C.1.3b - Area & Definite Integrals: An Algebraic Perspective Calculus - Santowski 1/7/2016Calculus - Santowski 1
Fast Five 1/7/2016Calculus - Santowski2 (1) 0.25[f(1) + f(1.25) + f(1.5) + f(1.75)] if f(x) = x 2 + x - 1 (2) Illustrate Q1 with a diagram, showing all relevant details
(A) Review 1/7/2016Calculus - Santowski3 We will continue to move onto a second type of integral the definite integral Last lesson, we estimated the area under a curve by constructing/drawing rectangles under the curve Today, we will focus on doing the same process, but from an algebraic perspective, using summations
(B) Summations, ∑ 1/7/2016Calculus - Santowski4 A series is the sum of a sequence (where a sequence is simply a list of numbers) Ex: the sequence 2,4,6,8,10,12, …..2n has a an associated sum, written as: The sum … + 2n can also be written as 2( … + n) or:
(C) Working with Summations 1/7/2016Calculus - Santowski5 Ex 1. You are given the following series: List the first 7 terms of each series
(C) Working with Summations 1/7/2016Calculus - Santowski6 Ex 1I. You are given the following series: Evaluate each series
(C) Working with Summations 1/7/2016Calculus - Santowski7 Ex 1. You are given the following series: List the first 10 terms of each series
(C) Working with Summations 1/7/2016Calculus - Santowski8 Ex 1. You are given the following series: Evaluate each series
(B) Summations, ∑ 1/7/2016Calculus - Santowski9 Here are “sum” important summation formulas: (I) sum of the natural numbers ( ….n) (II) sum of squares ( ….+n 2 ) (III) sum of cubes ( ….n 3 )
(E) Working With Summations - GDC Now, to save all the tedious algebra (YEAHH!!!), let’s use the TI-89 to do sums First, let’s confirm our summation formulas for i, i 2 & i 3 and get acquainted with the required syntax 1/7/2016Calculus - Santowski10
(E) Working With Summations - GDC So let’s revisit our previous example of And our 4th example of 1/7/2016Calculus - Santowski11
(F) Applying Summations 1/7/2016Calculus - Santowski12 So what do we need summations for? Let’s connect this algebra skill to determining the area under curves ==> after all, we are simply summing areas of individual rectangles to estimate an area under a curve
PART 2 - The Area Problem 1/7/2016Calculus - Santowski13 Let’s work with a simple quadratic function, f(x) = x and use a specific interval of [0,3] Now we wish to estimate the area under this curve
(A) The Area Problem – Rectangular Approximation Method (RAM) 1/7/2016Calculus - Santowski14 To estimate the area under the curve, we will divide the are into simple rectangles as we can easily find the area of rectangles A = l × w Each rectangle will have a width of x which we calculate as (b – a)/n where b represents the higher bound on the area (i.e. x = 3) and a represents the lower bound on the area (i.e. x = 0) and n represents the number of rectangles we want to construct The height of each rectangle is then simply calculated using the function equation Then the total area (as an estimate) is determined as we sum the areas of the numerous rectangles we have created under the curve A T = A 1 + A 2 + A 3 + ….. + A n We can visualize the process on the next slide
(A) The Area Problem – Rectangular Approximation Method (RRAM) 1/7/2016Calculus - Santowski15 We have chosen to draw 6 rectangles on the interval [0,3] A 1 = ½ × f(½) = A 2 = ½ × f(1) = 1.5 A 3 = ½ × f(1½) = A 4 = ½ × f(2) = 3 A 5 = ½ × f(2½) = A 6 = ½ × f(3) = 5.5 A T = square units So our estimate is which is obviously an overestimate
(B) Sums & Rectangular Approximation Method (RRAM) So let’s apply our summation formulas: Each rectangle’s area is f(x i ) x where f(x) = x x = 0.5 and x i = 0 + xi Therefore the area of 6 rectangles is given by 1/7/2016Calculus - Santowski16
(C) The Area Problem – Rectangular Approximation Method (LRAM) 1/7/2016Calculus - Santowski17 In our previous slide, we used 6 rectangles which were constructed using a “right end point” (realize that both the use of 6 rectangles and the right end point are arbitrary!) in an increasing function like f(x) = x this creates an over-estimate of the area under the curve So let’s change from the right end point to the left end point and see what happens
(C) The Area Problem – Rectangular Approximation Method (LRAM) 1/7/2016Calculus - Santowski18 We have chosen to draw 6 rectangles on the interval [0,3] A 1 = ½ × f(0) = 1 A 2 = ½ × f(½) = A 3 = ½ × f(1) = 1.5 A 4 = ½ × f(1½) = A 5 = ½ × f(2) = 3 A 6 = ½ × f(2½) = A T = square units So our estimate is which is obviously an under-estimate
