Higher Physics Checklist To Date 1.Errors booklet questions 1 - 6 in problem jotter (blue) 2.“Adding Vectors” Tutorial 1 in problem jotter. (This tutorial.

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Higher Physics Checklist To Date 1.Errors booklet questions in problem jotter (blue) 2.“Adding Vectors” Tutorial 1 in problem jotter. (This tutorial can be found in the homework booklet and a pdf file of the answers is also attached here) 3.Unit 1 Problems on Adding Vectors, in problem jotter. 4.HOMEWORK 1 (1995 Past Paper Q1 handout) - should be done in RED HW jotter and submitted for marking. 5.Unit 1 Problems on Resolving Vectors, in problem jotter. 6.“Resolving Vectors” Tutorial 2 (Q.1 & 2) in problem jotter. (This tutorial can be found in the homework booklet and a pdf file of the answers is also attached here)

Resolving Vectors (recap) Components of a Vector Any single vector can be split into 2 vectors at right angles to each other. Eg)

Resolving Vectors Components of a Vector Any single vector can be split into 2 vectors at right angles to each other. Eg)

Resolving Vectors Components of a Vector Any single vector can be split into 2 vectors at right angles to each other. Eg)

Objects on a Slope If an object accelerates in some direction, then the force making it accelerate must be in the same direction. For example, a mass (m) on a frictionless slope which makes an angle, , with the horizontal …  m NOTES p.6

 m The force acting on the mass is “gravity” which is the downwards “weight” of the mass … W = mg. W = weight in Newtons (N) m = mass in kg g = gravitational field strength in N/kg) W = mg

`  m BUT the force affecting the motion of the mass on the slope is the DOWNSLOPE COMPONENT OF WEIGHT. W = mg  mg (perpendicular component) So … Downslope component of weight = opp = hyp sin  = mg sin  (perpendicular comp. = mg cos  )

  2kg Example A 2kg mass is released on a slope which makes a 30 o angle with the ground. A frictional force of 4N acts upslope. Calculate the acceleration of the mass. mg sin  4N

  2kg mg sin  4N 1 st downslope weight = mg sin  = 2 x 9.8 x sin 30 = 9.8N 2 nd unbalanced force = F R = 9.8N – 4N = 5.8N, downslope 3 rd F u = 5.8N, downslope m = 2 kg a = ? a= F u / m = 5.8 / 2 = 2.9 m/s 2, downslope

So far, the following “Vectors” questions should be completed Tutorial 1 (all) Tutorial 2 (all) Problems 14 – 22 (addition of vectors) Problems 23 – 26 (resolving vectors) + Homework 1995 Past Paper Q1

Tutorial 1 1.a) 9.9N, 4.95 ms a) 4.47ms 333 o b) 4ms 030 o 4.a) b) 20.5ms 73 o from the horizontal Tutorial 2 1a) H – 18.8 ms -1, V – 6.8 ms -1 c) H – 17.7 ms -1, V – 17.7 ms -1 e) H – 0 ms -1, V – 30 ms a) 346N b) 230N c) 11N d) 7.9N e) 3.46N f) 13.8N 3.a)(i) 0.02ms -2 ii) 1.35ms -2 iii) 2.14ms -2 iv) 1.54ms -2 v) 5.05ms -2 b) 19.9 o Problems 14 – 22 (addition of vectors) Problems 23 – 26 (resolving vectors) Tutorial 2 - see HW booklet Tutorial 1 see HW booklet