SOLUTION Write an equation for the total number of quarts and an equation for the number of quarts of antifreeze. Let x be the number of quarts of 100%

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SOLUTION Write an equation for the total number of quarts and an equation for the number of quarts of antifreeze. Let x be the number of quarts of 100% antifreeze, and let y be the number of quarts of a 50% antifreeze and 50% water mix. STEP 1 For extremely cold temperatures, an automobile manufacturer recommends that a 70% antifreeze and 30% water mix be used in the cooling system of a car. How many quarts of pure ( 100% ) antifreeze and a 50% antifreeze and 50% water mix should be combined to make 11 quarts of a 70% antifreeze and 30% water mix? ANTIFREEZE Solve a mixture problem EXAMPLE 4

Equation 1 : Total number of quarts x + y = 11 Equation 2 : Number of quarts of antifreeze x quarts of 100% antifreeze y quarts of 50% –50% mix 11 quarts of 70% – 30% mix 1 x y = 0.7(11) x + 0.5y = 7.7 Solve a mixture problem EXAMPLE 4

The system of equations is: x + 0.5y = 7.7 Solve Equation 1 for x. x + y = 11 x = 11 – y Substitute 11 – y for x in Equation 2 and solve for y. x + 0.5y = 7.7 STEP 2 STEP 3 Equation 1 x + y =11 Equation 2 Write Equation 1. Revised Equation 1 Write Equation 2. Solve a mixture problem EXAMPLE 4

Solve a mixture problem EXAMPLE 4 ( 11 – y ) = 0.5y = 7.7 y = 6.6 Substitute 6.6 for y in the revised Equation 1 to find the value of x. STEP 4 x = 11 – y = 11 – 6.6 = 4.4 ANSWER Mix 4.4 quarts of 100% antifreeze and 6.6 quarts of a 50% antifreeze and 50% water mix to get 11 quarts of a 70% antifreeze and 30% water mix. Substitute 11 – y for x. Solve for y.

GUIDED PRACTICE for Example 4 WHAT IF ? How many quarts of 100% antifreeze and a 50% antifreeze and 50% water mix should be combined to make 16 quartz of a 70% antifreeze and 30% water mix ? 6. SOLUTION Write an equation for the total number of quarts and anequation for the number of quarts of antifreeze. Let x be the number of quarts of 100% antifreeze, and let y be the number of quarts of a 50% antifreeze and 50% water mix. STEP 1

GUIDED PRACTICE for Example 4 Equation 1 : Total number of quarts x + y = 16 Equation 2 : Number of quarts of antifreeze x quarts of 100% antifreeze y quarts of 50% –50% mix 11 quarts of 70% – 30% mix 1 x y = 0.7(16) x + 0.5y = 11.2

GUIDED PRACTICE for Example 4 The system of equations is: x + 0.5y = 11.2 Solve Equation 1 for x. x + y = 16 x = 16 – y STEP 2 Equation 1 x + y =16 Equation 2. Write Equation 1. Revised Equation 1

GUIDED PRACTICE for Example 4 ( 16 – y ) = 0.5y = 7.7 y = 9.6 Substitute 16 – y for x. Solve for y. Substitute 16 – y for x in Equation 1 and solve for x. x + 0.5y = 7.7 STEP 3 Write Equation 2.

GUIDED PRACTICE for Example 4 Substitute 9.6 for y in the revised Equation 1 to find the value of x. STEP 4 x = 16 – y = 16 – 9.6 = 6. 4 ANSWER Mix 6.4 quarts of 100% antifreeze and 9.6 quarts of a 50% Antifreeze.