(D) Sums & Rectangular Approximation Method (LRAM) So let’s apply our summation formulas: Each rectangle’s area is f(x i ) x where f(x) = x x = 0.5 and x i = 0 + xi Therefore the area of 6 rectangles is given by: (Notice change in i???) 1/7/2016Calculus - Santowski19
(E) The Area Problem – Rectangular Approximation Method (MRAM) 1/7/2016Calculus - Santowski20 So our “left end point” method (called a left hand Riemann sum or LRAM) gives us an underestimate (in this example) Our “right end point” method (called a right handed Riemann sum or RRAM) gives us an overestimate (in this example) We can adjust our strategy in a variety of ways one is by adjusting the “end point” why not simply use a “midpoint” in each interval and get a mix of over- and under-estimates? see next slide
(E) The Area Problem – Rectangular Approximation Method (MRAM) 1/7/2016Calculus - Santowski21 We have chosen to draw 6 rectangles on the interval [0,3] A 1 = ½ × f(¼) = A 2 = ½ × f (¾) = A 3 = ½ × f(1¼) = A 4 = ½ × f(1¾) = A 5 = ½ × f(2¼) = A 6 = ½ × f(2¾) = A T = square units which is a more accurate estimate (15 is the exact answer)
(F) Sums & Rectangular Approximation Method (MRAM) So let’s apply our summation formulas: Each rectangle’s area is f(x i ) x where f(x) = x x = 0.5 and x i = xi Therefore the area of 6 rectangles is given by: (Notice change in i??? and the x i expression???) 1/7/2016Calculus - Santowski22
(G) The Area Problem – Expanding our Example 1/7/2016Calculus - Santowski23 Now back to our left and right Riemann sums and our original example how can we increase the accuracy of our estimate? We simply increase the number of rectangles that we construct under the curve Initially we chose 6, now let’s choose a few more … say 12, 60, and 300 …. But first, we need to generalize our specific formula!
(G) The Area Problem – Expanding our Example 1/7/2016Calculus - Santowski24 So we have Now, x = (b-a)/n = (3 - 0)/n = 3/n And f(x i ) = f(a + xi) = f(0 + 3i/n) = f(3i/n) So, we have to work with the generalized formula
(G) The Area Problem – Expanding our Example Does this generalized formula work? Well, test it with n = 6 as before! 1/7/2016Calculus - Santowski25
(G) The Area Problem – Expanding our Example (RRAM) # of rectanglesArea estimate /7/2016Calculus - Santowski26
(G) The Area Problem – Expanding our Example # of rectanglesArea estimate /7/2016Calculus - Santowski27
(G) The Area Problem – Expanding our Example (LRAM) # of rectanglesArea estimate /7/2016Calculus - Santowski28
(G) The Area Problem – Expanding our Example (LRAM) # of rectanglesArea estimate /7/2016Calculus - Santowski29
(H) The Area Problem - Conclusion So our exact area seems to be “sandwiched” between and !!! So, if increasing the number of rectangles increases the accuracy, the question that needs to be asked is ….. how many rectangles should be used??? The answer is ….. why not use an infinite number of rectangles!! so now we are back into LIMITS!! So, the exact area between the curve and the x-axis can be determined by evaluating the following limit: 1/7/2016Calculus - Santowski30
(H) The Area Problem - Conclusion So let’s verify the example using the GDC and limits: 1/7/2016Calculus - Santowski31
(I) The Area Problem – Further Examples 1/7/2016Calculus - Santowski32 (i) Determine the area between the curve f(x) = x 3 – 5x 2 + 6x + 5 and the x-axis on [0,4] if we (a) construct 20 rectangles or (b) if we want the exact area (ii) Determine the exact area between the curve f(x) = x 2 – 4 and the x-axis on [0,2] if we (a) construct 30 rectangles or (b) if we want the exact area (iii) Determine the exact area between the curve f(x) = x 2 – 2 and the x-axis on [0,2] if we (a) construct 10 rectangles or (b) if we want the exact area
(J) Homework 1/7/2016Calculus - Santowski33 Homework to reinforce these concepts from this second part of our lesson: Handout, Stewart, Calculus - A First Course, 1989, Exercise 10.4, p474-5, Q3,4,6a
Internet Links 1/7/2016Calculus - Santowski34 Calculus I (Math 2413) - Integrals - Area Problem from Paul Dawkins Calculus I (Math 2413) - Integrals - Area Problem from Paul Dawkins Integration Concepts from Visual Calculus Integration Concepts from Visual Calculus Areas and Riemann Sums from P.K. Ving - Calculus I - Problems and Solutions Areas and Riemann Sums from P.K. Ving - Calculus I - Problems and Solutions