Solving Multistep Equations 2x + 4 = 12. Method 1 : Algebra tiles You should have a basic understanding of Algebra Tiles to use this tutorial. The Legal.

Slides:



Advertisements
Similar presentations
1.7 and 1.8 Solving one step equations with algebra tiles
Advertisements

Solving Equations with the Variable on Both Sides Objectives: to solve equations with the variable on both sides.
Solving Linear Equations
Solving Equations Please view this tutorial and answer the follow-up questions on loose leaf to turn in to your teacher.
Solving Equations with the Variable on Both Sides
Solve an equation with variables on both sides
Previously, we learned that adding two numbers together which have the same absolute value but are opposite in sign results in a value of zero. This can.
5-3 Elimination Using Addition and Subtraction
Solving Equations. Equations contain an equal sign (or inequality) and at least one variable.
Standardized Test Practice
EXAMPLE 1 Collecting Like Terms x + 2 = 3x x + 2 –x = 3x – x 2 = 2x 1 = x Original equation Subtract x from each side. Divide both sides by x2x.
Standardized Test Practice
Equations & Brackets.. You are now going to solve more complex equations by combining together two ideas that you have seen already. Try the following.
Introduction Two equations that are solved together are called systems of equations. The solution to a system of equations is the point or points that.
Standardized Test Practice
Tonight’s Homework: 6-6: (page 456) (evens): 4 – 18, 24, 28, 32 – 38, 46, 50, 58 (17 points) (17 points)
Solving Equations. A quadratic equation is an equation equivalent to one of the form Where a, b, and c are real numbers and a  0 To solve a quadratic.
ALGEBRA LESSON 3 – SOLVING ONE-STEP ADDITION/SUBTRACTION EQUATIONS.
1.4 Solving Equations ●A variable is a letter which represents an unknown number. Any letter can be used as a variable. ●An algebraic expression contains.
Solve a logarithmic equation
EXAMPLE 4 Solve a logarithmic equation Solve log (4x – 7) = log (x + 5). 5 5 log (4x – 7) = log (x + 5) x – 7 = x x – 7 = 5 3x = 12 x = 4 Write.
Solving Equations. The equations are equivalent If they have the same solution(s)
Lesson 3-4 Solving Multi-Step Inequalities August 20, 2014.
Rational Equations Section 8-6.
3.2 Solving Equations by Using Addition and Subtraction Addition Property of Equality –If the same number is added to each side of an equation, the resulting.
Dr. Fowler CCM Solving Systems of Equations By Substitution – Harder.
Multi-Step Equations Sol A.4. To solve multi-step equations you form a series of simpler equivalent equations. To do this use the properties of equality,
Lesson 2 Contents Example 1Solve a Two-Step Equation Example 2Solve Two-Step Equations Example 3Solve Two-Step Equations Example 4Equations with Negative.
ALGEBRA READINESS LESSON 9-2 Warm Up Lesson 9-2 Warm-Up.
ALGEBRA READINESS LESSON 9-2 Warm Up Lesson 9-2 Warm-Up.
Solve an equation 7y – 6y + 12 = 4y. Simplify 7y – 6y + 12 = 4y 7y – 6y + 12 = 4y becomes y + 12 = 4y when we combine like terms.
Solving Linear Equations Substitution. Find the common solution for the system y = 3x + 1 y = x + 5 There are 4 steps to this process Step 1:Substitute.
Warm Up Solve. 1. 3x = = z – 100 = w = 98.6 x = 34 y = 225 z = 121 w = 19.5 y 15.
Use the substitution method
Two Step Equation 2x + 6 = x = x = 5.
Solving Equations Unit 5 Lesson 1. Solving Equations The development of the equation solving model is based on two ideas. 1.Variables can be isolated.
Solve inequalities that contain more than one operation.
ALGEBRA TILES SOLVING EQUATIONS Replace the equation with tiles: Negative Positive -X X 1.
CONFIDENTIAL 1 Algebra I Solving Equations by Adding or Subtracting.
Modelling Equations with Algebra Tiles Jostie & The Dangers of Algebra.
Chapter 7.3.  Objective NCSCOS 4.03  Students will know how to solve a system of equations using addition.
ALGEBRA 1 Lesson 6-2 Warm-Up. ALGEBRA 1 “Solving Systems Using Substitution” (6-2) How do you use the substitution method to find a solution for a system.
One-Step Equations Rewriting Equations Symmetric Property- allows you to completely switch both sides of an equation Inverse Operations + -- x Solving-
CONFIDENTIAL 1 Grade 8 Pre-Algebra Solving Equations with Variables on Both Sides.
Solving Equations: More Than One Step The algebra tiles show the equation 2x –3 = 5 = When you solve equations, the object is to get the variable alone,
Solving Equations with Variables on Both Sides. Review O Suppose you want to solve -4m m = -3 What would you do as your first step? Explain.
Adapted by Mrs. Garay. Warm Up Solve. 1. 2x + 9x – 3x + 8 = – 4 = 6x + 22 – 4x 3. + = 5 4. – = 3 x = 1 x = –13 x = x x9x 16 2x2x 4.
§ 2.3 Solving Linear Equations. Martin-Gay, Beginning and Intermediate Algebra, 4ed 22 Solving Linear Equations Solving Linear Equations in One Variable.
Solving Multistep Linear Equations Using Algebra Tiles
Solving Multistep Equations
Solving Equations with the Variable on Each Side
Using Algebra Tiles to Solve Equations, Combine Like Terms, and use the Distributive Property Objective: To understand the different parts of an equation,
Making Algebra Play.
Introduction Two equations that are solved together are called systems of equations. The solution to a system of equations is the point or points that.
Objective Solve equations in one variable that contain variable terms on both sides.
2-4 Solving Multi-Step Equations
Solve an equation by combining like terms
EXAMPLE 4 Standardized Test Practice SOLUTION
Subtracting Integers with Tiles
Solving Two-Step Equations
5x + 3x + 2 = 20 Bellwork #1 of 2 a.) combine the x terms
Solving Equations by Adding and Subtracting Solving Equations
Substitution method y= 3x+1 5x + 2 y =13 Solve:
Objective Solve equations in one variable that contain variable terms on both sides.
Solving Equations by 2-1 Adding or Subtracting Warm Up
Definition of logarithm
EXAMPLE 4 Solve proportions Solve the proportion. ALGEBRA a x 16
How to Solve Linear Equations
Skill Check Lesson Presentation Lesson Quiz.
Presentation transcript:

