Stock Solutions Different experiments require solutions of various different molarities. It would not be practical to have multiple bottles of each type.

Slides:



Advertisements
Similar presentations
SOLUTIONS Concentration Measurement: Molarity
Advertisements

1 Chapter 10 Acids and Bases 10.10Dilutions. 2 Dilution Diluting a solution Is the addition of water. Decreases concentration. ConcentratedDilutedSolution.
Concentration of Solutions. Concentrations of Solutions (Section 2.5) Concentration = quantity of solute quantity of solution A solution is dilute if.
Solution Concentration. Calculations of Solution Concentration: Mass Percent Mass percent Mass percent is the ratio of mass units of solute to mass units.
Taking a concentrated solution and making it less concentrated.
Topic: Dilution Do Now:
Examples-Molarity and Dilutions. Example What is the molarity of a solution that contains 4.5 moles of sucrose in L of water?
TOPIC: Concentration and Dilution Do Now:. Parts of a Solution SoluteSolute = dissolved substance SolventSolvent = dispersing medium.
Chapter 12 Solutions 12.5 Molarity and Dilution.
CONCENTRATION OF SOLUTIONS Day 4 CONCENTRATION  A measurement of the amount of solute in a given amount of solvent or solution (unit of measurement.
Dilutions. Solve problems involving the dilution of solutions. Include: dilution of stock solutions, mixing common solutions with different volumes and.
Thursday, March 6, 2008 Discussion of Molarity Lab Results Introduce Section 15.2b -- Dilutions Homework: Pg. 555, #31a-d, 32, 33, 34.
Unit 10B Review Reg Chem When a solution sits out over a long period of time and water evaporates the concentration of the solution __________.
Molar Concentration. Measuring Concentration Molarity (M): the number of moles of solute in 1 liter solution. Example: 0.5 moles of NaCl dissolved in.
Solution Concentration Section 14.2 Concentration - amount of solute dissolved in a specific amount of solvent concentrated - a lot of solute dilute.
Preparing a Molar Solution
Concentration/Dilution
Molarity = Molarity ( M ) moles solute liters of solution
Solutions: Molarity. A. Concentration – measure of the amount of solute that is dissolved in a given amount of solvent I. Concentration of Solutions Solutions:
Notes 15.2 Describing Solution Composition. Mass Percent Mass percent= mass of solute X 100 mass of solution = grams of solute X 100 grams of solute +
a measure of the amount of solute that is dissolved in a given quantity of solvent unit of measurement is Molarity (M) which is moles/liter can be dilute.
Section 15.2 Describing Solution Composition 1. To understand mass percent and how to calculate it Objective.
II III I II. Solution Concentration (p. 480 – 488) Ch. 14 – Mixtures & Solutions.
CONCENTRATION OF SOLUTIONS. Solute + The amount of solution can be expressed by: - mass m (g, kg) or - volume V (cm 3, mL, dm 3, L, m 3 ) m = V x  -
Section 15.2 Describing Solution Composition 1. To understand mass percent and how to calculate it 2. To understand and use molarity 3. To learn to calculate.
Daily Inquiry: 1.Many solutions are described as concentrated or dilute. Distinguish between these two terms. 2.A solution is made by dissolving 4.75 g.
Solution Concentration. Concentration Describes the amount of solute dissolved in a specific amount of solvent.
Solutions, Problems, Solutions, Problems. Does it ever end?
Making Dilutions. Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles does not change. Higher molarity.
Concentration  A measure of how much solute is dispersed throughout the solvent  Molarity (M), molality (m), and mole fraction ( χ ), mass percent.
Daily Inquiry: 1.Many solutions are described as concentrated or dilute. Distinguish between these two terms. 2.A solution is made by dissolving 4.75 g.
Solutions & Solubility Solution Preparation by dilution.
Dilutions.
Dilution of Solutions.
Making Molar Solutions From Liquids (More accurately, from stock solutions)
DILUTION CALCULATIONS Molarity of Mixture = total moles of chemical in which we are interested total volume of mixture Dilute Solution – a solution with.
TEKS 10C: Calculate the concentration of solutions in units of molarity. TEKS 10D: Use molarity to calculate the dilutions of solutions. What are dilute.
Solution Preparation and Dilutions. Solution Preparation How do we create chemical solutions in a laboratory setting with a certain concentration/molarity?
1 Learning Check If we dissolve 40.55g of FeCl 3 in enough water to make 500. mL of the solution, what is the molarity of the solution? Convert all unit:
Dilutions. A dilution occurs when water is added to a concentrated solution. Because only water is being added, the moles of solute is unchanged. When.
Solutions Molarity = concentration term used to describe an amount of solute dissolved in a given amount of solvent. Concentrated solution = contains large.
Making Solutions and Dilutions Unit 13 – PPT 2. Molarity  M = moles solute/liters of solution  Uses the symbol M  Example:  2 moles of glucose are.
CONCENTRATION AND DILUTIONS. Concentrations of Solutions ■a dilute solution contains only a small amount of solute ■concentrated solution contains a large.
Chapter Four Reactions in Aqueous Solutions. Chapter Four / Reactions in Aqueous Solutions Solutions and concentrations Solution is a homogenous mixture.
Molarity & Dilutions. Molarity Concentration – Measure of the amount of solute that is dissolved in a given quantity of solvent Dilute solution – Contains.
Solution Concentrations The measured amount of solute in a given amount of solvent or solution.
Two methods for Preparation of a desired volume of a Molar Solution  1) Preparation from a solid solute.  2) Preparation by Dilution of a Concentrated.
Solution Concentration
DILUTING A STOCK SOLN To make a soln less concentrated: add solvent
Solutions Review What is the molarity of a solution made by dissolving 0.35 mol in 145 milliliters of solution?
Molarity (M): State the ratio between the number of moles of solute & the volume of solution (in liters). Molarity (M) =
Ch Concentration Units
Solutions Concentration.
Do Now: Define the term concentration as it relates to a solute in a solution. C. Johannesson.
Section 2: Concentration
Molarity & Dilution.
Molarity and Dilution Solution Chemistry.
Solution Concentration
Unit 8: Concentration and Molarity (M)
Solutions Section 3: Dilutions Dilutions Calculations print 1-3,5-7.
Environmental Chemistry Lesson # 1
Unit 3, Lesson 14: Dilutions
Which one of these is more concentrated?
Dilutions.
Dilutions M1V1=M2V2.
Solution Concentration
Molarity REview.
Concentration = # of moles volume (L) V = 1000 mL V = 1000 mL
Preparing Solutions by Dilution
Molarity (M): State the ratio between the number of moles of solute & the volume of solution (in liters). Molarity (M) =
Presentation transcript:

Stock Solutions Different experiments require solutions of various different molarities. It would not be practical to have multiple bottles of each type of solution for each different molarity needed. Concentrated (lots of moles per volume) stock solutions are stored for use in experiments. These solutions are diluted to the desired concentration as needed.

Dilution Dilution: The process of adding more solvent to a solution – Our aqueous solution are diluted by adding more water IMPORTANT: ***Only more water is added during a dilution!!! The amount of solute (number of moles) stays the same! *** Amount(moles) = sameVolume(Liters) = changes

Dilution—decrease in concentration M = moles of solute volume (L) DECREASES Stays the SAME! INCREASES (We’re adding water!)

Dilution Example How would you prepare 0.500L of 1.00M acetic acid from a 17.5M stock solution? – How many moles of acetic acid are required? L solution x 1.00 mol HC 2 H 3 O 2 = mol HC 2 H 3 O 2 L solution – What volume of the stock solution contains moles of HC 2 H 3 O 2 ? V x 17.5 mol HC 2 H 3 O 2 = mol HC 2 H 3 O 2 L solution V = L = 28.6mL of stock solution diluted to 500mL Don’t forget! M = mol ! L

17.5M HC 2 H 3 O mL 500mL 28.6 mL 500mL Add WATER to 500 mL mark 1.00M HC 2 H 3 O 2

Let’s make those calculations easier… Since the number of moles stays the same, we can simply write: M 1 X V 1 = moles of solute = M 2 X V 2 M 1 X V 1 = M 2 X V 2