-Nice neat notes that are legible and use indentations when appropriate.

-Nice neat notes that are legible and use indentations when appropriate. -Example of indent.

-Nice neat notes that are legible and use indentations when appropriate. -Example of indent. -Skip a line between topics

-Nice neat notes that are legible and use indentations when appropriate. -Example of indent. -Skip a line between topics -Make visuals clear and well drawn.

-Nice neat notes that are legible and use indentations when appropriate. -Example of indent. -Skip a line between topics -Make visuals clear and well drawn. Please label. Effort Arm Resistance Arm

Speed: A measure of motion, = distance divided by time. D/T Speed: A measure of motion, = distance divided by time. D/T Copyright © 2010 Ryan P. Murphy

Speed: A measure of motion, = distance divided by time. D/T Speed: A measure of motion, = distance divided by time. D/T Copyright © 2010 Ryan P. Murphy Speed is the rate of motion, or the rate of change of position.

Speed: A measure of motion, = distance divided by time. D/T Speed: A measure of motion, = distance divided by time. D/T Copyright © 2010 Ryan P. Murphy Speed is the rate of motion, or the rate of change of position. Can only be zero or positive.

Distance = Speed ● Time

How far did Joe walk if he walked a steady 4 km/h for three straight hours?

Distance = Speed ● Time

How far did Joe walk if he walked a steady 4 km/h for three straight hours? Distance = Speed ● Time Distance = 4 km/h ● 3 h

How far did Joe walk if he walked a steady 4 km/h for three straight hours? Distance = Speed ● Time Distance = 4 km/h ● 3 h Distance =

How far did Joe walk if he walked a steady 4 km/h for three straight hours? Distance = Speed ● Time Distance = 4 km/h ● 3 h Distance = 12 km

Distance Speed = Time

What is Joes speed if he walked a steady 5 km in one hour? Rate / Speed R =

What is Joes speed if he walked a steady 5 km in one hour? Rate / Speed R = 5 km 1 hour or 5 km/hr

What is Joes speed if he walked 5 km in one hour? Rate / Speed R = 5 km 1 hour or 5 km/hr

Juan travels 300km in 6hrs. Find his average speed in km/h.

Speed = Distance / Time

Juan travels 300km in 6hrs. Find his average speed in km/h. Speed = Distance / Time 300km Speed = = 50 km/h 6h

Juan travels 300km in 6hrs. Find his average speed in km/h. Speed = Distance / Time 300km 50km Speed = = h h

Distance Time = Speed

Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?

Time = Distance / Speed

Marlene drove 500 km at an average speed of 50 km/h? How long did she drive? Time = Distance / Speed 500km Time = = _____h 50km/h

Marlene drove 500 km at an average speed of 50 km/h? How long did she drive? Time = Distance / Speed 500km Time = = _____h 50km/h

Marlene drove 500 km at an average speed of 50 km/h? How long did she drive? Time = Distance / Speed 500km Time = = 10h 50km/h

Velocity = (distance / time) and direction. Velocity = (distance / time) and direction. Copyright © 2010 Ryan P. Murphy

Velocity = –S is replaced with V because velocity is speed and direction. Copyright © 2010 Ryan P. Murphy

What’s Joes velocity if he walked 4 kilometers East in one hour? 4 km East 4 km V = = 4 km/hr/east 1 hour Copyright © 2010 Ryan P. Murphy

What’s Joes velocity if he walked 4 kilometers East in one hour? 4 km East 4km km V = = 4 hr/east 1 hour Copyright © 2010 Ryan P. Murphy 4 km hr East

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 4m 8m

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 50m 60m 30m 100m

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 50m 60m 30m 100m

Velocity deals with displacement. –Displacement measures where you end up relative to where you started. Copyright © 2010 Ryan P. Murphy 50m 60m 30m 100m m 80m

Find the displacement. Copyright © 2010 Ryan P. Murphy

Find the displacement. Copyright © 2010 Ryan P. Murphy

Find the displacement. Copyright © 2010 Ryan P. Murphy 50m 10m 20m 100m

The speed of the car is 80 km / hr. Copyright © 2010 Ryan P. Murphy

The velocity of the car is 80 km / hr / West. Copyright © 2010 Ryan P. Murphy

The velocity of the plane is 300 km / hr / West. Copyright © 2010 Ryan P. Murphy

The velocity of the plane is 300 km / hr / West. Copyright © 2010 Ryan P. Murphy

The velocity of the plane is 300 km / hr / West. Copyright © 2010 Ryan P. Murphy

The speed of the plane is 300 km / hr

Copyright © 2010 Ryan P. Murphy The speed of the plane is 300 km / hr

Copyright © 2010 Ryan P. Murphy The speed of the plane is 300 km / hr Speed and Velocity Calculations and problems. Learn more at…. gation/MathScienceIntegation-827.htm gation/MathScienceIntegation-827.htm

