Doppler Effect David William D. Ecoben III-Archimedes.

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Presentation transcript:

Doppler Effect David William D. Ecoben III-Archimedes

The Doppler Effect on Waves  The apparent change in pitch produced by moving objects is called the Doppler Effect.  Sound waves undergo the Doppler Effect. When the source of the waves moves at a constant speed relative to you, the observer, the frequency of the wave as observed by you is shifted.

For sound, the shifted frequency f observed, in hertz, is given by:  f observed = f source x (v source - v observer ) (v source - v sound ) Where: F source = frequency in hertz at the source of the sound V source = the speed in m/s of the source of the sound V observer = the speed in m/s of the observer, v source – v observer = the relative speed in m/s of the source with respect to the observer, and V sound = the speed of sound in m/s.

Example 12.5 Emergency A fire truck siren emits a sinusoidal wave with a source frequency f source of 400 Hz. The speed of sound is 340 m/s. Find the wavelength of the siren while at rest. If the truck is moving with velocity v source = 40 m/s, find the wavelength of the siren going nearer to and then away from a stationary observer.

Given: Source frequency f source 400 Hz Velocity of source v source 40 m/s Velocity of the observer v observer 0 Find a. Wavelength if the source is at rest b. Wavelength if the source is nearing the observer c. Wavelength if the source is going away from the observer

Solution:  A. When source is at rest, using the equation v = f λ Solving for λ, λ = v source f source λ = 340 m/s / 400 Hz λ = O.85 m

 B. In front of the siren, since the object is getting farther, then the speed of sound relative to the observer is v – v s, so  λ = (v – v source ) / f source  = (340 m/s – 40 m/s) / 400 Hz  λ = 0.75 m

c. Behind the siren, since the object is going nearer, then the speed of sound relative to the observer is v + v s, so λ = (v + v source ) / f source = (340 m/s + 40 m/s) / 400 Hz λ = 0.95 m