(C) Adding a nonvolatile solute to a solvent increases the solution’s osmotic pressure. Osmosis is the net movement of solvent away from a soln. w /a lower.

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Presentation transcript:

(C) Adding a nonvolatile solute to a solvent increases the solution’s osmotic pressure. Osmosis is the net movement of solvent away from a soln. w /a lower solute [ ] toward a soln. w /a higher solute [ ]. Another way to say this is that osmosis is the diffusion of a solvent – i.e., from an area of higher solvent [ ] to an area of lower solvent [ ] – through a semipermeable membrane. more conc. (in terms of solute) = higher osmotic pres. Dialysis tubing used with various sugar solns.

prevents flow osmotic pressure,  : the external pressure req’d to prevent osmosis Solvent A (pure solvent) Solution B (mixture)  solvent tends to flow ; application of   “  ” A soln’s osmotic pressure cc an be thought of as a negative pressure; that is, the greater a soln’s , the greater is the tendency for solvent to flow _____ the solution. INTO  

hypertonic solns: large  ; “conc.” (in terms of solute) hypotonic solns: small  ; “dilute” (in terms of solute)

hypertonichypotonic dil. in H 2 Oconc. in H 2 O conc. in saltdil. in salt net H 2 O flow semipermeable membrane

Reverse osmosis is the process of applying a pressure (P >  ) such that solvent is forced to flow (“against its will”) from low solvent conc. to high solvent conc. Reverse osmosis is sometimes used in the desalination (or purification) of water.

osmotic pressure equation: n = # of moles of particles V = solution volume, in L R = L-kPa/mol-K = L-atm/mol-K T = absolute temp. (i.e., in K) i = van’t Hoff factor An early form of the osmotic pressure equation was proposed by van’t Hoff. The equation was improved to its current form by Harmon Northrop Morse, an American chemist who lived from 1848 to  V = n R T i

X = 1200 g/mol 1.5 mg of a certain protein are dissolved in water to make 10.0 mL of soln. The soln’s osmotic pressure was found to be 2.35 torr at 25 o C. Calculate the protein’s molar mass kPa 298 K = x 10 –6 mol