Chapter 6 One last thing…. Newton's 3 rd Law states that…

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Presentation transcript:

Chapter 6 One last thing…

Newton's 3 rd Law states that…

The force that object A puts on B is the same as object B puts on A (just in opposite directions) We can interpret this to mean that F A on B = -F B on A

What are the two things that make up force??

So can’t we substitute ma for F? Won’t this work? m A x a A = -m B x a B

What variables are we given? Practice problem: A 65 kg boy and a 45 kg girl use an elastic rope while engaged in a tug-of-war on an icy, frictionless surface. If the acceleration of the girl towards the boy is 3 m/s 2, find the acceleration of the boy towards the girl.

I have masses and accelerations for two different objects… Mass of boy = 65 kg Mass of girl = 45 kg Acc of girl = 3 m/s 2 Acc of boy = ?

Since we don’t have force, we will use the mass and acceleration.. Yes!! Use Newton’s 3 rd Law F A on B = -F B on A

65 x a = 45 x 3 65a = 135 a = 2.1 m/s 2

We are done. Quiz on Friday.