SECTION 2-6 Algebraic Proofs JIM SMITH JCHS. Properties we’ll be needing REFLEXIVE -- a=a SYMMETRIC -- if x=2 then 2=x TRANSITIVE -- if a=b and b=c then.

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Presentation transcript:

SECTION 2-6 Algebraic Proofs JIM SMITH JCHS

Properties we’ll be needing REFLEXIVE -- a=a SYMMETRIC -- if x=2 then 2=x TRANSITIVE -- if a=b and b=c then a=c SUBSTITUTION -- If a=b then a may be used in any equation instead of b

DISTRIBUTIVE -- a(b+c) = ab+ac ADD and SUBTRACT -- if a=b then a+c=b+c and a-c=b-c MULT and DIVIDE – if a=b then ac=bc and a/c = b/c

2 COLUMN PROOFS Statements Reasons

In an algebraic proof, you must show all steps used to solve the equation. Each individual step you use is a statement in the proof. You then give each statement a reason.

SHOW ME - THEN DO IT WHEN WE ADD, SUBTRACT, MULT, OR DIV BOTH SIDES OF THE EQUATION, SHOW ME WHAT YOU ARE GOING TO DO FIRST THE NEXT STEP IS THE DO IT STEP

Given: 2x+5=17 Prove x=6 Start by stating the given. The reason will be GIVEN Statement Reason 1) 2x + 5 = 17 1) Given

Given: 2x+5=17 Prove x=6 Statement Reason 1) 2x + 5 = 17 1) Given 2) 2x + 5 – 5 = ) Subtraction Property

Given: 2x+5=17 Prove x=6 Statement Reason 1) 2x + 5 = 17 1) Given 2) 2x + 5 – 5 = ) Subtraction Property 3) 2x = 12 3) Substitution

Given: 2x+5=17 Prove x=6 Statement Reason 1) 2x + 5 = 17 1) Given 2) 2x + 5 – 5 = ) Subtraction Property 3) 2x = 12 3) Substitution 4) 2x / 2 = 12 / 24) Division Property

Given: 2x+5=17 Prove x=6 Statement Reason 1) 2x + 5 = 17 1) Given 2) 2x + 5 – 5 = ) Subtraction Property 3) 2x = 12 3) Substitution 4) 2x / 2 = 12 / 24) Division Property 5) X = 65) Substitution

Remember !! The SHOW ME steps will be Add, Sub, Mult, or Div or Distributive Properties The DO IT steps will be Substitution