Pg. 255/268 Homework Pg. 277#32 – 40 all Pg. 310#1, 2, 7, 41 – 48 #6 left 2, up 4#14Graph #24 x = #28x = 6 #35 Graph#51r = 6.35, h = 9, V = 380 #1 Graph#3a)

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Pg. 255/268 Homework Pg. 277#32 – 40 all Pg. 310#1, 2, 7, 41 – 48 #6 left 2, up 4#14Graph #24 x = #28x = 6 #35 Graph#51r = 6.35, h = 9, V = 380 #1 Graph#3a) dec b) inc c) dec #5 Down 4#6Stretch 3 #7 Right 3#8Reflect x and y axes #9 Left 1, Up 7#15a = c

5.1 Exponential Functions Life Span Problems The formula for Life Span problems is similar to the continuous growth/decay equation using e. Population: Life Span: Suppose the half-life of a certain radioactive substance is 20 days and there are 5g present initially. – Write an equation to represent the situation. – Draw a complete graph. – Find when there will be less than 1g of the substance remaining.

5.2 Simple and Compound Interest Compound Interest Compound Interest is when financial institutions pay interest on the interest. (Yay… more money!) Suppose P dollars are invested at an interest rate r, then the compound interest formula for the total amount S after n interest periods is: Example Sally invests $500 at 7% interest compounded annually. Find the value of the investment after 10 years. How much should Sally invested at 6.25% compounded semi-annually in order to have an investment of $1,500 after 5 years?

5.2 Simple and Compound Interest Compound Interest Sally invests $1000 at 8%. Find the value of the investment after one year when it is compounded – Annually – Quarterly – Monthly – Weekly – Daily – Hourly – Continuously Continuous Interest If P dollars are invested at an APR, r, (in decimal form) and compounded continuously, then the value of the investment after t years is given by: S = Pe rt