Electrostatics – Coulomb’s Law. Tues / Wed Read Chapter 20 pp. 461-470 Homework: p. 477 1-3, 9-12 Wed/Thurs Do problems p. 478 20, 21, 22, 24, 25, 27.

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Electrostatics – Coulomb’s Law

Tues / Wed Read Chapter 20 pp Homework: p , 9-12 Wed/Thurs Do problems p , 21, 22, 24, 25, 27 Thurs/Fri p , 29, 30, 31, 32 Thurs / Fri Lab Fri / Mon Homework: Read ch 21 pages Do p , 24, 26, 27, 28, 30, 31 Mon / Tues Homework: Read Do 32, 33, 34, 42, 43, 47

Coulomb’s Law __ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ Charles Coulomb discovered that the repulsive force due to similar charges or the attractive force of dissimilar charges was inversely proportional to the square of the distance between the two charged bodies. r F  1/r 2

Coulomb’s Law Coulomb further discovered that the force was proportional to the product of the charge on each of the objects __ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ F  q 1 q 2 q2q2 q1q1 Sphere 1Sphere 2

Coulomb’s Law F = kq 1 q 2 r 2 Where: k = 8.99 x 10 9 Nm 2 /C 2 q 1, q 2 = the charge of each sphere in Coulombs. r = the distance between the two charged bodies. Applet 1 - Coulomb's Law Applet II - Coulomb's Law

Example 1: Where: k = 8.99 x 10 9 Nm 2 /C 2 q 1, q 2 = the charge of each sphere in Coulombs. r = the distance between the two charged bodies. Two point charges, q1 = 1C q2 = 2C are separated by 1 m. What is the force between them? F = kq 1 q 2 / r 2 = (8.99E9N*m 2 /C 2 )(1C)(2C)/(1m) 2 = 1.8E10N

Example 2: Where: k = 8.99 x 10 9 Nm 2 /C 2 q 1, q 2 = the charge of each sphere in Coulombs. r = the distance between the two charged bodies. Two point charges, q1 = 1C q2 = -2C are separated by 1 m. What is the force between them? F = kq 1 q 2 / r 2 = (8.99E9N*m 2 /C 2 )(1C)(2C)/(1m) 2 = -1.8E10N

Example 3: Where: k = 8.99 x 10 9 Nm 2 /C 2 q 1, q 2 = the charge of each sphere in Coulombs. r = the distance between the two charged bodies. Two point charges, q1 = 1E-19C q2 = -2E-19C are separated by 1E-10 m. What is the force between them? F = kq 1 q 2 / r 2 = (8.99E9N*m 2 /C 2 )(1E-19C)(-2E-19C)/(1E-10m) 2 = E-8N

Example 4: Where: k = 8.99 x 10 9 Nm 2 /C 2 q 1, q 2 = the charge of each sphere in Coulombs. r = the distance between the two charged bodies. At what distance does the electrostatic force between two protons equal 899N? F = kq 1 q 2 / r 2  kq 1 q 2 / F = r 2 (8.99E9)(1.6E-19) 2 / 899 = (2.56E-31)  r= 5.05E-16

Graphs (oh, no, not again.) Graph of F vs. r? Graph of F vs. q 1 q 2 ?

Key Ideas Like charges repel. The electrostatic force is proportional to the charge on the two objects and inversely proportional to the square of the distance between them.