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 600 km / 2.5 h

It took Lightning McGreen 2.5 hours to travel 600 kilometers. –How fast was he going in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 600 km / 2.5 h Speed = 240 km/h

Answer: 240 km/h –Speed is distance over time. Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Velocity = Distance / Time

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Velocity = Distance / Time Velocity = 165km / 4 h

It took Ms. Rally 4 hours to travel 165 kilometers due North. –What was the velocity of her car in Kilometers an hour? Copyright © 2010 Ryan P. Murphy Velocity = Distance / Time Velocity = 165km / 4 h Velocity = km/h/North

Answer: km / h / North –Velocity is distance over time and direction. Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 340km / 3 h

What is the speed if the distance was 340 km and the time was 3 hours? –Was Jater speeding? Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 340km / 3 h Speed = 113km/h

340 km / 3 hours = 113km/h –Jater was speeding. Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy Distance = Speed ● Time

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy Distance = Speed ● Time Distance = 60km/h ● 4 h

How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours? Copyright © 2010 Ryan P. Murphy Distance = Speed ● Time Distance = 60km/h ● 4 h

In this case, we just multiply the distance traveled by the time. 60 km/h times 4 hours. Copyright © 2010 Ryan P. Murphy

60 km times 4 hours = 240 km –Check your work, 240/4 should be 60. Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy Speed = Distance / Time

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 400m / 43s

What is the speed if a runner runs a distance of 400 meters in 43 seconds. Copyright © 2010 Ryan P. Murphy Speed = Distance / Time Speed = 400m / 43s Speed = 9.30 m/s

400m / 43s = 9.30 m/s Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

Activity! Looking for the Violators.

Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent.

Activity! Looking for the Violators. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent. Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent. We also must try to conceal ourselves at all time. We do not want anyone to see us / slow down. We also must try to conceal ourselves at all time. We do not want anyone to see us / slow down.

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/sec.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/sec.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the village have a speeding problem?

Activity! Optional –Teacher measures out 300 feet along road and puts a cone at the start and finish a short distance from the roads edge. –From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone. –Speed = Distance (300 ft) divided by time (ft/s.) –Multiply by.681 (ft/sec to mph conversion) = mph –Over 30 mph is speeding in the village. –Create list of all the speeds and then average. –Does the town have a speeding problem?

Note: This is nice to know. Average vs. Instantaneous Velocity –Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed).

Note: This is nice to know. Average vs. Instantaneous Velocity –Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed). Instantaneous Velocity Definition: The velocity of an object at any given instant (especially that of an accelerating object); the limit of the change in position per unit time as the unit of time approaches zero; expressed mathematically

Note: This is nice to know. Average vs. Instantaneous Velocity –Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed). Instantaneous Velocity Definition: The velocity of an object at any given instant (especially that of an accelerating object); the limit of the change in position per unit time as the unit of time approaches zero; expressed mathematically

Average: The result obtained by adding several quantities together and then dividing this total by the number of quantities; the mean

Average: The result obtained by adding several quantities together and then dividing this total by the number of quantities; the mean.

Acceleration = The rate of change in velocity. (m/s) Acceleration = The rate of change in velocity. (m/s) Copyright © 2010 Ryan P. Murphy

Or… a = (v 2 − v 1 )/(t 2 − t 1 )

Acceleration is measured by taking the change in velocity of an object divided by the time to change that velocity:

Video Link! Speed, Velocity, Acceleration –Be proactive, sketch problems in journal as completed in video. – 8-ihCA9Ehttp:// 8-ihCA9E

Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

Acceleration = The final velocity – the starting velocity, divided by time. Acceleration = The final velocity – the starting velocity, divided by time. Copyright © 2010 Ryan P. Murphy

Video Link (Optional) 100 meter final London Summer Games (Note Bolt’s acceleration) – (Skip ahead to 4:15 for race)

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy 200 m/s80 m/s 4 s

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy 120 m/s 4 s

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = a = 120 m/s / 4 s = Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = a = 120 m/s / 4 s = 30 m/s Copyright © 2010 Ryan P. Murphy

Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. –What’s the rat mobiles acceleration? The formula for acceleration is: a = (Final velocity – starting velocity) / time. a = 200m/s -80m/s / 4 s = a = 120 m/s / 4 s = 30 m/s North Copyright © 2010 Ryan P. Murphy

A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t

A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t 0 m/s 10 m/s 20 s

A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t 10 m/s 20 s

A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. –What is its acceleration / deceleration? Copyright © 2010 Ryan P. Murphy a = (v 2 − v 1 ) t 10 m/s 20 s -.5 m/s

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. –What was the acceleration? Copyright © 2010 Ryan P. Murphy

A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. –What was the acceleration? Copyright © 2010 Ryan P. Murphy

A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. –What was the acceleration? Copyright © 2010 Ryan P. Murphy

The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration. Copyright © 2010 Ryan P. Murphy 6 m/s – 2m/s 3s – 0s

The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration. Copyright © 2010 Ryan P. Murphy 4 m/s 3s

The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration. Copyright © 2010 Ryan P. Murphy 4 m/s 3s = m/s South

Copyright © 2010 Ryan P. Murphy Acceleration: Learn more at…

Video Link! Khan Academy. Acceleration. (Optional) complete problems as he does. –Be active in your learning not passive. – mechanics/v/accelerationhttp:// mechanics/v/acceleration Copyright © 2010 Ryan P. Murphy

Deceleration: To slow velocity. Deceleration: To slow velocity. - Copyright © 2010 Ryan P. Murphy

Deceleration: To slow velocity. Deceleration: To slow velocity. Formula is the same as acceleration but will be a negative value. Formula is the same as acceleration but will be a negative value. Copyright © 2010 Ryan P. Murphy

Deceleration: To slow velocity. Deceleration: To slow velocity. Formula is the same as acceleration but will be a negative value. Formula is the same as acceleration but will be a negative value. Copyright © 2010 Ryan P. Murphy Note: There is no "deceleration", only negative acceleration

The formula is the same, but the value will be a negative. –Deceleration = (final velocity – starting velocity) divided by time. Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

Lightning McGreen was traveling 200 m/s West when he slowed to 50 m/s in 10 seconds. –What was his deceleration? Copyright © 2010 Ryan P. Murphy

Lightning McGreen was traveling 200 m/s West when he slowed to 50 m/s in 10 seconds. –What was his deceleration? Copyright © 2010 Ryan P. Murphy

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 50 m/s m/s 10s – 0s

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds. Copyright © 2010 Ryan P. Murphy 150 m/s 10s Deceleration = -15 m/s West

Momentum: A measure of the motion of a body equal to the product of its mass and velocity. Momentum: A measure of the motion of a body equal to the product of its mass and velocity. Copyright © 2010 Ryan P. Murphy

Momentum = Mass * Velocity. Momentum = Mass * Velocity. Copyright © 2010 Ryan P. Murphy p = m v

Momentum = Mass * Velocity. Momentum = Mass * Velocity. Copyright © 2010 Ryan P. Murphy p = m v Momentum Mass kg Velocity m/s

Momentum = ? Copyright © 2010 Ryan P. Murphy

Video Link! Momentum (Optional) – Copyright © 2010 Ryan P. Murphy

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum =

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum = 60,000 kg/m/s West

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum = 60,000 kg/m/s West

What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 3000 kg 20/m/s/ West Momentum = 60,000 kg/m/s West Momentum = 6 x 10 4 kg/m/s West

Momentum = 60,000 kg/m/s Copyright © 2010 Ryan P. Murphy Momentum. Learn more at… entum/u4l1a.cfm entum/u4l1a.cfm

Forces in Motion, Speed, Velocity, Acceleration and more available sheet.

Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy

Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v

Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North

Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North Momentum = 20,000 kg/m/s North

Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North Momentum = 20,000 kg/m/s North

Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum? Copyright © 2010 Ryan P. Murphy p = m v Momentum = 1000 kg 20/m/s/ North Momentum = 20,000 kg/m/s North Momentum = 2 x 10 4 kg/m/s North

Momentum for car = 20,000 kg/m/s North

Copyright © 2010 Ryan P. Murphy

Momentum for car = 20,000 kg/m/s North –The truck has more momentum so the car gets pushed back. Copyright © 2010 Ryan P. Murphy

Momentum for car = 20,000 kg/m/s North –The truck has more momentum so the car gets pushed back. Copyright © 2010 Ryan P. Murphy