Chemistry Chapter 12 Review Game

Balancing Chemical Equations Stoich #1 (easy) Stoich #2 (more difficult) % Yield 1 point 1 point 1 point 1 point 1 point 1 point 1 point 1 point 2 points 2 points 2 points 2 points 2 points 2 points 2 points 2 points 3 points 3 points 3 points 3 points 3 points 3 points 3 points 3 points 4 points 4 points 4 points 4 points 4 points 4 points 4 points 4 points 5 points 5 points 5 points 5 points 5 points 5 points 5 points 5 points

Calcium carbonate reacts with phosphoric acid to produce calcium phosphate, carbon dioxide and water. 1 pointCheck

What is… 3 CaCO H 3 PO 4  Ca 3 (PO4) CO H 2 O? 1 point Back to Category Slide

Iron (III) sulfide reacts with oxygen to form iron (III) oxide and sulfur dioxide. 2 pointsCheck

What is… 4 FeS O 2  2 Fe 2 O SO 2 ? 2 points Back to Category Slide

Ammonium nitrate decomposes to nitrogen, water and oxygen. 3 pointsCheck

What is… 2 NH 4 NO 3  2 N H 2 O + O 2 ? 3 points Back to Category Slide

Manganese oxide reacts with potassium hydroxide, oxygen and chlorine to form potassium permanganate, potassium chloride and water. 4 pointsCheck

What is … 2 MnO KOH + O 2 + Cl 2  2 KMnO KCl + 2 H 2 O? 4 points Back to Category Slide

Nitric acid and zinc react to form zinc nitrate, ammonium nitrate and water. 5 pointsCheck

5 points Back to Category Slide What is… 4 Zn + 10 HNO 3  4 Zn(NO 3 ) 2 + NH 4 NO H 2 O?

This allows you to convert from substance A to substance B. 1 pointCheck

What is mole to mole ratio? 1 point Back to Category Slide

N H 2  2 NH 3 The number of moles of H 2 I started with if I have 4.8 mol of ammonia 2 pointsCheck

What is 7.2 mol of H 2 ? 2 points Back to Category Slide

N H 2  2 NH 3 The number of H atoms in ammonia if I have 28.3 grams of H 2. 3 pointsCheck

What is 1.70 x H atoms? 3 points Back to Category Slide

N H 2  2 NH g of ammonia are produced. The volume of nitrogen gas (assume STP). 4 pointsCheck

What is 15.7 liters of N 2 ? 4 points Back to Category Slide

N H 2  2 NH 3 I have 140,000 H atoms. The number of ammonia molecules I can produce with excess nitrogen. 5 pointsCheck

What is 47,000 ammonia molecules? 5 points Back to Category Slide

Use the following equation for #’s C 2 H O 2  4 CO H 2 O 1 pointCheck

Use the following equation for #’s C 2 H O 2  4 CO H 2 O 1 point Back to Category Slide

2.0 g of acetylene react with 6.0 g of oxygen. This is my limiting reactant. 2 pointsCheck

What is oxygen? 2 points Back to Category Slide

The number of grams of water that are produced when 2.0 g of C 2 H 2 react with 6.0 g of O 2. 3 pointsCheck

3 points Back to Category Slide What is 1.4 grams of water?

The number of acetylene molecules we started with if we produced 28.7 g of CO 2. 4 pointsCheck

4 points Back to Category Slide What is 1.96 x molecules of C 2 H 2 ?

1,500 mL of acetylene react with excess oxygen. The number of liters of carbon dioxide that are produced. 5 pointsCheck

What is 3.0 liters of carbon dioxide? 5 points Back to Category Slide

The formula for % yield. 1 pointCheck

What is… (Actual / Theoretical) x 100? 1 point Back to Category Slide

If 15.0 g of nitrogen reacts with 15.0 g of hydgrogen, 10.5 g of ammonia is produced. The percent yield of this reaction. 2 pointsCheck

What is 57.7%? 2 points Back to Category Slide

Three reasons % yield can’t be more than 100%. 3 pointsCheck

What is impure reactants, competing side reactions, and human error? 3 points Back to Category Slide

The % yield when a test yields 12.3 mg of product A. According to the book, it should have yielded dg. 4 pointsCheck

What is 92.5%? 4 points Back to Category Slide

The amount of product that needs to be made in a lab with a 95.5% yield. Assume a theoretical yield of 23.9 grams. 5 pointsCheck

What is 22.8 grams? (actual) 5 points Back to Category Slide