If you draw squares on the two shorter sides…

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Presentation transcript:

If you draw squares on the two shorter sides… Pythagoras’ theorem only works on right – angled triangles … and find their area. Area A Area B

Area C Area A Area A + Area B = Area C The sum of their areas equals the area of the square on the longest side! Area B

Find the area of the smaller squares Find the length of x. Find the area of the smaller squares x 9cm2 3cm 4cm 16cm2

What will the length x be? 9cm2 Find the length of x. 25cm2 x What will the length x be? 9cm2 3cm add to find the area of the large square. x = 25 = 5cm 4cm 16cm2

Find the length of x. x x2 = 82 + 62 x2 = 64 + 36 x2 = 100 6cm x2 = 64 + 36 8cm x2 = 100 x = 100 = 10

Find the length of x. x x2 = 92 + 72 x2 = 81 + 49 x2 = 130 7cm x2 = 81 + 49 9cm x2 = 130 x = 130 = 11.4

This time we need to find the area of one of the smaller squares … Find the length of x. This time we need to find the area of one of the smaller squares … … so we need to subtract! 12cm x2 = 122 - 82 x x2 = 144 - 64 8cm x2 = 80 x = 80 = 8.9