Completely unpolarized horizontally traveling light of intensity I 0 is normally incident on a vertical polarizer. The light that gets through is then.

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Presentation transcript:

Completely unpolarized horizontally traveling light of intensity I 0 is normally incident on a vertical polarizer. The light that gets through is then normally incident on a horizontal polarizer. How does the intensity I 2 of the light that gets through both polarizers compare with I 0 ? a) I 2 = 0 b) I 2 = 0.25 I 0 c) I 2 = 0.5 I 0 d) I 2 = I 0 e) None of the above.

Completely unpolarized, horizontally-traveling light is normally incident on an ideal polarizer whose polarization direction makes an angle of 25  with the vertical. How does the intensity I 1 of the light that gets through the polarizer compare with the intensity I 0 of the incident light? a) I 1 = I 0 b) I 1 = I 0 cos 25  c) I 1 = I 0 (cos 25  ) 2 d) I 1 = 0.5 I 0 e) None of the above

Completely horizontally-polarized, horizontally- traveling light is normally incident on an ideal polarizer whose polarization direction makes an angle of 25  with the vertical. How does the intensity I 1 of the light that gets through the polarizer compare with the intensity I 0 of the incident light? a) I 1 = I 0 b) I 1 = I 0 cos 25  c) I 1 = I 0 (cos 25  ) 2 d) I 1 = 0.5 I 0 e) None of the above

In an ongoing two-slit interference experiment involving initially unpolarized light, one slit is covered with a horizontal polarizer and the other with a vertical polarizer. What happens to the pattern of light on the screen? a)Both the interference pattern and the diffraction pattern go away. You see a bright dot on the screen, of the same shape as you get with no obstruction, but, of lesser brightness. b)The diffraction pattern goes away but the interference pattern remains. c)The interference pattern goes away but the diffraction pattern remains.

Unpolarized light of intensity I 0 passes through an ideal vertical polarizer giving it an intensity I 1 and then an ideal polarizer at 15  with respect to the vertical giving it an intensity I 2. In a separate experiment, vertically polarized light of the same intensity I 0 passes through the same two polarizers yielding I 1 and I 2 respectively. How does I 2 compare to I 2 ? a) I 2 = I 2 b) I 2 = 2 I 2 c) I 2 =.5 I 2 d) None of the above

What is the appropriate polarization direction for polarized sunglasses? a) Horizontal b) Vertical

Completely unpolarized horizontally traveling light of intensity I 0 is normally incident on a vertical polarizer. The light that gets through is then normally incident on a second, and then a third polarizer. The polarization direction of the 3 rd polarizer is horizontal. Does the intensity of the light, if any, that makes it through all three polarizers depend on the polarization direction of the second polarizer? a) Yes b) No, because none makes it through all three polarizers.

Completely unpolarized light of intensity I is normally incident upon a polarizer. The light passing through that polarizer is then normally incident upon a second polarizer. What is the maximum possible value of the intensity of the light that makes it through the second polarizer? a) I / 4 b) I / 2 c) I d) 2 I e) 4 I

In the expression I = I o [cos(  )] 2, the angle  is the angle between what and what? a) The polarization direction of the first polarizer and the polarization direction of the second polarizer. b) The polarization direction of the light and the polarization direction of the polarizer. c) The direction in which the light is traveling and the direction of polarization of the light. d) The polarization direction that the polarizer makes with the vertical. e) The direction of polarization of the polarizer and the horizontal.

The expression I = I o [cos(  )] 2 relates the intensity of what to the intensity of what? a) The intensity I o of any light incident on a polarizer to the intensity of the light that gets through the polarizer. b) The intensity I o of completely unpolarized light incident on a polarizer to the intensity of the light that gets through the polarizer. c) The intensity I o of polarized light incident on a polarizer to the intensity of the light that gets through the polarizer. d) The intensity I o of light incident on a mirror to the intensity of the light reflected from that mirror.

Given that the light given off by the sun is completely unpolarized, what is the point of polarized sunglasses? a) Sunlight is horizontally polarized when it undergoes specular reflection (as light reflects off a mirror), the kind of reflection that forms glare. The lenses in polarized sunglasses are oriented so that the polarization direction of the lenses is vertical. The lenses thus absorb most of the glare (and, as a side effect, half of the unpolarized light). b) The purpose is to reduce the intensity of light about to enter one's eyes to one half of its value. c) None of the above.

A physics professor has a polarizer and wants to determine the polarization direction of the polarizer so that she can draw a line on it, in the direction of polarization, for future reference. Assume that she is in a building like the Goulet Science Center on a sunny winter day. How can she determine the direction of polarization of the polarizer?

Three polarizers are lined up one behind the other. The polarization direction of the 1st polarizer is vertical. The polarization of the 3rd polarizer is horizontal. Unpolarized light approaching the polarizers along a path at right angles to the surfaces of all the polarizers hits the 1st polarizer first. What must the polarization direction of the 2nd polarizer be in order to minimize the intensity of the light that makes it through all three? a) Horizontal. b) Vertical. c) Either horizontal or vertical. d) It doesn't matter. No light makes it through all 3 for any polarization direction of the second polarizer. e) 45  with respect to the vertical. f) 45  with respect to the horizontal. g) Answers e and f are the same and both are correct.