5.4 Warm Up Warm Up Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Use Medians and Altitudes.

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Presentation transcript:

5.4 Warm Up Warm Up Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Use Medians and Altitudes

5.4 Warm-Up 1. For A(–4, 8) and B(5, 8), find the midpoint of AB. 2. For A(–3, 2) and B(4, –1), find the length of AB. ANSWER 1 2, 8 ANSWER 58

5.4 Warm-Up ANSWER For A(0, 4) and C(18, 4), find the length of AB, where B is a point the distance from A to C. 2 3

5.4 Example 1 SOLUTION SQ = 2 3 SW Concurrency of Medians of a Triangle Theorem 8 =8 = 2 3 SW Substitute 8 for SQ. 12 = SW Multiply each side by the reciprocal,. 3 2 Then QW = SW – SQ = 12 – 8 =4. So, QW = 4 and SW = 12. In RST, Q is the centroid and SQ = 8. Find QW and SW.

5.4 Example 2 SOLUTION Sketch FGH. Then use the Midpoint Formula to find the midpoint K of FH and sketch median GK. The centroid is two thirds of the distance from each vertex to the midpoint of the opposite side. K( ) = 2 + 6, K(4, 3)

5.4 Example 2 The distance from vertex G(4, 9) to K(4, 3) is 9 – 3 = 6 units. So, the centroid is (6) = 4 units down from G on GK. 2 3 The coordinates of the centroid P are (4, 9 – 4), or (4, 5). The correct answer is B.

5.4 Guided Practice There are three paths through a triangular park. Each path goes from the midpoint of one edge to the opposite corner. The paths meet at point P. 1. If SC = 2100 feet, find PS and PC. 700 ft, 1400 ftANSWER 2. If BT = 1000 feet, find TC and BC ft, 2000 ftANSWER 3. If PT = 800 feet, find PA and TA ft, 2400 ftANSWER

5.4 Example 3 Find the orthocenter P in an acute, a right, and an obtuse triangle. SOLUTION Acute triangle P is inside triangle. Right triangle P is on triangle. Obtuse triangle P is outside triangle.

5.4 Example 4 Prove that the median to the base of an isosceles triangle is an altitude. SOLUTION GIVEN: ABC is isosceles, with base AC. BD is the median to base AC. PROVE: BD is an altitude of ABC.

5.4 Example 4 Proof: Legs AB and BC of isosceles ABC are congruent. CD AD because BD is the median to AC. Also, BD BD. Therefore, ABD CBD by the SSS Congruence Postulate.  ADB   CDB because corresponding parts of  s are . Also,  ADB and  CDB are a linear pair. BD and AC intersect to form a linear pair of congruent angles, so BD  AC and BD is an altitude of  ABC.

5.4 Guided Practice 4. Copy the triangle in Example 4 and find its orthocenter. ANSWER

5.4 Guided Practice In Example 4, suppose you wanted to show that median BD is also an angle bisector. How would your proof be different? 5. WHAT IF? CBD ABD by SSS making ABD CBD which leads to BD being an angle bisector. ANSWER

5.4 Guided Practice 6. Triangle PQR is an isoscleles triangle and OQ is an altitude. What else do you know about OQ ? What are the coordinates of P ? OQ is also a perpendicular bisector, angle bisector, and median; (–h, 0). ANSWER

5.4 Lesson Quiz In Exercises 1–3, use the diagram. G is the centroid of ABC. 1. If BG = 9, find BF. ANSWER If BD = 12, find AD. ANSWER If CD = 27, find GC. ANSWER 18

5.4 Lesson Quiz ANSWER (1, 1) 5. Which type of triangle has its orthocenter on the triangle? ANSWER a right triangle 4. Find the centroid of ABC.