Temperature Scales _________ scales are based on the boiling point which is ____ & freezing point of ___. Fahrenheit 212°32° __________________ scales.

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Presentation transcript:

Temperature Scales _________ scales are based on the boiling point which is ____ & freezing point of ___. Fahrenheit 212°32° __________________ scales are based on the boiling point which is ___, and freezing point of __. Celsius or centigrade 100° 0° ______scale is based on _______ ____ which is when an object has no ____ and the mole- cules stop ______ : ___________________ Kelvin absolute zero heat moving 0°K  -273°C  -459°F

Converting Temperatures Celsius to Fahrenheit : F = 9595 C + 32 Fahrenheit to Celsius, solve this equation for C. F = 9595 C + 32 F - 32 = 5959 C = C (F – 32) (F – 32) = C 5959

1. Consider the formula A = p + pr, which gives the amount A (in dollars) after one year in a bank account that started with p dollars and which has an annual yield of r. a. Solve this formula for p. b. Solve this formula for r. A = p + pr A = p (1 + r) A = p + pr -p -p A – p = pr (1 + r) A = p 1 + r p A – p = r p

2. Solve C = 2πr for the variable r. C is the circumference of a circle with radius r. C = 2πr 2π C = r 2π 3. A formula for the area of a sphere is A = 4πr². Solve the formula for r. Explain what you do in each step. A = 4πr² 4π A = r² 4π √ √ A = r 4π √

4. If a coin is tossed and H heads and T tails appear, the relative frequency r of heads is expressed by the formula r = H H + T a. Solve this formula for T. Hr + Tr = H r1r1 H H + T = Putting r over 1 creates a _________ which can be solved by _____________. r H + T -Hr Tr = H - Hr r T = H - Hr r proportion cross products = H ()

5. Use a graphing calculator to graph -7x + 3y = 18. What equation would you need to enter into the calculator? Graphing calculators ____ have the equation __________. -7x + 3y = 18 7x 3y = 7x + 18 Use the window: -10 < x < 10 & -10 < y < 10 must solved for y y = 7x

y = 7x x x y

P = 2 l + 2 w C = 2πr P = 2t + 2πr -2t P – 2t = 2πr 2π 2π P – 2t = r 2π 400 – 2(100) = r 2(3.14) 200 = r … = r The radius is m. P – 2t = r 2π 400 – 2(115) = r 2(3.14) 170 = r … = r The radius is m. 6.