Probability The Study of Randomness The language of probability Random is a description of a kind of order that emerges only in the long run even though.

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Probability: The Study of Randomness
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Presentation transcript:

Probability The Study of Randomness

The language of probability Random is a description of a kind of order that emerges only in the long run even though individual outcomes are uncertain. The probability of any outcome of a random phenomenon is the proportion of times the outcome would occur in a very long series of repetitions.repetitions POP QUIZ!!!

Mongolian History 1300 – False6. False 2. False7. True 3. True8. True 4. False9. False 5. True10. True

Mongolian History 1300 – D16. E21. E26. D 12. E17. A22. B27. A 13. B18. A23. B28. C 14. B19. C24. A29. B 15. A20. E25. A30. E

Mongolian Probability The sample space of a random event is the set of all possible outcomes. What is the sample space for answering one true/false question? S = {T, F} What is the sample space for answering two true/false questions? S = {TT, TF, FT, FF} What is the sample space for three?

Tree diagram S = {TTT, TTF, TFT, FTT, FFT, FTF, TFF, FFF} True False True False True False

Multiplication Principle Explain what you think the multiplication principle is regarding our previous example. If you can do one task in a number of ways and a second task in b number of ways, both tasks can be done in a x b number of ways. If we answer 4 true/false and 2 multiple choice (5), how many possible outcomes are possible?

Basic Probability Rules Any probability is a number between 0 and 1. All possible outcomes together must have probability of 1. The probability that an event does not occur is 1 minus the probability that the event does occur.

Venn diagram: complement AAcAc S

General Addition Rule for Unions of Two Events For any two events A and B, P(A or B) = P(A) + P(B) – P(A and B) The simultaneous occurrence of two events is called a joint event. The union of any collections of event that at least one of the collection occurs.

Venn diagram: union S A B

Venn diagram: disjoint events A B S

Suppose that 60% of all customers of a large insurance agency have automobile policies with the agency, 40% have homeowner’s policies, and 25% have both types of policies. If a customer is randomly selected, what is the probability that he or she has at least one of these two types of policies with the agency? Examples P(A or B) = P(A) + P(B) – P(A and B) P(auto or home) = .25 =.75

General Multiplication Rule The joint probability that both of two events A and B happen together can be found by P(A and B) = P(A) P(B|A) P(B|A) is the conditional probability that B occurs given the information that A occurs.

Multiplication Rule Practice Drawing two aces with replacement. Drawing three face cards with replacement.

Multiplication Rule Practice Draw 5 reds cards without replacement. Draw two even numbered cards without replacement.

Multiplication Rule Practice Draw three odd numbered red cards with replacement.

Definition of Conditional Probability When P(A)>0, the conditional probability of B given A is

Example What is the probability of a GFI switch from a selected spa is from company 1? What is the probability of a GFI switch from a selected spa is defective?

Example What is the probability of a GFI switch from a selected spa is defective and from company 1? What is the probability of a GFI switch from a selected spa is from company 1 given that it is defective?

Example P(A and B) = P(A) P(B|A)

What is the probability of an individual having tuberculosis given the DNA test is negative?

Conditional probability in medicine False positive P(no disease|test positive) False negative P(disease|test negative) Sensitivity P(disease|test positive) Specificity P(no disease|test negative)

Independent Events? Pick a card, replace/reshuffle, pick another. What is the probability that the first card is red and the second is a king? P(A and B) = P(A) P(B|A) P(red and king) = P(red)*P(king|red) P(red and king) = P(red)*P(king) Two events A and B that both have positive probability are independent iff P(B|A) = P(B)

Is the event that a participant is male and the event that he correctly identified tap water independent? YesNoTotal Male Female Total Jack and Jill have finished conducting taste tests with 100 adults from their neighborhood. They found that 60 of them correctly identified the tap water. The data is displayed below.

YesNoTotal Male Female Total In order for a participant being male and the event that he correctly identified tap water to be independent, we know that P(male|yes) = P(male) or P(yes|male) = P(yes)

YesNoTotal Male Female Total In order for a participant being male and the event that he correctly identified tap water to be independent, we know that P(yes|male) = P(yes)

YesNoTotal Male Female Total In order for a participant being male and the event that he correctly identified tap water to be independent, we know that P(male|yes) = P(male)

Example We will assume that the table from the article is indicative of the larger group of chat room users. Suppose that a chat room user is randomly selected. Let C = event that the individual has criticized others and let O = event that the individual has been personally criticized by others.

Example continued

Conditional Probability with Tree Diagrams Dr. Carey has two bottles of sample pills on his desk for the treatment of arthritic pain. He often grabs a bottle without looking and takes the medicine. Since the first bottle is closer to him, the chances of grabbing it are He knows the medicine from this bottle relieves the pain 70% of the time while the medicine in the second bottle relieves the pain 90% of the time. What is the probability that Dr. Carey grabbed the first bottle given his pain was not relieved?

1 st 2 nd.6.4 relieved not relieved not