Polynomials So what? What is important to understand about this? The concept is important for the AHSGE Objective I-2. You may add or subtract polynomials.

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Presentation transcript:

Polynomials So what? What is important to understand about this? The concept is important for the AHSGE Objective I-2. You may add or subtract polynomials when determining or representing a customers order at a store. Main idea Monomials Example: 4x 3 Cubic 5 Constant Number of terms : One Degree: Sum the exponents of its variables Main idea Binomials Example: 7x + 4 Linear 9x th degree Number of terms: Two Degree: The degree of monomial with greatest degree Main idea Trinomials Example: 3x 2 + 2x + 1 Quadratic Number of terms: Three Degree: The degree of the monomial with greatest degree Main idea Polynomials Example: 3x 5 + 2x 3 + 5x 2 + x th degree Number of terms: Many (> three) Degree: The degree of the monomial with greatest degree

1. Graph the linear equations on the same coordinate plane.2. If the lines intersect, the solution is the point of intersection.3. If the lines are parallel, there is no solution.1. Graph the linear equations on the same coordinate plane.2. If the lines intersect, the solution is the point of intersection.3. If the lines are parallel, there is no solution. Polynomial Products Multiplying Polynomials and Special Products So what? What is important to understand about this? AHSGE Objective: I -3. Applications include finding area and volume. Special products are used in graphing functions by hand. Punnett Squares in Biology. Main idea Polynomials times Polynomials Monomial times a Polynomial: Use the distributive property (x coeff + exponents) Example: -4y 2 ( 5y 4 – 3y ) = -20y y 4 – 8y 2 Polynomial times a Polynomial: Use the distributive Property Example: (2x – 3) ( 4x 2 + x – 6) = 8x 3 – 10x 2 – 15x + 18 Main idea Binomials times Binomials FOIL: F = First O = Outer I = Inner L = Last Example: (3x – 5 )( 2x + 7)= 6x x - 35 Main idea Square of a Binomial (a + b) 2 = a 2 + 2ab + b 2 (a – b) 2 = a 2 – 2ab + b 2 1 st term: Square the first term 2 nd term: Multiply two terms and Double 3 rd term: Square the last term Examples: (x + 6) 2 = x x + 36 (7m – 2p) 2 = 49m 2 –14mp + 4p 2 Main idea Difference of Two Squares DOTS: (a + b) ( a – b) = a 2 – b 2 Example: (t 3 – 6) (t 3 + 6) = t 6 – 36

1. Graph the linear equations on the same coordinate plane.2. If the lines intersect, the solution is the point of intersection.3. If the lines are parallel, there is no solution.1. Graph the linear equations on the same coordinate plane.2. If the lines intersect, the solution is the point of intersection.3. If the lines are parallel, there is no solution. Solving Systems of Linear Equations Is about … Finding solutions for more than one linear equation by using one of four methods. So what? What is important to understand about this? Method 1 GRAPHING Method 2 SUBSTITUTION 1.Solve one of the linear equations for one of the variables (look for a coefficient of one). 2.Substitute this variable’s value into the other equation. 3.Solve the new equation for the one remaining variable. 4.Substitute this value into one of the original equations and find the remaining variable value. Method 3 ELIMINATION Look for variables with opposite or same coefficients. If the coefficients are opposites, add the equations together. If the coefficients are the same, subtract the equations, by changing the sign of each term in the 2 nd equation and adding. Substitute the value of the remaining variable back into one of the orig. equations to find the other variable. Method 4 ELIMINATION W/MULTIPLICATION 1.1. Choose a variable to eliminate Look the coefficients and find their LCD. This is the value you are trying to get Multiply each equation by the needed factor to get the LCD Continue as for regular elimination Graph the linear equations on the same coordinate plane If the lines intersect, the solution is the point of intersection If the lines are parallel, there is no solution If the lines coincide, there is infinitely many solutions The solution (if it has just one) is an ordered pair. This point is a solution to both equations and will test true if substituted into each equation.