Heating curves and  H temperature added energy

Heating curves and  H temperature added energy solidliquidgas

Heating curves and  H temperature added energy melting/ freezing pt solidliquidgas

Heating curves and  H temperature added energy melting/ freezing pt boiling/ cond. pt solidliquidgas

Heating curves and  H temperature added energy melting/ freezing pt boiling/ cond. pt solidliquidgas melting/freezing occurring here boiling/condensing occurring here

How is the total enthalpy change (  H) calculated for a substance whose temperature change includes a change in state?

temperature added energy  t of solid absorbing energy

temperature added energy  = m x C solid x  t

temperature added energy  = m x C solid x  t the energy absorbed as a solid melts becomes potential energy, so no  t

temperature added energy  H =  H fus x # mols  = m x C solid x  t

temperature added energy  H =  H fus x # mols  t of liquid absorbing energy  = m x C solid x  t

temperature added energy  H =  H fus x # mols  = m x C liquid x  t  = m x C solid x  t

temperature added energy  H =  H fus x # mols the energy absorbed as a liquid boils becomes potential energy, so no  t  = m x C liquid x  t  = m x C solid x  t

temperature added energy  H =  H fus x # mols  H =  H vap x # mols  = m x C liquid x  t  = m x C solid x  t

temperature added energy  H =  H fus x # mols  H =  H vap x # mols  t of gas absorbing energy  = m x C liquid x  t  = m x C solid x  t

temperature added energy  H =  H fus x # mols  H =  H vap x # mols  = m x C gas x  t  = m x C liquid x  t  = m x C solid x  t

temperature added energy  H =  H fus x # mols  H =  H vap x # mols  = m x C gas x  t  = m x C liquid x  t  = m x C solid x  t

temperature added energy  H =  H fus x # mols  H =  H vap x # mols  = m x C gas x  t  = m x C liquid x  t  = m x C solid x  t The  H of any substance being heated will be the sum of the  H of any  t occurring plus  H of any phase change occurring

temperature added energy  =  H fus x # mols  =  H vap x # mols  = m x C gas x  t  = m x C liquid x  t  = m x C solid x  t The  H of any substance being heated will be the sum of the  H of any  t occurring plus  H of any phase change occurring

temperature added energy  H =  H fus x # mols  H =  H vap x # mols  = m x C gas x  t  = m x C liquid x  t  = m x C solid x  t EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C?

temperature added energy -20 o C 0 o C 50 o C EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C?

temperature added energy EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? -20 o C 0 o C 50 o C use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C

temperature added energy -20 o C 0 o C 50 o C  H  =  H fus x # mols   = m x C liquid x  t   = m x C solid x  t EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C

temperature added energy -20 o C 0 o C 50 o C  H  =  H fus x # mols   = 10g x 2.1 J/g o C x 20 o C EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C   = m x C liquid x  t

temperature added energy -20 o C 0 o C 50 o C  H  =10 g x 1mol/18g x 6.01kJ/mol   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C   = m x C liquid x  t

temperature added energy -20 o C 0 o C 50 o C   = 10g x J/g o C x 50 o C   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C

temperature added energy -20 o C 0 o C 50 o C   = 10g x J/g o C x 50 o C   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C total  H =   +  H 2 +  

temperature added energy -20 o C 0 o C 50 o C   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C total  H =   +  H 2 +   = 420 J J J   = 10g x J/g o C x 50 o C

temperature added energy -20 o C 0 o C 50 o C   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c,  H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = J/g o C total  H =   +  H 2 +   5853 J = 420 J J J   = 10g x J/g o C x 50 o C

temperature added energy -20 o C 0 o C 50 o C   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? It takes 5853 joules to heat up 10 grams of water from -20 o C to +50 o C.   = 10g x J/g o C x 50 o C

temperature added energy -20 o C 0 o C 50 o C   = 10g x 2.1 J/g o C x 20 o C  H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? It takes 5853 joules to heat up 10 grams of water from -20 o C to +50 o C.   = 10g x J/g o C x 50 o C

temperature added energy -20 o C 0 o C 50 o C EXAMPLE : What is  H for 10 g water with a total  t from -20 o C to +50 o C? It takes 5853 joules to heat up 10 grams of water from -20 o C to +50 o C J