SI unit of pressure- pascal (Pa) Standard atmospheric pressure = 101

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Presentation transcript:

SI unit of pressure- pascal (Pa) Standard atmospheric pressure = 101 SI unit of pressure- pascal (Pa) Standard atmospheric pressure = 101.3 kilopascals (kPa) 1 mm Hg = pressure needed to support a column of mercury 1 mm high Stp = 1 atm of pressure and o°C 1 atm = 760 mm Hg = 760 torr =101.3 kPa YOU MUST KNOW THESE MEASUREMENTS!

The air pressure for a certain tire is 109 kpa The air pressure for a certain tire is 109 kpa. What is this pressure in atmospheres?   109 kPa 101.3kPa 1 atm = 1.08 atm

The air pressure inside a submarine is 0. 62 atm The air pressure inside a submarine is 0.62 atm. What would be the height of a column of mercury balanced by this pressure?   0.62 atm 1 atm 760 mm Hg = 470 mm Hg

A bag of potato chips is sealed in a factory near seal level A bag of potato chips is sealed in a factory near seal level. The atmospheric pressure at the factory is 761.3 mm Hg. The pressure inside the bag is the same. What is the pressure inside the bag of potato chip in Pa?   761.3 mm Hg 760 mm Hg 1 atm 101.3 kPa 1000 Pa 1 atm 1 kPa 101500 Pa = or 1.015 x 105 Pa

Variables That Describe a Gas Compressibility – a measure of how much the volume of matter decreases under pressure. P = pressure V = volume T = temperature n = number of moles

What Happens when you add or remove gas from a container? Adding gas to a container Increases the number of particles Increases the number of collisions And thus increases the pressure in the container Removing gas from a container Decreases the number of particles Decreases the number of collisions And thus decreases the pressure

Pressure and Particles are related The number of particles of gas and pressure are directly related. double # of particles = double pressure Airing up a balloon illustrates this!

The Effect Of Changing The Size Of The Container Increase Volume  Decrease Pressure Decrease Volume  Increase Pressure Volume and Pressure are indirectly related. If you cut the volume in half, the pressure doubles.

The Effect of Heating or Cooling a Gas Compressing A Gas Increases Its Temperature. Expanding A Gas Decreases Its Temperature. Heating a Gas Increases KE Increases the number of collisions with the walls of the container Thus increasing the pressure Cooling a Gas Decreases KE Decreases the number of collisions with the walls of the container Thus decreasing the pressure

The Gas Laws

1. Boyle’s law for pressure-volume changes -for a given mass of gas at constant temperature, the volume of the gas varies inversely with pressure. P1 V1 = P2 V2 or “We Boyle Peas and Vegetables”

Example:. A gas is collected in a 242 ml container Example: A gas is collected in a 242 ml container. The pressure of the gas in the container is measured and determined to be 87.6 kpa. What is the volume of this gas at 101.3 kpa? Assume the temperature is constant. P1 = 87.6 P2 = 101.3 kPa V1 = 242 mL V2 = ? P1 V1 = P2 V2 (87.6 kPa)(242 mL) = (101.3kPa)V2 V2 = 209 mL

“Charlie Brown’s Christmas is on TV” 2. Charles’ law for temperature-volume changes The volume of a fixed mass of gas is directly proportional to its kelvin temperature if the pressure is kept constant. Temperature must be in Kelvin! V1 = V2 or V1 T2 = V2 T1 T1 T2 “Charlie Brown’s Christmas is on TV”

Example:. A sample of gas at 15oC and 1 atm has a volume of 2. 58 L Example: A sample of gas at 15oC and 1 atm has a volume of 2.58 L. What volume will this gas occupy at 38oC and 1 atm? T1 = 15oC + 273 =288K V1 = V2 T2 = 38oC + 273 = 311K T1 T2 V1 = 2.58 L V2 = ? 2.58L = V2 288K 311K V2 = 2.79L

GayLe drives a PT Cruiser! 3. Gay-lussac’s law for temperature-pressure changes The pressure of a gas is directly proportional to the kelvin temperature if the volume is kept constant. Temperature must be in kelvin! P1 = P2 or P1T2 = T1P2 T1 T2 GayLe drives a PT Cruiser!

Example: A 2.00 L flask contains helium gas at a pressure of 685 torr and a temperature of 0oC. What would be the pressure in a flask if the temperature is increased to 150.OC? P1 = 685 torr P2 =? T1 = 0oC + 273 = 273K T2 = 150.oC + 273 = 423K P1 = P2 685 torr = P2 T1 T2 273K 423K P2 = 1060 torr

Complete the following statements. Bellwork Wednesday, 1/9 Complete the following statements. When the pressure of a gas goes up, the volume… This means it is a(n) __________________ relationship. When the temperature of a gas goes up, the volume… When the temperature of a gas goes up, the pressure…

P1V1 = P2V2 T1 T2 The Combined Gas Law P1V1 = P2V2 T1 T2 “Peas and Vegetables on the Table” By canceling out terms remaining constant, we can derive Boyle’s, Charles’, and Gay-Lussac’s laws.

Ex. If a helium-filled balloon has a volume of 3. 40 L at 25 Ex. If a helium-filled balloon has a volume of 3.40 L at 25.0oC and 120.0 kPa, what is its volume at STP? V1 = 3.40L V2 = ? P1 = 120.0 kPa P2 = 1 atm = 101.3 kPa T1 = 25.0oC + 273 = 298K T2 = 0oC + 273 = 273K P1V1 = P2V2 (120.0 kPa)(3.40L) = (101.3 kPa)V2 T1 T2 298K 273K V2 = 3.69L

Bellwork Thursday Jan. 9 A sample of air has a volume of 550.0mL at 106oC. At what temperature will its volume be 700.0mL at constant pressure?

A flask contains 1. 4L of an ideal gas at 50. 0oC and 1 A flask contains 1.4L of an ideal gas at 50.0oC and 1.44atm of pressure. If the gas is compressed to 0.7L and the temperature is raised to 100.0oC what will be the new pressure in the container? V1 = 1.4 L V2 = 0.7 L P1 = 1.44 atm P2 = ? T1 = 50.0oC + 273 = 323K T2 = 100.0oC + 273 = 373K P1V1 = P2V2 (1.44 atm)(1.4L) = (P2)(0.7 L) T1 T2 323K 373K P2 = 3.3 atm or 3 atm

12.4 Real vs. Ideal Gases Ideal gas- follows the gas laws at all conditions of temperature and pressure. - Ideal gases don’t exist  Real gases can be liquefied and sometimes solidified; ideal gases can not.

Gases Behave Most Ideally At High Temperature And Low Pressure *Gases Behave Most Ideally At High Temperature And Low Pressure. (Just Like Students In The Summer!!!!!!)

The Ideal Gas Law -Allows Us To Include the Amount Of Gas (Moles) In Our Calculations. PV = Nrt “Puv Nert” P = Pressure In Atm V = Volume In L N = # Of Moles R = Ideal Gas Constant = 0.0821 (L.Atm)/(Mol.K) T = Temperature In Kelvin

Example. A 5. 0 L flask contains 0. 60 g O2 at a temperature of 22oC Example A 5.0 L flask contains 0.60 g O2 at a temperature of 22oC. What is the pressure (in atm) inside the flask? P=? V= 5.0L R = 0.0821 (L.atm/mol.K) T = 22°C +273= 295K n = 0.60g O2 1 mol O2 = 0.01875 mol 32.0g O2 PV = nRT P(5.0L) = (0.01875mol)(0.0821Latm/molK)(295K) P = 0.091 atm

Example How many grams of krypton are present in a 600 Example How many grams of krypton are present in a 600. Ml container at 1010oC in which the pressure of krypton is 10.0 atm? P = 10.0 atm V= 600.mL = 0.600 L n = ? R = 0.0821 (L.atm)/(mol.K) T = 1010oC + 273 = 1283K PV = nRT (10.0atm)(0.600L)= n(0.0821 L.atm)/(mol.K)(1283K) n = 0.05696 mol Kr 0.05696mol Kr 83.8g Kr = 4.77g Kr 1 mol Kr

How many atoms is this? 0.05696 mol Kr 6.02 x 1023 atoms Kr 1 mol Kr = 3.43 x 1022 atoms Kr

At STP, 1 mol (6.02 x 1023 particles of gas) = 22.4L Avogadro’s Hypothesis- Equal volumes of gases at the same temperature and pressure have equal numbers of particles. STP = 1 atm and 0oC At STP, 1 mol (6.02 x 1023 particles of gas) = 22.4L

Scuba Science SCUBA = Self Contained Underwater Breathing Apparatus

At the surface, pressure is 1 atm At the surface, pressure is 1 atm. It increases 1 atm for every 10 m underwater. At 30 m, the pressure is 4 atm. At 40m, pressure of 5 atm would not allow you to inflate your lungs to breathe. Scuba gear increases the pressure in your lungs as you descend, allowing normal breathing.

If a diver ascends without exhaling, the increase in lung volume could cause the lungs to rupture. From 40m (5 atm) to the surface (1 atm), would cause the lungs to increase in volume 5 times!

Divers may also experience “the bends”, a condition in which nitrogen dissolves in the blood at high pressures and then comes out as bubbles as the pressure is decreased, causing death.

Bellwork Monday, January 13th A diver descends from 10m under water to 50m underwater. What is the pressure, in atm, on the diver at this depth? Use circles to represent the lungs and show what happens to them as the diver descends.

Bellwork monday, January 14th Why is the boiling point of water in Denver Colorado 2 degrees lower than the boiling point of water in College Station? (Explain in 2-3 sentences!)

Bellwork Tuesday, January 15th A gas takes up 14.8 liters at 24oC. What temperature in kelvin is required to obtain a volume of 25.0 liters if the pressure is held constant? How many moles of chlorine gas are present at 25oC if the pressure is 762 torr and the volume is 14.2 L?