By: GROUP 8 ~ Saga Linea Gonzales ~ Harriette Pauline Herrera ~ Vin Sebastian Lascota ~ Ian Paolo Llapitan
Problem #1: The Length of a rectangular piece of property is 1 foot more than twice of the width. If the perimeter is 302 feet, find the length and the width.
Solution: Let x = width 2x+1 = length The perimeter of a triangle is modelled by the equation: 2L + 2W = P 2(2x+1)+2(x)=302 4x+2+2x=302 6x=302 Width: x=50 Length: 2x+1=101
REASON: Because... P=2(101)+ 2(50)=302 and 101 is 1 more than twice 50 feet.
Problem #2: If the length of a rectangular parking lot is 10m less than twice its width, and the perimeter is 400m, find the length of a parking lot.
Solution: Let x = the width 2x-10 = the length P = 2L + 2W 400 = 2(2x-10)+2(x) 400 = 2(2x-10)+2x 400 = 4x-20+2x = 4x + 2x 420 = 6x 70 = x Length: 2x-10 = 2(70)-10 = 130m
The formula for the perimeter is: P = 2L + 2W There fore, 400 = 2(2x-10)+2(x) So, when we simplify this problem, It is equal to: 420 = 6x When we divide both sides by 6, The answer is: 420 = 6x Therefore, the answer is: Length: 2x-10 = 2(70)-10 = 130m
Problem #3 Greg Smith invested some money in a certificate of deposit with annual yield of 9%. He invested twice as much as the annual yield of 12%. His interest from two investments at the end of the year was $396. How much money was invested at each rate?
Solution: PrincipalRateInterest Certificate of deposit X9% = x Mutual Fund2x12% = (2x) The fact that the total interest from the investments was $396 is expressed in the following equation: 0.09x+0.12(2x) = x = x = 396 x = x = 2400 Now, $108+$288 = $396. So Greg invested $1200 at 9% and $2400 at 12%
REASON: $108+$288 = $396 Therefore, the investment of Greg is $1200 at 9% And $2400 at 12%
SOURCES Problem 1 and 3: ~ Algebra for College Students,Dugapolski M., 2001, McGraw-Hill Book Co. Problem 2: ~ MSA: Elementary Algebra, Alferez, M., Duro, M., 2007, MSA Publishing House