Do Now What is a hyperbola? What is the equation of a hyperbola?

Objective After teaching students how to understand and analyze the geometry of a hyperbola SWBAT understand and analyze the geometry of a hyperbola

Direct Instruction What is a hyperbola, how can it be used in the real world? Equation for a hyperbola Find the focal axis, foci, vertices, semitransverse, semiconjugate axis’ and asymptotes of (x-0) 2 -(y-0) 2 =1 5 4

Guided Practice Find the focal axis, foci, vertices, semitransverse, semiconjugate axis’ and asymptotes of (x+2) 2 -(y-5) 2 = *LORAN-Coast Guard

Independent Practice Find the focal axis, foci, vertices, semitransverse, semiconjugate axis’ and asymptotes of the building bellow (x+2) 2 -(y-5) 2 =

Closure What did we learn today?

Exit Slip Tomorrow we are going to learn how to use hyperbolas to solve real world problems. – Write one goal for tomorrows lesson.

Do Now-Constructed Response 10 Minutes To find the equation of a parabola you need to find the vertex and use another point to find your “p” value. Determine the equation of a parabola and explain how you got it and why it is the right equation.

Objective After teaching students how to use hyperbolas to solve real world problems such as long range navigation SWBAT use hyperbolas to solve real world problems

Direct Instruction Find the equation of the hyperbola with foci (- 3, 0) and (3,0), whose conjugate axis has length 4.

Guided Practice -Find out how far out in the lake a swimmer is if: The life guard stand (center) of the hyperbola is (-3, 6) and the ocean meets the beach at (sqrt(12), 6). Also the Semiconjugate axis is sqrt(5).

Independent Practice Find out how far out in the ocean a stranded boat is if: The coast guard center is (center) placed at (0,0) and one vertices is (3, 0). Also the Semiconjugate axis is 2.

Closure What did we learn today?

Exit Slip Tell me – 3 Things you learned today – 2 Questions you have – 1 Thing you want me to know