Solving Multistep Equations 2x + 4 = 12

Method 1 : Algebra tiles You should have a basic understanding of Algebra Tiles to use this tutorial. The Legal Moves are the set of moves allowed. Let’s review the Legal Moves.

Method 1 : Algebra tiles Legal Moves 1. Removing Zero Pairs

Removing Zero Pairs ++ --

++ --

Method 1 : Algebra tiles Legal Moves 1. Removing Zero Pairs 2. Flipping Tiles

Flipping Tiles

Method 1 : Algebra tiles Legal Moves 1. Removing Zero Pairs 2. Flipping Tiles 3. Dividing into groups

Dividing into Groups x = -6 x = -2

Are you ready for an Example?

Putting it all Together Let’s Start with a basic equation: 4x – 7 = 9 4x – 7 =

Putting it all Together Flip up tiles in the (-) region: 4x – 7 = 9 4x – 7 =

Putting it all Together Flip unit tiles away from the region with the x-tiles: 4x = 16 4x =

Putting it all Together Arrange unit tiles into four equal groups since there are 4 x-tiles:x = 4 4x = 16 4x =

Putting it all Together x = 4 is the correct answer!!! ++ --

CHECK YOUR ANSWER Plug x = 4 into the original equation 4x – 7 = 9 4(4) - 7 = 9 16 – 7 = 9 9 = 9 Since the statement is true then 4 is a solution!!!

Another Example?

Example 2 Let’s Start with an advanced equation: 2(3 – 2x) = 4 + (-2x) – 10 2(3 – 2x) = 4 + (-2x) –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Flip up: 6 – 4x = 4 - 2x – 10 6 – 4x = 4 - 2x –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Flip up: 6 – 4x = 4 - 2x – 10 6 – 4x = 4 - 2x –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Remove Zero Pairs: 6 – 4x = - 2x – 6 6 – 4x = - 2x –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Remove more Zero Pairs: 6 – 2x = – 6 6 – 2x = –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Flip red x-tiles to the other side: 6 = 2x – 6 6 = 2x –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Flip red x-tiles to the other side: 6 = 2x – 6 6 = 2x –

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Flip unit tiles away from the x-tiles: 12 = 2x 12 = 2x ++ --

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Flip unit tiles away from the x-tiles: 12 = 2x 12 = 2x ++ --

Example 2 2(3 – 2x) = 4 + (-2x) – 10 Arrange tiles into 2 group since there are 2 x-tiles: 6 = x 6 = x ++ --

Example 2 2(3 – 2x) = 4 + (-2x) – 10 x = 6 is the correct answer!!! ++ --

CHECK YOUR ANSWER Plug x = 6 into the original equation 2(3 – 2x) = 4 + (-2x) – 10 2(3 – 2(6)) = 4 + (-2(6)) – 10 2(3 – 12) = 4 + (-12) – 10 2(-9) = - 8 – = - 18 Since the statement is true then 6 is a solution!!!

Method 2 : Solve using a Table

Using a Table Let’s solve the equation: 5x – 3(x – 2) = -2x - 4 EQUATIONREASON 5x – 3(x – 2) = -2x – 4 Original Equation 5x – 3x + 6 = -2x – 4Distributive Property 2x + 6 = -2x – 4Combined like terms 4x + 6 = -4(Flipped -2x) Added 2x to both sides 4x = -10(flipped 6) Subtracted 6 from both sides x = - 2.5Divided both sides by 4

CHECK YOUR ANSWER Plug x = -2.5 into the original equation 5x – 3(x – 2) = -2x - 4 5(-2.5) – 3(-2.5 – 2) = -2(-2.5) – – 3(-4.5) = 5 – = 1 1 = 1 Since the statement is true then -2.5 is a solution!!!

Give it a try!!! You should be ready to give it a try on your own. Locate the Checkpoint 1 – Worksheet from the Geometry Page on School Fusion, Print it, show all work, and turn it in to your teacher. Once the worksheet is 100% correct then you will be eligible to retake the Checkpoint 1 – Quiz!!!