Stoichiometry Practice Problem Nick Maskrey. Problem If 5.26 g of Lithium Sulfate react with Sodium Phosphate complete the stoichiometry. If 5.26 g of.

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Presentation transcript:

Stoichiometry Practice Problem Nick Maskrey

Problem If 5.26 g of Lithium Sulfate react with Sodium Phosphate complete the stoichiometry. If 5.26 g of Lithium Sulfate react with Sodium Phosphate complete the stoichiometry.

Complete and Balance the Equation 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 )

Split Each Chemical Into Separate Columns 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 )

Write the given measurement into the correct column 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g.

Convert the given into moles 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles

Get moles for all other columns by putting the moles of the given times (x) a fraction in each 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles.0478 x /

The numerator is the coefficient of the column 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles.0478 x 2/.0478 x 3/

The denominator is the coefficient of the given 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles.0478 x 2/ x 3/3

Do all of the math to get the moles 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles.0478 x 2/ moles.0478 x 2/ moles.0478 x 3/ moles

Convert All to Grams 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles.0478 x 2/ moles.0319 m x g 1 1 mole 3(22.989) (15.994) g 5.23 g.0478 x 2/ moles.0319 m x g 1 1 mole 3(6.941) ( ) g 3.69 g.0478 x 3/ moles.0478m x g 1 1 mole 2(22.989) ( ) g 6.79 g

Verify the law of conservation of mass 3Li 2 (SO4) + 2Na 3 (PO 4 ) ---> 2Li 3 (PO 4 ) + 3Na 2 (SO 4 ) 5.26 g. 5.26g x 1 mole g 2(6.941) ( ) g.0478 moles 5.26g g 10.49g.0478 x 2/ moles.0319 m x g 1 1 mole 3(22.989) (15.994) g 5.23 g.0478 x 2/ moles.0319 m x g 1 1 mole 3(6.941) ( ) g 3.69 g 3.69g g 10.48g.0478 x 3/ moles.0478m x g 1 1 mole 2(22.989) ( ) g 6.79 g

Answer The reactant mass adds up to g and the products mass adds up to g. The third significant digit in each is 4 and within two of each other so the problem is correct. The reactant mass adds up to g and the products mass adds up to g. The third significant digit in each is 4 and within two of each other so the problem is correct.