Medical Instrumentation

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Presentation transcript:

Medical Instrumentation HW #3 2004200456 Lim Myeong Jun

Contents Resistive sensor Capacitive sensor Inductive sensor LVDT Problem solution Piezoelectric sensor Electromagnetic spectrum Radiation thermometer

Resistive sensor Strain gage : Changes in L & ρ ∵ ρ : Specific resistance Strain gage : Changes in L & ρ Force sensing resistor : Changes in A Thermister : Changes in temperature Potentiometer : Changes in Length

Force sensing resistor(FSR)

Thermister R Ceramic NTC thermister (Negative temperature coefficient) PTC thermister (Positive temperature coefficient)

Thermister + Vout - Vo, Vs, F, T : Non linear A ) - + B )

Thermister C ) Bridge circuit Rs Rp R Linear range D ) Linearization

Capacitive & Inductive sensor Capacitive sensor x A εR Most capacitive sensor is based on changes in x. Inductive sensor Self Inductance Mutual Inductance Difference Inductance

LVDT LVDT(Linear Variable Differential Transformer) a c x=D x= δ d f Primary coil

LVDT Magnetic core + Vo - Mutual Inductance Sensor Line is Vs and dot is Vo at magnetic core

LVDT When core is x=0

LVDT When core is x=+δ

LVDT When core is x=- δ

Problem #13 Vertical displacement Given by Vs(t) = sin(2π*1000t) [V] (f = 1000Hz, T = 1ms) 180º Phase change

Problem #13 Method 1: Rectifier + LPF Full x=D wave rectifier x=0 x=-D D=20mm, 2D=40mm V(t) t

Problem #13 Method 2: Phase-Sensitive demodulation Vo(t) x(t)·Vo²(t) x(t) = sin(2π· 1000t) LPF(Low Pass Filter) V(t) t V(t)

Problem #14 In phase-sensitive demodulation Vo(t) Vm(t) x(t) = sin(2π· 1000t) LPF(Low Pass Filter) V(t)

Problem #14 formula

Piezoelectric sensor x q : Charge , x : Deflection Fig. piezoelectric sensor x q : Charge , x : Deflection That means piezoelectric sensor has no DC response.

Piezoelectric sensor 1) i(t) Vs(t) = R*i(t) i=0 + IA - Vo(t)

Piezoelectric sensor 2) i(t), Current flow - IA + Vo(t) 0V Change Amplifier

Piezoelectric sensor |H| If you plan to use the piezoelectric sensor, for measuring pulse, the lowest frequency of pulse, signal is assumed to be 0.1Hz k/c fc f = 1/2πRC

Thanks for your attention!