REACTIONS OF HYDROCARBONS. 4.Reforming straight chain alkane  branched alkane 2.Substitution (with halides) alkane + halogen  haloalkane +hydrogen halide.

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Presentation transcript:

REACTIONS OF HYDROCARBONS

4.Reforming straight chain alkane  branched alkane 2.Substitution (with halides) alkane + halogen  haloalkane +hydrogen halide CH 4 + Cl 2  CH 3 Cl + HCl CH 3 Cl + Cl 2  CH 2 Cl 2 + HCl 3.Cracking larger alkane  (2) smaller alkanes + alkenes CH 3 -CH 2 -CH 2 -CH 3  CH 3 -CH 3 + CH 2 =CH 2 1.Combustion (Extreme Oxidation) Alkane + O 2  CO 2 + H 2 O ALKANES

Preparation of Alkanes 1.Inorganic Calcium acetate + calcium hydroxide  2 calcium carbonate + 2 methane 2.Organic (Hydrogenation of Alkenes) Alkene + hydrogen  alkane CH 2 = CH 2 + H 2  C 2 H 6

ALKENES 1.Addition Reactions (breaking of the  bond) A)Halogenation (adding halides) alkene + halogen  haloalkane B)Hydrogenation (adding hydrogen) alkene + hydrogen  alkane CH 2 =CH 2 + H 2  CH 3 CH 3

C)Hydrohalogenation (adding hydrogen halides) alkene + hydrogen halide  haloalkane Hydrohalogenation and hydration follow Markovnikov’s Rule which states that the hydrogen is added to the carbon with the most hydrogen atoms originally bonded to it. D)Hydration (adding water) alkene + water  alcohol

2.Combustion (extreme oxidation) Alkene + O 2  CO 2 + H 2 O 3.Polymerization (forming long chains from small subunits) Preparation of Alkenes 1. The Dehydration of Alcohols (reverse of 1 D) alcohol  alkene + water

ALKYNES 1.Addition Reactions (breaking of the  bond) A)Halogenation (adding halides) alkyne + 2 halogens  haloalkane B)Hydrogenation (adding hydrogen) alkyne + 2 hydrogen  alkane CH  CH + 2 H 2  CH 3 CH 3 C) Hydrohalogenation (adding hydrogen halides) alkyne + 2 hydrogen halides  haloalkane * Remember Markovnikov’s Rule *

C) Hydrohalogenation (adding hydrogen halides) alkyne + 2 hydrogen halides  haloalkane 2.Reaction as an Acid ethyne + sodium  sodium ethanide + hydrogen 2 HC  CH + Na  2 HC  C –1 Na +1 + H 2 * heavy metal ethanides can be explosive

Preparation of Ethyne Inorganic (limestone + coal) Ca CO 3  CaO + CO 2 CaO + 3 C  Ca C 2 + CO Ca C 2 + H 2 O  HC  CH + CaO

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