Wednesday June 15, 2005 1 PHYS 1443-001, Summer I 2005 Dr. Andrew Brandt PHYS 1443 – Section 001 Lecture #9 Wednesday June 15, 2005 Dr. Andrew Brandt Lightning.

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Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt PHYS 1443 – Section 001 Lecture #9 Wednesday June 15, 2005 Dr. Andrew Brandt Lightning review Conservation of Mechanical Energy Work Done by Non-conservative Forces Energy Diagram and Equilibrium Gravitational Potential Energy

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Announcements Test 2 Thursday 6/16, be there at 8am Homework: –HW5 on ch 6 due Wednesday 6/15 at 6pm

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Chapters 4-5 Force, Newton’s Laws, weight, free body diagrams, inclined planes, pulleys, friction, circular motion. Chapter 6 Gravitation, Newton, Kepler

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Example w/ Friction Suppose a block is placed on a rough surface inclined relative to the horizontal. The inclination angle is increased till the block starts to move. Show that by measuring this critical angle,  c, one can determine coefficient of static friction, s.s. Free-body Diagram  x y M a FgFg n n F= -Mg  fs=snfs=sn Net force x comp. y comp. x y On the verge of sliding, block is stationary, acceleration is zero, friction is static friction. If block moves at constant speed, acceleration is zero, friction is kinetic friction. Coefficient of kinetic friction can be calculated as

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Example for Potential Energy A bowler drops bowling ball of mass 7kg on his toe. Choosing floor level as y=0, estimate the total work done on the ball by the gravitational force as the ball falls. b) Perform the same calculation using the top of the bowler’s head as the origin. Assuming the bowler’s height is 1.8m, the ball’s original position is –1.3m, and the toe is at –1.77m. M Let’s assume the top of the toe is 0.03m from the floor and the hand was 0.5m above the floor. What has to change? First we must re-compute the positions of ball at the hand and the toe.

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Conservative Forces In Free fall, the work done on the object by the gravitation force is The work done on an object by a conservative force, such as the gravitational force, does not depend on the object’s path. How about if we lengthen the incline by a factor of 2, keeping the height the same? Still the same amount of work Forces like gravitational or elastic forces are called conservative forces So the work done by the gravitational force on an object is independent of the path of the object’s movement. It only depends on the difference of the object’s initial and final position in the direction of the force. h l m  mgmg When sliding down a hill of length l, the work is N Total mechanical energy is conserved!! 1.If the work performed by the force does not depend on the path. 2.If the work performed on a closed path is 0.

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Conservative Forces and Potential Energy The work done on an object by a conservative force is equal to the decrease in the potential energy of the system What else does this statement tell you? The work done by a conservative force is equal to the negative of the change of the potential energy associated with that force. We can rewrite the above equation in terms of potential energy U So the potential energy associated with a conservative force at any given position becomes Only the changes in potential energy of a system is physically meaningful!! Potential energy function What can you tell from the potential energy function above? Since Ui Ui is a constant, it only shifts the resulting U f (x) by a constant amount. One can always change the initial potential so that U i can be 0.

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Elastic Potential Energy The force a spring exerts on an object when it is distorted from its equilibrium by a distance x is Potential energy given to an object by a (frictionless) spring or an object with elasticity (the system, in this case, consists of the object and the spring) What do you see from the above equations? The work performed on the object by the spring is The work done on the object by the spring depends only on the initial and final position of the distorted spring. Where else did you see this trend? The potential energy of this system is The gravitational potential energy, UgUg So what does this tell you about the elastic force?A conservative force!!!

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Conservation of Mechanical Energy Total mechanical energy is the sum of kinetic and potential energies Let’s consider a brick of mass m at a height h from the ground The brick gains speed The lost potential energy converted to kinetic energy What does this mean? The total mechanical energy of a system remains constant in any isolated system of objects that interacts only through conservative forces: Principle of mechanical energy conservation m mgmg h What is its potential energy? What happens to the energy as the brick falls to the ground? m h1h1 By how much? So what? The brick’s kinetic energy increased And?

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Another KE+PE Example A ball of mass m is dropped from a height h above the ground. Neglecting air resistance determine the speed of the ball when it is at a height y above the ground. b) Determine the speed of the ball at y if it had initial speed v i at the time of release at the original height h. mgmg h m y m Using the principle of mechanical energy conservation Again using the principle of mechanical energy conservation but with non-zero initial kinetic energy!!! This result looks suspiciously like one of our kinematic equations. Why not, it is motion under constant acceleration! PEKE mgh mgy 0 0 mv 2 /2 mv i 2 /2 mv f 2 /2

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt You are getting very sleepy… mgh Pendulum Example A ball of mass m is attached to a light cord of length L, making up a pendulum. The ball is released from rest when the cord makes an angle A A with the vertical, and the pivoting point P is frictionless. Find the speed of the ball when it is at the lowest point, B. b) Determine tension T at the point B. Using the principle of mechanical energy conservation Using Newton’s 2 nd law of motion and recalling the centripetal acceleration of a circular motion Cross check the result in a simple situation. What happens when the initial angle  A is 0? Compute the potential energy at the maximum height, h.h. Remember where the 0 is. mgmg m m AA L T h{ PE 0 KE 0 mv 2 /2 B mgmg T

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Work Done by Liberal Forces Mechanical energy of a system is not conserved when any one of the forces in the system is a non-conservative (dissipative) force. Two kinds of non-conservative forces: Applied forces: Forces that are external to the system. These forces can take away or add energy to the system. So the mechanical energy of the system is no longer conserved. If you were to hit a free falling ball, the force you apply to the ball is external to the system of ball and the Earth. Therefore, you add kinetic energy to the ball-Earth system. Kinetic Friction: Internal non-conservative force that causes irreversible transformation of energy. The friction force causes the kinetic and potential energy to transfer to internal energy Work Done by Non-conservative Forces

Wednesday June 15, PHYS , Summer I 2005 Dr. Andrew Brandt Example of Non-Conservative Force What does this mean in this problem? Don’t we need to know mass? Compute the speed at the bottom of the hill, using mechanical energy conservation on the hill, before friction starts working at the bottom of the hill h=20.0m  =20 o The change of kinetic energy is the same as the work done by kinetic friction. Since we are interested in the distance the skier can get to before stopping, the friction must do work equivalent to the available kinetic energy. Since Well, it turns out we don’t need to know mass. What does this mean? No matter how heavy the skier is he will get as far as anyone else has gotten. A skier starts from rest at the top of a frictionless hill with a vertical height 20.0 m and an inclination angle of 20 o. Determine how far the skier can go horizontally after he reaches the bottom of the hill if the coefficient of kinetic friction between the skis and the snow is