An Application Activity Projectile Motion An Application Activity

Projectile Motion When an object is dropped, it falls a distance of {(-16feet) or (-9.81meters)}t2 in t seconds. This is the force of gravity on any given object.

Projectile Motion What happens to a projectile that is launched with some initial vertical velocity, v0, (measured in distance units per second at some initial height h0 (measured in distances units).

Projectile Motion Horizontal motion is uniform, and independent of vertical motion. Vertical motion is free fall, and independent of horizontal motion.

Projectile Motion You know that a dropped object falls a distance of 16t2 feet in t seconds. When an object is not simply released but is thrown or launched, it is called a projectile. What happens to a projectile that is launched with some initial vertical velocity, Vo (measured in feet per second), at some initial height ho (measured in feet).

Projectile Motion Without gravity to pull the projectile its height h Would increase according to the equation h = vo t + ho With gravity, the projectile falls 16t2 feet in t seconds. So the projectile’s height at any time t is given by H = -16t2 + v0t + h0

Projectile Motion For a tennis ball, a baseball, and a model rocket, Find, the maximum height, the time it reached that height and the time the object returns to earth given the following velocities and starting heights

h(t) = {(-16ft) or (-9.81m)}t2 + v0t + h0 Projectile Motion h(t) = {(-16ft) or (-9.81m)}t2 + v0t + h0 Tennis ball h0 = 0.8m, v0 =34.7m/sec h0 = 1.0m, v0 =27.3m/sec Baseball h0 = 3.4ft., v0 =101mph h0 = 2.7ft, v0=80.67ft/sec Model Rocket h0 = 0.4ft., v0 =670ft/sec h0 = 2.4ft., v0 =490ft/sec