Example 1 Identifying Parts of an Expression Identify the terms, coefficients, like terms, and constant terms of the expression. 2+5x5x3–7x7x– SOLUTION.

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Example 1 Identifying Parts of an Expression Identify the terms, coefficients, like terms, and constant terms of the expression. 2+5x5x3–7x7x– SOLUTION Write the expression as a sum:. 2+5x5x ()() 3 – +7x7x – + Terms:Like terms: 5x, 2,, 7x7x – 3 – 5x and ; 2 and 7x7x – 3 – Coefficients:Constant terms: 5,5, 7 – 2,2, 3 –

Example 2 Combining Like Terms a. 4x4x+3x3x () 4+3x = Distributive property 7x7x = Add inside grouping symbols. b. 5z5z+7y7y 9y9y – + () 7+9y = Distributive property – 5z5z+ = Add inside grouping symbols. 5z5z+ 2y2y –

Example 3 Simplifying Expressions a. () x+42x+ Distributive property = 2x2x+x+8 Combine like terms. = 3x3x+8 b. –() 7y7y+6–3y3y5 Distributive property y – 7y7y+ = Combine like terms y8y – =

Guided Practice 1. for Examples 1, 2, and 3 Identify the terms, coefficients, like terms, and constant terms of the expression 4x4x1– 8x8x y.y. ++ 4y4y– 2.Simplify the expression by combining like terms. 3b3b+17ab–4a4a– 2b2b+13a ANSWER terms: 4x,,, 8x, y ; coefficients: 4, – 4, 8, 1 ; 4y4y – 1 – like terms: 4x and 8x, 4y and y ; constant term: – ANSWER 1 –

Guided Practice 3. for Examples 1, 2, and 3 Simplify the expression. () z+632z2z– ANSWER 18z––