Practice Problems Actex Sections 6, 7. Section 6 -- #3 A company prices its hurricane insurance using the following assumptions: – In any calendar year,

Slides:



Advertisements
Similar presentations
Stats for Engineers Lecture 5
Advertisements

Fall 2008 Version Professor Dan C. Jones FINA 4355 Class Problem.
Continuous Random Variables and the Central Limit Theorem
The UNIVERSITY of NORTH CAROLINA at CHAPEL HILL Chapter 5. Continuous Probability Distributions Sections 5.4, 5.5: Exponential and Gamma Distributions.
Sampling Distributions Martina Litschmannová K210.
Continuous Distributions
Areas Under Any Normal Curve
Continuous Random Variables. L. Wang, Department of Statistics University of South Carolina; Slide 2 Continuous Random Variable A continuous random variable.
Part 9: Normal Distribution 9-1/47 Statistics and Data Analysis Professor William Greene Stern School of Business IOMS Department Department of Economics.
Risk Pooling in Insurance If n policies, each has independent probability p of a claim, then the number of claims follows the binomial distribution. The.
The Poisson Probability Distribution
October 5, 2006Purdue University Reserves James Miles, FSA, MAAA October 5, 2006.
Introduction Before… Next…
Section 09.  This table is on page 280 of the Actex manual Distribution of XiDistribution of Y Bernoulli B(1,p)Binomial B(k,p) Binomial.
Section 10.  An insurance policy is a contract between the party that is at risk (the policyholder) and the insurer  The policyholder pays a premium.
The Poisson Probability Distribution The Poisson probability distribution provides a good model for the probability distribution of the number of “rare.
© 2010 Pearson Education Inc.Goldstein/Schneider/Lay/Asmar, CALCULUS AND ITS APPLICATIONS, 12e – Slide 1 of 15 Chapter 12 Probability and Calculus.
Problems Problems 3.75, 3.80, Random Variables.
Jeopardy Statistics Edition. Terms General Probability Sampling Distributions Confidence Intervals Hypothesis Tests: Proportions Hypothesis Tests: Means.
Two-Sample Inference Procedures with Means. Two-Sample Procedures with means two treatments two populationsThe goal of these inference procedures is to.
Chapter 8 – Further Applications of Integration 8.5 Probability 1Erickson.
Insurance Jeopardy AutoInsuranceHomeownersLifeHealth
Section 06. The Bernoulli distribution is a special case where n=1!
Ch4: 4.3The Normal distribution 4.4The Exponential Distribution.
Poisson Random Variable Provides model for data that represent the number of occurrences of a specified event in a given unit of time X represents the.
Practice Problems Actex 8. Section 8 -- #5 Let T 1 be the time between a car accident and reporting a claim to the insurance company. Let T 2 be the time.
Probabilistic and Statistical Techniques 1 Lecture 19 Eng. Ismail Zakaria El Daour 2010.
 A probability function is a function which assigns probabilities to the values of a random variable.  Individual probability values may be denoted by.
1 INTRODUCTION TO HYPOTHESIS TESTING. 2 PURPOSE A hypothesis test allows us to draw conclusions or make decisions regarding population data from sample.
Random Variables and Probability Models
Expected value. Question 1 You pay your sales personnel a commission of 75% of the amount they sell over $2000. X = Sales has mean $5000 and standard.
 A probability function is a function which assigns probabilities to the values of a random variable.  Individual probability values may be denoted.
Definition A random variable is a variable whose value is determined by the outcome of a random experiment/chance situation.
A life insurance company sells a term insurance policy to a 21-year-old male that pays $100,000 if the insured dies within the next 5 years. The probability.
Section 02. An insurance company pays hospital claims. The number of claims that include emergency room or operating room charges is 85% of.
The final exam solutions. Part I, #1, Central limit theorem Let X1,X2, …, Xn be a sequence of i.i.d. random variables each having mean μ and variance.
Example-1: An insurance company sells a 10,000 TRL 1-year term insurance policy at an annual premium of 290 TRL. Based on many year’s information, the.
2008 Probability Distributions. Question One Sillicom find from their broadband customer service hotline that 15% of their broadband customers have problems.
Slide PURCHASING CONSIDERATIONS Discuss insurability and probability. Explain product options, price, and company ratings. GOALS GOALS.
 A probability function is a function which assigns probabilities to the values of a random variable.  Individual probability values may be denoted.
1 Sampling distributions The probability distribution of a statistic is called a sampling distribution. : the sampling distribution of the mean.
Section 5.2: PROBABILITY AND THE NORMAL DISTRIBUTION.
Statistics Sampling Distributions and Point Estimation of Parameters Contents, figures, and exercises come from the textbook: Applied Statistics and Probability.
12.1 Discrete Probability Distributions (Poisson Distribution)
Week 21 Statistical Model A statistical model for some data is a set of distributions, one of which corresponds to the true unknown distribution that produced.
Chapter5 Statistical and probabilistic concepts, Implementation to Insurance Subjects of the Unit 1.Counting 2.Probability concepts 3.Random Variables.
Practice Problems Actex 3, 4, 5. Section 3 -- #3 A box contains 4 red balls and 6 white balls. A sample of size 3 is drawn without replacement from the.
The Poisson Distribution. The Poisson Distribution may be used as an approximation for a binomial distribution when n is large and p is small enough that.
Homework #4 Solution Daily amount of raining in winter at Gaza is by ml cube, A random variable X have a continuous uniform distribution with A = 100 ml.
8.2 The Geometric Distribution 1.What is the geometric setting? 2.How do you calculate the probability of getting the first success on the n th trial?
Practice Problems Actex 10. Section #1 An insurance policy pays an individual 100 per day for up to 3 days of hospitalization and 25 per day for.
Review of Risk Management Concepts
A life insurance company sells a term insurance policy to a 21-year-old male that pays $100,000 if the insured dies within the next 5 years. The probability.
Chapter 5 Discrete Probability Distributions
Example: Given below is a company’s future prospect
The Poisson Probability Distribution
Section 6.3 The Poisson Probability Distribution
Random Variable 2013.
Functions and Transformations of Random Variables
Homework #3 Solution Write the distribution for formula and determine whether it is a probability distribution or not if it is then calculated mean, variance.
Continuous Random Variables
Chapter 2 Hypothesis Testing Test for one and two means
In-Class Exercise: The Poisson Distribution
Exponential and Poisson Distributions
LESSON 12: EXPONENTIAL DISTRIBUTION
The Normal Probability Distribution Summary
Areas Under Any Normal Curve
No Tutoring Today! Warm-Up… Quickwrite…
The Geometric Distributions
Example: Given below is a company’s future prospect
Presentation transcript:

Practice Problems Actex Sections 6, 7

Section 6 -- #3 A company prices its hurricane insurance using the following assumptions: – In any calendar year, there can be at most one hurricane. – In any calendar year, the probability of a hurricane is – The number of hurricanes in any calendar year is independent of the number of hurricanes in any other calendar year. Using these assumptions, calculate the probability that there are fewer than 3 hurricanes in a 20-year period. Answer:

Section 6 -- #9 An actuary has discovered that policyholders are three times as likely to file 2 claims as to file 4 claims. If the number of claims has a Poisson distribution, what is the variance of the number of claims filed? Answer: 2

Section 6 -- #10 An insurance policy on an electrical device pays a benefit of 4000 if the device fails during the first year. The amount of the benefit decreases by 1000 each successive year until it reaches 0. If the device has not failed by the beginning of any given year, the probability of failure during that year is 0.4. What is the expected benefit under this policy? Answer:

Section 6 -- #13 A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% high-risk drivers. Because these drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This month, the insurance company writes 4 new policies. What is the probability that these 4 will contain at least two more high-risk drivers than low-risk drivers? Answer:

Section 6 -- #25 A company takes out an insurance policy to cover accidents that occur at its manufacturing plant. The probability that one or more accidents will occur during any given month is 3/5. The number of accidents that occur in any given month is independent of the number of accidents that occur in all other months. Calculate the probability that there will be at least four months in which no accidents occur before the fourth month in which at least one accident occurs. Answer:

Section 7 -- #11 Two instruments are used to measure the height, h, of a tower. The error made by the less accurate instrument is normally distributed with mean 0 and standard deviation h. The error made by the more accurate instrument is normally distributed with mean 0 and standard deviation h. Assuming the two measurements are independent random variables, what is the probability that their average value is within 0.005h of the height of the tower? Answer:

Section 7 -- #13 The lifetime of a printer costing $200 is exponentially distributed with a mean 2 years. The manufacturer agrees to pay a full refund to a buyer if the printer fails during the first year following its purchase, and one-half refund if it fails during the second year. If the manufacturer sells 100 printers, how much should it expect to pay in refunds? Answer:

Section 7 -- #15 The time to failure of a component in an electronic device has an exponential distribution with a median of 4 hours. Calculate the probability that the component will work without failing for at least 5 hours. Answer: 0.42