Law of Cosines. Let's consider types of triangles with the three pieces of information shown below. SAS You may have a side, an angle, and then another.

Slides:



Advertisements
Similar presentations
The Law of Cosines.
Advertisements

The Law of Cosines February 25, 2010.
(8 – 2) Law of Sines Learning target: To solve SAA or ASA triangles To solve SSA triangles To solve applied problems We work with any triangles: Important.
LAW OF SINE Sin A = Sin B = Sin C a b c A, B and C are angles. a, b and c are the sides opposite their angles. Use when: you have 2 angles and a side (AAS.
Unit 8: Modeling with Trigonometric Functions
The Law of Sines and The Law of Cosines
7 Days. Two days  In any triangle, the ratio of the sine of any angle to the side opposite that angle is equal to the ratio of the sine of another angle.
The Law of Sines and The Law of Cosines
FUNCTIONS OF ANY ANGLE, OBLIQUE TRIANGLES
Math 112 Elementary Functions Section 2 The Law of Cosines Chapter 7 – Applications of Trigonometry.
Areas of Regular Polygons
The Law of SINES.
Work out problems on board Add visuals (ranges of arccos and arcsin) to show why you use LOC for big angles and LOS for small angles.
Areas of Regular Polygons Lesson Equilateral Triangle Remember: drop an altitude and you create two triangles. What is the measure of the.
Math 010: Chapter 9 Geometry Lines, figures, & triangles
Ambiguous Case Triangles
Right Triangle Trig Review Given the right triangle from the origin to the point (x, y) with the angle, we can find the following trig functions:
Geometry CRCT Prep.
Solving Right Triangles
6.2 LAW OF COSINES. 2 Use the Law of Cosines to solve oblique triangles (SSS or SAS). Use the Law of Cosines to model and solve real-life problems. Use.
Lesson 6.1 Law of Sines. Draw any altitude from a vertex and label it k. Set up equivalent trig equations not involving k, using the fact that k is equal.
Section 7.1 & 7.2- Oblique Triangles (non-right triangle)
Trigonometric Equations M 140 Precalculus V. J. Motto.
Solve a triangle for the AAS or ASA case
The Law of Sines The Law of Cosines And we’re not talking traffic (7.1, 7.2)
6.2 The Law of Cosines.
Chapter 11 Area of Polygons and Circles. Chapter 11 Objectives Calculate the sum of the interior angles of any polygon Calculate the area of any regular.
9.5 Apply the Law of Sines When can the law of sines be used to solve a triangle? How is the SSA case different from the AAS and ASA cases?
Notes Over 8.1 Solving Oblique Triangles To solve an oblique triangle, you need to be given one side, and at least two other parts (sides or angles).
Math /7.2 – The Law of Sines 1. Q: We know how to solve right triangles using trig, but how can we use trig to solve any triangle? A: The Law of.
The Law of Cosines. Let's consider types of triangles with the three pieces of information shown below. SAS You may have a side, an angle, and then another.
The Law of Cosines. Let's consider types of triangles with the three pieces of information shown below. SAS You may have a side, an angle, and then another.
Chapter 8 Section 8.2 Law of Cosines. In any triangle (not necessarily a right triangle) the square of the length of one side of the triangle is equal.
EXAMPLE 2 Solve the SSA case with one solution Solve ABC with A = 115°, a = 20, and b = 11. SOLUTION First make a sketch. Because A is obtuse and the side.
Lesson 6.5 Law of Cosines. Solving a Triangle using Law of Sines 2 The Law of Sines was good for: ASA- two angles and the included side AAS- two angles.
1 Equations 7.3 The Law of Cosines 7.4 The Area of a Triangle Chapter 7.
Lesson 6.1- Law of Sines Provided by Vivian Skumpija and Amy Gimpel.
Section 4.2 – The Law of Sines. If none of the angles of a triangle is a right angle, the triangle is called oblique. An oblique triangle has either three.
The Inverse Trigonometric Functions. Let's again review a few things about inverse functions. To have an inverse function, a function must be one-to-one.
7.7 Law of Cosines. Use the Law of Cosines to solve triangles and problems.
Chapter 5 Relationships within Triangles  Midsegments  Perpendicular bisectors - Circumcenter  Angle Bisectors – Incenter  Medians – Centroid  Altitudes.
Law of Sines AAS ONE SOLUTION SSA AMBIGUOUS CASE ASA ONE SOLUTION Domain error NO SOLUTION Second angle option violates triangle angle-sum theorem ONE.
Law of Cosines If you do not have a right triangle you use Law of Sines or Law of cosines. SOH CAH TOA only works in right triangles!
Law of Cosines HOMEWORK: Lesson 12.4/ Who's Law Is It, Anyway?  Murphy's Law: Anything that can possibly go wrong, will go wrong (at the worst.
Area of Regular Polygons Terms Radius – segment joining the center of the polygon to the vertex of the polygon. All radii of a polygon are equal. When.
Splash Screen. Then/Now You used trigonometric ratios to solve right triangles. Use the Law of Sines to solve triangles. Use the Law of Cosines to solve.
Right Triangle Trig Review Given the right triangle from the origin to the point (x, y) with the angle, we can find the following trig functions:
Copyright © 2011 Pearson Education, Inc. Slide
SOH CAH TOA only works in right triangles!
7.2 The Law of Cosines and Area Formulas
7.2 LAW OF COSINES.
The Law of SINES.
The Inverse Trigonometric Functions
6.2 The Law of Cosines.
Ambiguous Case Triangles
Re:view Use the Law of Sines to solve: Solve ABC
The Law of Cosines.
The Law of Cosines.
The Laws of SINES and COSINES.
Law of Cosines Lesson 4.2.
8-5 The Law of Sines Geometry.
7.7 Law of Cosines.
Law of Cosines.
The Law of Cosines.
Law of Cosines.
The Law of Cosines.
The Law of Sines.
7.1, 7.2, 7.3 Law of Sines and Law of Cosines
Ambiguous Case Triangles
6.1 Laws of Sines.
Presentation transcript:

