Quadratic Cliff Jumping Deann Anguiano Laura Moore-Mueller Russ Ballard Lake Chelan Conference 2008.

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Presentation transcript:

Quadratic Cliff Jumping Deann Anguiano Laura Moore-Mueller Russ Ballard Lake Chelan Conference 2008

May 2,

3 Motion along a curved path What is happening The scene is messy What can be assumed What are the concepts

May 2,

5

6

7

8

9 Why use projectile motion? Position vs. position graph Apply regression curve First few points do not work

May 2, Which points? Depends on what’s occurring Symmetry Vertex

May 2, Hot wheels Instructions –You have a sheet for the activity Data gathering –Gather as much data as possible –Three to four runs is a minimum

May 2, Challenge cup Team Crimson –Given a height you pick position Team Silver –Given a position you pick the height

May 2, Tossing the ball Watch the ball being tossed into the air Plot a d vs. t graph of the motion on your ball toss graph

May 2, Tossing the ball Exchange with a neighbor Answer questions based on graph in front of you How long was the ball in the air? Is the vertical distance as the ball travels upward the same or different as the vertical distance traveled downward? Is the time from the launch to the vertex the same as the vertex to the ground?

May 2, Why use distance vs time? Return the graph to the owner and owners now reflect –What kind of motion did I graph? –If it was incorrect why would the graph mislead a student? –If necessary redraw the graph on the opposite side of the paper.

May 2,

May 2, What is the motion? In the horizontal? In the vertical? Motion is parametric Look at the vertical motion

May 2, Horizontal motion

May 2, Vertical motion

May 2, a(t) = m/sec 2 v(t) = area in graph in the rectangle Therefore v(t) = -9.81m/s 2 * t(s) Or the ball is traveling at -9.81*t m/s after t seconds

May 2, Initial velocity is zero at the top After one second it = m/s Slope is constant so the area under the curve is a triangle =½ base * height =½ t(s) * (-9.81*t m/s) = -4.9 t 2 (m) I second Velocity = m/s Velocity(m/s) time (s)

May 2, Y = At^2 + Bt +C A: B:6.513 C:-1.168

May 2,

May 2, T3 clip Calculate if the TX will make to the hearse roof. Distance and speed of hearse 20 m/s 26 m travel Distance vertical that TX will fall 8.3 m Distance at speed horizontal she is traveling 7.9 m/s 10.3 m

May 2, Vernier LoggerPRo Hand out Vernier LoggerPRo profile

May 2, Video Analysis Demo video analysis of the clip if time

All info is located at russballard.com/workshop/chelan conference 2008

Questions?