 Objectives:  Students will apply proportions with a triangle or parallel lines.  Why?, So you can use perspective drawings, as seen in EX 28  Mastery.

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Presentation transcript:

 Objectives:  Students will apply proportions with a triangle or parallel lines.  Why?, So you can use perspective drawings, as seen in EX 28  Mastery is 80% or better on 5-minute checks and independent practice.

 In this lesson, you will study four proportionality theorems. Similar triangles are used to prove each theorem.

If a line parallel to one side of a triangle intersects the other two sides, then it divides the two side proportionally. If TU ║ QS, then RT TQ RU US =

If a line divides two sides of a triangle proportionally, then it is parallel to the third side. RT TQ RU US = If, then TU ║ QS.

 In the diagram AB ║ ED, BD = 8, DC = 4, and AE = 12. What is the length of EC?

 So, the length of EC is 6.

 Given the diagram, determine whether MN ║ GH. LM MG = 8 3 = LN NH = 3 1 = ≠ MN is not parallel to GH.

 If three parallel lines intersect two transversals, then they divide the transversals proportionally.  If r ║ s and s║ t and l and m intersect, r, s, and t, then UW WY VX XZ =

 If a ray bisects an angle of a triangle, then it divides the opposite side into segments whose lengths are proportional to the lengths of the other two sides.  If CD bisects  ACB, then AD DB CA CB =

 In the diagram  1   2   3, and PQ = 9, QR = 15, and ST = 11. What is the length of TU?

PQ QR ST TU = TU = 9 ● TU = 15 ● 11 Cross Product property 15(11) = TU = Parallel lines divide transversals proportionally. Substitute Divide each side by 9 and simplify.  So, the length of TU is 55/3 or 18 1/3.

 In the diagram,  CAD   DAB. Use the given side lengths to find the length of DC.

Since AD is an angle bisector of  CAB, you can apply Theorem 8.7. Let x = DC. Then BD = 14 – x. AB AC BD DC = X X = Apply Thm. 8.7 Substitute.

9 ● x = 15 (14 – x) 9x = 210 – 15x 24x= 210 x= 8.75 Cross product property Distributive Property Add 15x to each side Divide each side by 24.  So, the length of DC is 8.75 units.

 Example 5: Finding the length of a segment  Building Construction: You are insulating your attic, as shown. The vertical 2 x 4 studs are evenly spaced. Explain why the diagonal cuts at the tops of the strips of insulation should have the same length.

 Because the studs AD, BE and CF are each vertical, you know they are parallel to each other. Using Theorem 8.6, you can conclude that DE EF AB BC = Because the studs are evenly spaced, you know that DE = EF. So you can conclude that AB = BC, which means that the diagonal cuts at the tops of the strips have the same lengths.

 In the diagram KL ║ MN. Find the values of the variables.

 To find the value of x, you can set up a proportion x x = 13.5(37.5 – x) = 9x – 13.5x = 9x = 22.5 x 22.5 = x Write the proportion Cross product property Distributive property Add 13.5x to each side. Divide each side by 22.5  Since KL ║MN, ∆JKL ~ ∆JMN and JK JM KL MN =

 To find the value of y, you can set up a proportion y = 9y = 7.5(22.5) y = Write the proportion Cross product property Divide each side by 9.

 What was the objective for today?  Students will apply proportions with a triangle or parallel lines.  Why?, So you can use perspective drawings, as seen in EX 28  Mastery is 80% or better on 5-minute checks and independent practice.

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