INTRODUCTORY MATHEMATICAL ANALYSIS For Business, Economics, and the Life and Social Sciences  2011 Pearson Education, Inc. Chapter 1 Applications and.

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INTRODUCTORY MATHEMATICAL ANALYSIS For Business, Economics, and the Life and Social Sciences  2011 Pearson Education, Inc. Chapter 1 Applications and More Algebra

 2011 Pearson Education, Inc. To model situations described by linear or quadratic equations. Chapter 1: Applications and More Algebra Chapter Objectives

 2011 Pearson Education, Inc. Chapter 1: Applications and More Algebra Chapter Outline Applications of Equations 1.1)

 2011 Pearson Education, Inc. Modeling: Translating relationships in the problems to mathematical symbols. Chapter 1: Applications and More Algebra 1.1 Applications of Equations A chemist must prepare 350 ml of a chemical solution made up of two parts alcohol and three parts acid. How much of each should be used? Example 1 - Mixture

 2011 Pearson Education, Inc. Solution: Let n = number of milliliters in each part. Each part has 70 ml. Amount of alcohol = 2n = 2(70) = 140 ml Amount of acid = 3n = 3(70) = 210 ml Chapter 1: Applications and More Algebra 1.1 Applications of Equations Example 1 - Mixture

 2011 Pearson Education, Inc. Fixed cost is the sum of all costs that are independent of the level of production. Variable cost is the sum of all costs that are dependent on the level of output. Total cost = variable cost + fixed cost Total revenue = (price per unit) x (number of units sold) Profit = total revenue − total cost Chapter 1: Applications and More Algebra 1.1 Applications of Equations

 2011 Pearson Education, Inc. The Anderson Company produces a product for which the variable cost per unit is $6 and the fixed cost is $80,000. Each unit has a selling price of $10. Determine the number of units that must be sold for the company to earn a profit of $60,000. Chapter 1: Applications and More Algebra 1.1 Applications of Equations Example 3 – Profit

 2011 Pearson Education, Inc. Solution: Let q = number of sold units. variable cost = 6q total cost = 6q + 80,000 total revenue = 10q Since profit = total revenue − total cost 35,000 units must be sold to earn a profit of $60,000. Chapter 1: Applications and More Algebra 1.1 Applications of Equations Example 3 – Profit

 2011 Pearson Education, Inc. Problem 1.1