Copyright © Cengage Learning. All rights reserved. 11 Analytic Geometry in Three Dimensions
Copyright © Cengage Learning. All rights reserved. The Cross Product of Two Vectors 11.3
3 Find cross products of vectors in space. Use geometric properties of cross products of vectors in space. Use triple scalar products to find volumes of parallelepipeds. Objectives
4 The Cross Product
5 Many applications in physics, engineering, and geometry involve finding a vector in space that is orthogonal to two given vectors. In this section, you will study a product that will yield such a vector. It is called the cross product, and it is conveniently defined and calculated using the standard unit vector form.
6 The Cross Product It is important to note that this definition applies only to three-dimensional vectors. The cross product is not defined for two-dimensional vectors. A convenient way to calculate u v is to use the following determinant form with cofactor expansion. (This 3 3 determinant form is used simply to help remember the formula for the cross product—it is technically not a determinant because the entries of the corresponding matrix are not all real numbers.)
7 The Cross Product
8 Note the minus sign in front of the j-component. Note that each of the three 2 2 determinants can be evaluated by using the following pattern.
9 Example 1 – Finding Cross Products Given u = i + 2j + k and v = 3i + j + 2k, find each cross product. a. u v b. v u c. v v Solution: a.
10 Example 1 – Solution b. cont’d
11 Example 1 – Solution Note that this result is the negative of that in part (a). c. cont’d
12 The Cross Product The results obtained in Example 1 suggest some interesting algebraic properties of the cross product. For instance, u v = –(v u) and v v = 0.
13 The Cross Product These properties, and several others, are summarized in the following list.
14 Geometric Properties of the Cross Product
15 Geometric Properties of the Cross Product The first property, u v = –(v u) indicates that the cross product is not commutative. In particular, this property indicates that the vectors u v and v u have equal lengths but opposite directions.
16 Geometric Properties of the Cross Product The following list gives some other geometric properties of the cross product of two vectors.
17 Geometric Properties of the Cross Product Both u v and v u are perpendicular to the plane determined by u and v. One way to remember the orientations of the vectors u, v, and u v is to compare them with the unit vectors i, j, and k = i j, respectively, as shown in Figure The three vectors u, v, and u v form a right-handed system. Figure 11.13
18 Example 2 – Using the Cross Product Find a unit vector that is orthogonal to both u = 3i – 4j + k and v = –3i + 6j. Solution: The cross product u v, as shown in Figure 11.14, is orthogonal to both u and v. Figure 11.14
19 Example 2 – Solution Because a unit vector orthogonal to both u and v is. cont’d
20 Geometric Properties of the Cross Product In Example 2, note that you could have used the cross product v u to form a unit vector that is orthogonal to both u and v. With that choice, you would have obtained the negative of the unit vector found in the example. The fourth geometric property of the cross product states that || u v || is the area of the parallelogram that has u and v as adjacent sides. It follows that the area of a triangle having vectors u and v as adjacent sides is || u v ||.
21 The Triple Scalar Product
22 The Triple Scalar Product
23 The Triple Scalar Product When the vectors u, v, and w do not lie in the same plane, the triple scalar product u (v w) determines the volume of a parallelepiped (a polyhedron, where all faces are parallelograms) with u, v, and w as adjacent edges, as shown in Figure Area of base = ||v w|| Volume of parallelepiped =| u (v w)| Figure 11.17
24 The Triple Scalar Product
25 Example 5 – Volume by the Triple Scalar Product Find the volume of the parallelepiped having u, v, and w as adjacent edges, as shown in Figure Figure 11.18
26 Example 5 – Solution The value of the triple scalar product is
27 Example 5 – Solution So, the volume of the parallelepiped is. cont’d