Law of Cosines

Let's consider types of triangles with the three pieces of information shown below. SAS You may have a side, an angle, and then another side AAA You may have all three angles. SSS You may have all three sides This case doesn't determine a triangle because similar triangles have the same angles and shape but "blown up" or "shrunk down" We can't use the Law of Sines on these because we don't have an angle and a side opposite it. We need another method for SAS and SSS triangles. AAA

Let's place a triangle on the rectangular coordinate system.  a b c (b, 0) What is the coordinate here? Drop down a perpendicular line from this vertex and use right triangle trig to find it. (x, y) (a cos , a sin  ) Now we'll use the distance formula to find c (use the 2 points shown on graph) square both sides and FOIL factor out a 2 This = 1 y x rearrange termsThis is the Law of Cosines

We could do the same thing if gamma was obtuse and we could repeat this process for each of the other sides. We end up with the following: LAW OF COSINES If you say it in words, you don't need to memorize 3 formulas: One side squared equals the sum of each of the other sides squared minus two times the product of those other sides times the cosine of the angle between those sides.

Since the Law of Cosines is more involved than the Law of Sines, when you see a triangle to solve you first look to see if you have an angle (or can find one) and a side opposite it. You can do this for ASA, AAS and SSA. In these cases you'd solve using the Law of Sines. However, if the 3 pieces of info you know don't include an angle and side opposite it, you must use the Law of Cosines. These would be for SAS and SSS (remember you can't solve for AAA).

Solve a triangle where b = 1, c = 3 and  = 80° Draw a picture. 80   a 1 3 Do we know an angle and side opposite it? No so we must use Law of Cosines. Hint: we will be solving for the side opposite the angle we know. This is SAS times the cosine of the angle between those sides One side squared sum of each of the other sides squared minus 2 times the product of those other sides Now punch buttons on your calculator to find a. It will be square root of right hand side. a = 2.99 CAUTION: Don't forget order of operations: powers then multiplication BEFORE addition and subtraction

We'll label side a with the value we found. We now have all of the sides but how can we find an angle? 80   Hint: We have an angle and a side opposite it  is easy to find since the sum of the angles is a triangle is 180° 19.2 NOTE: These answers are correct to 2 decimal places for sides and 1 for angles. They may differ with book slightly due to rounding. Keep the answer for  in your calculator and use that for better accuracy.

Solve a triangle where a = 5, b = 8 and c = 9 Draw a picture.   Do we know an angle and side opposite it? No, so we must use Law of Cosines. Let's use largest side to find largest angle first. This is SSS times the cosine of the angle between those sides One side squared sum of each of the other sides squared minus 2 times the product of those other sides CAUTION: Don't forget order of operations: powers then multiplication BEFORE addition and subtraction  84.3

How can we find one of the remaining angles?   Do we know an angle and side opposite it?  Yes, so use Law of Sines.

Length of Chord A chord is a line segment inside a circle with endpoints on the circle. If we wanted to find the length a of the chord shown on the left, can you think of something you just learned to help you find this length? The Law of Cosines! Equation for Length of Chord

So to find the length of a chord, we’d need the radius of the circle r and the central angle  which is the angle formed with the center of the circle as the vertex and rays containing the endpoints of the chord.

Find the length of the side of a regular hexagon inscribed in circle of radius 5. 5  a Let’s get a picture of this. We’ve got r but how do we find  ? We could also have arrived at this seeing that we have an equilateral triangle.