ideas Solve systems of linear equations in three variables. Solve real-world problems using systems.
Solving Linear Equations in Two Variables
Chapter 12 Section 1.
Solving Systems of Equations
Elimination Method Day 1
Objective I CAN solve systems of equations using elimination with multiplication.
Solve Systems of Equations by Elimination
Solving Linear Equations in Two Variables
3.4 Solving Systems with 3 variables
Honors Algebra II 3.5 Solving Systems with Three Variables.
3-2: Solving Linear Systems
Solve a system of linear equation in two variables
6-3 Solving Systems Using Elimination
Solving Systems Equations in Three Variables
3.5 Solving systems of equations in 3 variables
Do Now 1) t + 3 = – 2 2) 18 – 4v = 42.
4.6 Cramer’s Rule System of 2 Equations System of 3 Equations
Notes Solving a System by Elimination
Solving Systems of Equations
3-2: Solving Linear Systems
Solving systems using substitution
Systems with Three Variables
Solving Systems of Equations
Solve the linear system.
3-2: Solving Linear Systems
Example 2B: Solving Linear Systems by Elimination
3-2: Solving Linear Systems
Step 1: Put the equations in Standard Form. Standard Form: Ax + By = C
Presentation transcript:

1 Echelon Method Problem 2.2 # 29 Prepared by E. Gretchen Gascon

2 Step 1: The problem Notice that this problem has three unknowns, but only two equations. To arrive at a unique solution, there should be the same number of equations as the number of variables. We will start the problem the same way with the regular echelon method.

3 Step 2: Eliminate the y term Use equation 1 and 2 Add the two equations to get a new equation. Remember this equation it will be used later Reorganize the equations so that the y term is first. You don’t have to but doing so, makes the first step easier.

4 The new system of equations This is the new system of equation. Because there was not a third equation, it was not possible to create a second equation from which the y was eliminated.

5 Step 7: Solve for y and x in terms of z Assume that z is the parameter. The variable that can be any value. Solve for x in terms of z Using the value for x, solve for y in terms of z

6 Comments Was there anything about this PowerPoint presentation that you would like further explained? Post comments or questions to the Main Forum.

7 Answer: