Holt Geometry Medians and Altitudes of Triangles Entry Task 1. How do you multiply fractions? What is 2/3 * 1/5? Find the midpoint of the segment with.

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Presentation transcript:

Holt Geometry Medians and Altitudes of Triangles Entry Task 1. How do you multiply fractions? What is 2/3 * 1/5? Find the midpoint of the segment with the given endpoints. 2. (–1, 6) and (3, 0) Straight across: 2/15 (1, 3) LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Learning Target: I can apply properties of medians and altitudes of a triangle. Success Criteria: I can find the orthocenters and centroid of a triangle and apply its properties 5.4 Medians and Altitudes LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles A median of a triangle is a segment whose endpoints are a vertex of the triangle and the midpoint of the opposite side. Every triangle has three medians, and the medians are concurrent. LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles The point of concurrency of the medians of a triangle is the centroid of the triangle. The centroid is always inside the triangle. The centroid is also called the center of gravity because it is the point where a triangular region will balance. LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Example 1A: Using the Centroid to Find Segment Lengths In ∆LMN, RL = 21 and SQ =4. Find LS. LS = 14 Centroid Thm. Substitute 21 for RL. Simplify. LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Example 1B: Using the Centroid to Find Segment Lengths In ∆LMN, RL = 21 and SQ =4. Find NQ. Centroid Thm. NS + SQ = NQ Seg. Add. Post. 12 = NQ Substitute 4 for SQ. Multiply both sides by 3. Substitute NQ for NS.Subtract from both sides. LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Check It Out! Example 1a In ∆JKL, ZW = 7, and LX = 8.1. Find KW. Centroid Thm. Substitute 7 for ZW. Multiply both sides by 3. KW = 21 LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Check It Out! Example 1b In ∆JKL, ZW = 7, and LX = 8.1. Find LZ. Centroid Thm. Substitute 8.1 for LX. Simplify. LZ = 5.4 LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles An altitude of a triangle is a perpendicular segment from a vertex to the line containing the opposite side. Every triangle has three altitudes. An altitude can be inside, outside, or on the triangle. LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles In ΔQRS, altitude QY is inside the triangle, but RX and SZ are not. Notice that the lines containing the altitudes are concurrent at P. This point of concurrency is the orthocenter of the triangle. The height of a triangle is the length of an altitude. Helpful Hint LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Orthocenter ObtuseRightAcute LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Assignment # Homework– p. 312 #5, 8-13,17-20,24-28 Challenge - #36 LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Altitudes and Medians Cut out 2 acute triangles. Make them straight and do it quickly Do problems 29 and 30 on page 314. When you show Mrs. Amoth or myself you are finished you may begin the homework. LT: I can apply properties of medians and altitudes of a triangle

Holt Geometry Medians and Altitudes of Triangles Lesson Quiz Use the figure for Items 1–3. In ∆ABC, AE = 12, DG = 7, and BG = 9. Find each length. 1. AG 2. GC 3. GF For Items 4 and 5, use ∆MNP with vertices M (–4, –2), N (6, –2), and P (–2, 10). Find the coordinates of each point. 4. the centroid 5. the orthocenter (0, 2) LT: I can apply properties of medians and altitudes of a triangle