The Solubility Product Principle Chapter 20. __________: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter.

Slides:



Advertisements
Similar presentations
Solubility and Complex-Ion Equilibria
Advertisements

SOLUBILITY Saturated Solution BaSO 4(s)  Ba 2+ (aq) + SO 4 2- (aq) Equilibrium expresses the degree of solubility of solid in water. Equilibrium expresses.
Equilibrium and Solubility 1.Solubility rules for common ions 2.Using the solubility product, K sp, to calculate solubility - molar solubility, gram solubility.
Notes handout, equilibrium video part 2. 2 Le Chatelier’s Principle: if you disturb an equilibrium, it will shift to undo the disturbance. Remember, in.
Solubility Product Constant 6-5 Ksp. is a variation on the equilibrium constant for a solute-solution equilibrium. remember that the solubility equilibrium.
Please Pick Up Solubility Products Constants Data Sheet Heterogeneous Equilibria Problem Set.
Solubility Product Constants Silver chloride, AgCl,is rather insoluble in water. Careful experiments show that if solid AgCl is placed in pure water and.
The Solubility Product Principle. 2 Silver chloride, AgCl,is rather insoluble in water. Careful experiments show that if solid AgCl is placed in pure.
The K sp of chromium (III) iodate in water is 5.0 x Estimate the molar solubility of the compound. Cr(IO 3 ) 3 (s)  Cr 3+ (aq) + 3 IO 3 - (aq)
Please Pick Up Solubility Products Constants Data Sheet Heterogeneous Equilibria Problem Set Sample page from the Handbook of Chemistry and Physics.
Solubility Equilibria
PRECIPITATION REACTIONS Chapter 17 Part 2 2 Insoluble Chlorides All salts formed in this experiment are said to be INSOLUBLE and form precipitates when.
Precipitation Equilibrium Solubility Product Principle
A salt, BaSO4(s), is placed in water
Ksp and Solubility Equilibria
Section 4: Solubility Equilibrium. Objectives Explain what is meant by solubility product constants, and calculate their values. Calculate solubilities.
Chapter 18: Solubility and Complex-Ion Equilibria Chemistry 1062: Principles of Chemistry II Andy Aspaas, Instructor.
Ionic Equilibria III: The Solubility Product Principle
Solutions. Definitions Solution: homogeneous mixture of 2 or more substances in a single physical state Solute: the substance dissolved in the solution.
Copyright Sautter SOLUBILITY EQUILIBRIUM Solubility refers to the ability of a substance to dissolve. In the study of solubility equilibrium we.
Solubility and Complex-ion Equilibria. 2 Solubility Equilibria Many natural processes depend on the precipitation or dissolving of a slightly soluble.
11111 Chemistry 132 NT The most difficult thing to understand is the income tax. Albert Einstein.
Dilute vs. Concentrated Concentrated solutions Concentrated solutions contain a high amount of solute. Diluted solutions Diluted solutions contain a low.
Chapter 18 The Solubility Product Constant. Review Quiz Nuclear Chemistry Thermochemistry –Hess’s Law –Heats (Enthalpies) of…
1 Chapter Seventeen Additional Aspects of Aqueous Equilibria.
Solubility of Salts & Complex Ions. Solubility of Salts Precipitation reactions occur when one of the products in a double replacement is a water-_________.
K sp and Solubility Equilibria. Saturated solutions of salts are another type of chemical equilibrium. Slightly soluble salts establish a dynamic equilibrium.
The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter.
Unit 17. Dissolution: the process in which an ionic solid dissolves in a polar liquid. AgCl (s) ↔ Ag + (aq) + Cl - (aq) Precipitation: the process in.
Solubility & SOLUBILITY PRODUCT CONSTANTS. Solubility Rules All Group 1 (alkali metals) and NH 4 + compounds are water soluble. All nitrate, acetate,
Which of the following solubility product expressions is incorrect?
 is an equilibrium expression for a chemical equation that represents the dissolving of an ionic compound  K sp = The product of the concentration of.
Chemistry 1011 Slot 51 Chemistry 1011 TOPIC Solubility Equilibrium TEXT REFERENCE Masterton and Hurley Chapter 16.1.
Solubility Equilibria 16.6 AgCl (s) Ag + (aq) + Cl - (aq) K sp = [Ag + ][Cl - ]K sp is the solubility product constant MgF 2 (s) Mg 2+ (aq) + 2F - (aq)
©2003 Mark S. Davis Chapter 4 Aqueous Reactions Solution Stoichiometry.
Solubility Equilibrium Solubility Product Constant Ionic compounds (salts) differ in their solubilities Most “insoluble” salts will actually dissolve.
Solubility Equilibria
1 Solubility Equilibria Dissolution M m X x (s)  m M n+ (aq) + x X y- (aq) Precipitation m M n+ (aq) + x X y- (aq)  M m X x (s) For a dissolution process,
Warm-Up Nitrogen and hydrogen gas react to form ammonia according to the reaction N2 (g) + 3H2 (g) –> 2NH3 (g) If a flask contains the mixture of reactants.
DO NOW: What is dissolution. What is precipitation
Properties of Solutions A Solution l A solution is made up of a solute and a solvent. l The solvent does the dissolving. l The solute is the substance.
CHE1102, Chapter 17 Learn, 1 Chapter 17 Solubility and Simultaneous Equilibria.
E 12 Water and Soil Solve problems relating to removal of heavy –metal ions and phosphates by chemical precipitation
Acid-Base Equilibria and Solubility Equilibria Chapter 16.
Ch 12.1 Types of Mixtures. Heterogeneous vs. Homogeneous Mixtures Heterogeneous Mixture: mixture does not have a uniform composition. Ex: Milk and soil.
N OTES 17-3 Obj. 17.4, S OLUBILITY P RODUCTS A.) Consider the equilibrium that exists in a saturated solution of BaSO 4 in water: BaSO 4 (
Common-Ion EffectCommon-Ion Effect  Similar to acids and bases  There is a “common ion” when 2 salt solutions are mixed together.
1 16 Ionic Equilibria III: The Solubility Product Principle.
1 20 Ionic Equilibria III: The Solubility Product Principle.
SOLUBILITY – The maximum amount of solute that will dissolve in a specific amount of solvent EQUILIBRIA WITH SALTS SATURATED – A solution where the solid.
Solubility Equilibria Will it all dissolve, and if not, how much will?
K sp and the Solubility Product Constant. K sp The Solubility Product Constant The study of __________ _________ compounds.
Chapter 16 Solubility Equilibria. Saturated solutions of “insoluble” salts are another type of chemical equilibria. Ionic compounds that are termed “insoluble”
Ionic Equilibria III: The Solubility Product Principle
Types of Chemical Reactions & Solution Chemistry
The Solubility Product Principle
Chapter 7.6 Solubility Equilibria and the Solubility Product Constant
Chapter 16: Solubility Equilibria
Acids, Bases, and Solutions
A salt, BaSO4(s), is placed in water
Review Practice What is the molality of a solution created by adding 58 grams of magnesium hydroxide to 4 liters of water? Answer: 0.25 m Mg(OH)2 What.
Ionic Equilibria III: The Solubility Product Principle
Solubility and Complex-Ion Equilibria
Kc Ksp!!!!! Kp Kw Ka Kb.
Solubility Lesson 8 Review Notes.
Acids and Bases.
Solubility Equilibria
Gravimetric Analysis.
Ionic Equilibria III: The Solubility Product Principle
Presentation transcript:

The Solubility Product Principle Chapter 20

__________: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter or grams per 100 mL ____________________: number of moles of a compound that dissolve to give 1 Liter of saturated solution.

_____________________________: for a compound it is the product of the concentrations of its ions each raised to a power that corresponds to the number of ions formed. ____________________: the solubility of a compound is less in a solution that contains an ion common to the compound than it is in pure water.

Ex. 1) a. What is the solubility product expression for the dissociation of calcium carbonate? (K sp = solubility product constant.)

b. For aluminum fluoride?

c. For barium nitride?

Ex. 2) Calculate the molar solubility, concentrations of the constituent ions, and solubility in grams per liter of copper(II) hydroxide. K sp = 1.6 x

Ex. 3) Find [S 2- ] in saturated iron(III) sulfide K sp = 1.40x10 -88

Ex. 4) M FeI 3 is added to Ex. 3. What is the final concentration of iron and sulfur ions?

Ex. 5) Calculate the molar solubility and ion concentrations of aluminum fluoride in pure water and its solubility in grams per 100 mL. K sp = 6.4 x Then using the common ion effect, find the molar solubility of AlF 3 in 0.20 M potassium fluoride solution along with the ion concentrations and compare the molar solubilities.

Ex. 6) What is the solubility product constant if g of silver dichromate is in a one liter solution?

____________________: a separation process that removes some ions from solution while leaving other ions with similar properties in the solution.

Ex. 7) Solid silver nitrate is slowly added to a solution that is M each in sodium bromide and sodium iodide. Calculate the [Ag + ] required to initiate the precipitation of each silver halide. Which precipitates first? For AgBr: K sp = 3.3 x for AgI: K sp = 1.5 x For AgCl the K sp = 1.8 x Compare that to AgBr and AgI to determine which would precipitate last.

Ex. 8) Using your answer from #7, find the percentage of Iodine ions that precipitated before silver bromide precipitates.

Ex. 9) How many moles of bismuth(III) hydroxide will dissolve in 1.00 L of a solution with a pH=4.77 K sp = 3.2x10 -40

Reaction Quotient in Precipitation Reactions If Q sp < K sp ____________________ ◦No precipitation occurs; if solid is present, more solid can dissolve If Q sp = K sp ____________________ ◦Solid and solution are in equilibrium; neither forward nor reverse process is favored. If Q sp > K sp ____________________ ◦Precipitation occurs to form more solid

Extra Credit Opportunity Many industries require extremely large amounts of water as a coolant in heat exchange processes. Muddy or cloudy water usually doesn’t work b/c the solids may clog filters or deposit sediment in the pipes and pumps. Murky water can be clarified by adding agents that form colloids which settle out in holding tanks or ponds before the clarified water is moved to the plant intakes. If 56 g of Ca(OH) 2 and 75 g of MgSO 4 were added to 520 liters of water, would any of the compounds form precipitates?

K sp Ca(OH) 2 = 7.9 x K sp MgSO 4 = 4.8 x K sp CaSO 4 = 2.4 x K sp Mg(OH) 2 = 1.5 x