Lesson 6-7 Pages 298-302 Using Percent Equations Lesson Check 6-6.

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Presentation transcript:

Lesson 6-7 Pages Using Percent Equations Lesson Check 6-6

What you will learn! 1. How to solve percent problems using percent equations. 2. How to solve real-life problems involving discount and interest.

Percent equation Discount Simple interest

What you really need to know! In a percent equation, the percent is written as a decimal.

What you really need to know! % of BASE = PART The word “ of ” means multiply!

What you really need to know! The number after the word “of” is the base! The number near the word “is” is the part!

Example 1: Find 38% of 22. % x BASE = PART 38% x 22 = PART 0.38 x 22 = PART 8.36 = PART

Example 2: 19 is what percent of 25? % x BASE = PART % x 25 = 19 % = 19 ÷ 25 % = %

Example 3: 84 is 16% of what number? % x BASE = PART 16% x BASE = x BASE = 84 BASE = 84 ÷ 0.16BASE = 525

Example 4: The regular price of a ring is $495. It is on sale at a 20% discount. What is the sale price of the ring? 20% x $495 = $99 $495 - $99 = $396

Example 5: Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495? I = prt

I is interest p is principal r is annual interest rate t is time in years

Example 5: Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495? 495 = 2, t 5.5 years = t

Page 300 Guided Practice #’s 4-11

Pages with someone at home and study examples! Read:

Homework: Pages #’s even #’s Lesson Check 6-7

Page 738 Lesson 6-7

Lesson Check 6-7