Chapter 5 Applications of the Exponential and Natural Logarithm Functions.

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Goldstein/Schneider/Lay/Asmar, CALCULUS AND ITS APPLICATIONS, 11e – Slide 1 of 47 Chapter 5 Applications of the Exponential and Natural Logarithm Functions.

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Presentation transcript:

Chapter 5 Applications of the Exponential and Natural Logarithm Functions

§ 5.1 Exponential Growth and Decay

Exponential Growth DefinitionExample Exponential Growth: A quantity, such that, at every instant the rate of increase of the quantity is proportional to the amount of the quantity at that instant

Exponential Growth & Decay Model

Exponential Growth in ApplicationEXAMPLE (World’s Population) The world’s population was 5.51 billion on January 1, 1993 and 5.88 billion on January 1, Assume that at any time the population grows at a rate proportional to the population at that time. In what year will the world’s population reach 7 billion?

Exponential Decay DefinitionExample Exponential Decay: A quantity, such that, at every instant the rate of decrease of the quantity is proportional to the amount of the quantity at that instant

Exponential Decay in ApplicationEXAMPLE (Radioactive Decay) Radium-226 is used in cancer radiotherapy, as a neutron source for some research purposes, and as a constituent of luminescent paints. Let P(t) be the number of grams of radium-226 in a sample remaining after t years, and suppose that P(t) satisfies the differential equation (a) Find the formula for P(t). (b) What was the initial amount? (c) What is the decay constant? (d) Approximately how much of the radium will remain after 943 years? (e) How fast is the sample disintegrating when just one gram remains? Use the differential equation.

Exponential Decay in ApplicationCONTINUED (f) What is the weight of the sample when it is disintegrating at the rate of grams per year? (g) The radioactive material has a half-life of about 1612 years. How much will remain after 1612 years? 3224 years?

§ 5.2 Compound Interest

Compound Interest: Non-Continuous P = principal amount invested m = the number of times per year interest is compounded r = the interest rate t = the number of years interest is being compounded A = the compound amount, the balance after t years

Compound Interest Notice that as m increases, so does A. Therefore, the maximum amount of interest can be acquired when m is being compounded all the time - continuously.

Compound Interest: Continuous P = principal amount invested r = the interest rate t = the number of years interest is being compounded A = the compound amount, the balance after t years

Compound Interest: ContinuousEXAMPLE (Continuous Compound) Ten thousand dollars is invested at 6.5% interest compounded continuously. When will the investment be worth $41,787?

Compound Interest: Present Value

EXAMPLE (Investment Analysis) An investment earns 5.1% interest compounded continuously and is currently growing at the rate of $765 per year. What is the current value of the investment?