Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!

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Presentation transcript:

Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!

Molarity = moles (Molar) or (M) litres

Calculate the molarity of 18 moles of LiBr dissolved in 6.0 L. =18 moles 6.0 L = 3.0 M

How many moles of AlF 3 are there in 20.5 L of a M solution?

How many moles of AlF 3 are there in 20.5 L of a M solution? 20.5 L x

How many moles of AlF 3 are there in 20.5 L of a M solution? 20.5 L x 1 L

How many moles of AlF 3 are there in 20.5 L of a M solution? 20.5 L x mole 1 L

How many moles of AlF 3 are there in 20.5 L of a M solution? 20.5 L x mole= 3.53 moles 1 L

STOICHIOMETRY

Stoichiometry is where you use the balancing coefficients to create a ratio between two different compounds in a chemical reaction.

1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2

1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g

2 4

105 g Fe

1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole 55.8 g

1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole x 2 mole Fe 2 O 55.8 g4 mole Fe

1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole x 2 mole Fe 2 O x g 55.8 g4 mole Fe 1 mole

1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole x 2 mole Fe 2 O x g = 150. g 55.8 g4 mole Fe 1 mole

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO 2

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO g ? g

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO g ? g 65.2 g x Na 2 CO 3 2 1

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO g Na 2 CO 3 2 1

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 x 2 mol NaCl g Na 2 CO 3 1 mol Na 2 CO 3 2 1

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 x 2 mol NaCl x 58.5 g NaCl g Na 2 CO 3 1 mol Na 2 CO 3 1 mol NaCl 2 1

How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO HCl → 2 NaCl + 1 H 2 O + 1 CO g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 x 2 mol NaCl x 58.5 g NaCl = 72.0 g g Na 2 CO 3 1 mol Na 2 CO 3 1 mol NaCl 2 1

30.2 L of HCl gas (as STP) is dissolved in L of water to produce an acid solution. What volume of M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2

30.2 L of HCl gas (as STP) is dissolved in L of water to produce an acid solution. What volume of M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl L ? L 30.2 L HCl 1 2

30.2 L of HCl gas (as STP) is dissolved in L of water to produce an acid solution. What volume of M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl L ? L 30.2 L HCl x 1 mol HCl 22.4 L 1 2

30.2 L of HCl gas (as STP) is dissolved in L of water to produce an acid solution. What volume of M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH) L 2 mol HCl 1 2

30.2 L of HCl gas (as STP) is dissolved in L of water to produce an acid solution. What volume of M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH) 2 x 1 L Ba(OH) 2 = 22.4 L 2 mol HCl mol Ba(OH) 2 1 2

30.2 L of HCl gas (as STP) is dissolved in L of water to produce an acid solution. What volume of M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH) 2 x 1 L Ba(OH) 2 = 3.37 L 22.4 L 2 mol HCl mol Ba(OH) 2 1 2

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO 4

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO L? L

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO L? L L H 2 SO 4

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO L? L L H 2 SO 4 x mol H 2 SO 4 1L

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO L? L L H 2 SO 4 x mol H 2 SO 4 x 2 mol KOH 1L 1 mol H 2 SO 4

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO L? L L H 2 SO 4 x mol H 2 SO 4 x 2 mol KOH x 1 L KOH 1L 1 mol H 2 SO mol KOH

250. mL of water is added to mL of M H 2 SO 4. What volume of M KOH will neutralize it? 1 H 2 SO KOH → 2 HOH + 1 K 2 SO L? L L H 2 SO 4 x mol H 2 SO 4 x 2 mol KOH x 1 L KOH 1L 1 mol H 2 SO mol KOH = L of KOH

Homework: Worksheet #4 (in Molarity Unit)