Warm up Why do we have to balance chemical equations? 2. Balance these chemical equations: a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF 3 c) HCl + CaCO 3 → H 2 O + CO 2 + CaCl 2 Agenda -Turn in Lab -Notes Unit 5-3 -One-on-One grade check -WS Practice Unit 5-3 Homework Dec 9 - Deadline for quiz retake

a) Sb + O 2 → Sb 4 O 6 b) FeCl 3 + KF → KCl + FeF 3 c) HCl + CaCO 3 → H 2 O + CO 2 + CaCl 2

Unit 5-3 Types of Chemical Reactions

Types of Chemical Reactions Synthesis or Combination A + B → AB Ex: 2Na (s) + Cl 2 (g) → 2NaCl (s) The love story

Types of Chemical Reactions Decomposition AB → A + B Ex: 2H 2 O → 2H 2 + O 2 The break-up

Types of Chemical Reactions Single Replacement or Single Displacement AX + B → BX + A Ex: CuSO 4 + Zn (s) → ZnSO 4 + Cu (s) The complication

Types of Chemical Reactions Double Replacement or Double Displacement AB + CD → CB + AD Ex: Pb(NO 3 ) 2 + 2KI → PbI 2 + 2KNO 3

Types of Chemical Reactions Combustion Carbon compound + O 2 → CO 2 + H 2 O Ex: CH 4 + 2O 2 → CO 2 + 2H 2 O

Check In Name the reaction type for the following equations: NH 3 + H 2 SO 4 → (NH 4 ) 2 SO 4 HgO → Hg + O 2 CH 4 + O 2 → H 2 O + CO 2 CuCl 2 + H 2 S → CuS + HCl BaCl 2 + Na 2 SO 4 → NaCl + BaSO 4 Synthesis Decomposition Combustion Double Replace.

Percent Yield Analysis of the efficiency for chemical reaction Percent Yield calculation

Percent Yield Theoretical yield – The maximum amount of products that can be formed in a reaction based on calculation

Percent Yield The actual yield – Real amount produced in a reaction (usually less than the expected theoretical yield).

Percent Yield Example A reaction should have produced 1.44g of MgO. After the experiment, only 1.23g of magnesium oxide was present. What is the percent yield?

Assignments Summary Practice Worksheet due next class One-on-One grade check