Example: [Z m ;+,*] is a field iff m is a prime number [a] -1 =? If GCD(a,n)=1,then there exist k and s, s.t. ak+ns=1, where k, s Z. ns=1-ak. [1]=[ak]=[a][k] [k]= [a] -1 Euclidean algorithm
Theorem 6.31(Fermat’s Little Theorem): if p is prime number, and GCD(a,p)=1, then a p-1 1 mod p Corollary 6.3: If p is prime number, a Z, then a p a mod p
Definition 27: The characteristic of a ring R with 1 is the smallest nonzero number n such that 0 = · · · + 1 (n times) if such an n exists; otherwise the characteristic is defined to be 0. We denoted by char(R). Theorem 6.32: Let p be the characteristic of a ring R with e. Then following results hold. (1)For a R, pa=0. And if R is an integral domain, then p is the smallest positive number such that 0=la, where a 0. (2)If R is an integral domain, then the characteristic is either 0 or a prime number.
6.6.3 Ring homomorphism Definition 28: A function : R→S between two rings is a homomorphism if for all a, b R, (1) (a + b) = (a) + (b), (2) (ab) = (a) (b) An isomorphism is a bijective homomorphism. Two rings are isomorphic if there is an isomorphism between them. If : R→S is a ring homomorphism, then formula (1) implies that is a group homomorphism between the groups [R; +] and [S; +’ ]. Hence it follows that (a) (0 R ) =0 S and (-a) = - (a) for all a R. where 0 R and 0 S denote the zero elements in R and S;
If : R→S is a ring homomorphism, (1 R ) = 1 S ? No Theorem 6.33: Let R be an integral domain, and char(R)=p. The function :R R is given by (a)=a p for all a R. Then is a homomorphism from R to R, and it is also one-to-one.
6.6.4 Subring, Ideal and Quotient ring 1. Subring Definition 29: A subring of a ring R is a nonempty subset S of R which is also a ring under the same operations. Example :
Theorem 6.34: A subset S of a ring R is a subring if and only if for a, b S : (1)a+b S (2)-a S (3)a·b S
Example: Let [R;+,·] be a ring. Then C={x|x R, and a·x=x·a for all a R} is a subring of R. Proof: For x,y C, x+y,-x ?C, x·y? C i.e. a R,a·(x+y)=?(x+y)·a,a·(-x)=?(-x)·a,a·(x·y) =?(x·y)·a
2.Ideal( 理想 ) Definition 30:. Let [R; +, * ] be a ring. A subring S of R is called an ideal of R if rs S and sr S for any r R and s S. To show that S is an ideal of R it is sufficient to check that (a) [S; +] is a subgroup of [R; + ]; (b) if r R and s S, then rs S and sr S.
Example: [R;+,*] is a commutative ring with identity element. For a R , (a)={a*r|r R},then [(a);+,*] is an ideal of [R;+,*]. If [R;+,*] is a commutative ring, For a R, (a)={a*r+na|r R,n Z }, then [(a);+,*] is an ideal of [R;+,*].
Principle ideas Definition 31: If R is a commutative ring and a R, then (a) ={a*r+na|r R} is the principle ideal defined generated by a. Example: Every ideal in [Z;+,*] is a principle. Proof: Let D be an ideal of Z. If D={0}, then it holds. Suppose that D {0}. Let b=min a D {|a| | a 0,where a D}.
3. Quotient ring Theorem 6.35: Let [R; +,*] be a ring and let S be an ideal of R. If R/S ={S+a|a R} and the operations and on the cosets are defined by (S+a) (S+b)=S+(a + b) ; (S+a) (S+b) =S+(a*b); then [R/S; , ] is a ring. Proof: Because [S;+] is a normal subgroup of [R;+], [R/S; ] is a group. Because [R;+] is a commutative group, [R/S; ] is also a commutative group. Need prove [R/S; ] is an algebraic system, a sumigroup, distributive laws
Definition 32: Under the conditions of Theorem 6.35, [R/S; , ] is a ring which is called a quotient ring.
Definition 33: Let be a ring homomorphism from ring [R;+,*] to ring [S;+’,*’]. The kernel of is the set ker ={x R| (x)=0 S }. Theorem 6.36: Let be a ring homomorphism from ring [R;+,*] to ring [S;+’,*’]. Then (1)[ (R);+’,*’] is a subring of [S;+’,*’] (2)[ker ;+,*] is an ideal of [R;+,*].
Theorem 6.37(fundamental theorem of homomorphism for rings): Let be a ring homomorphism from ring [R;+,*] to ring [S;+’,*’]. Then [R/ker ; , ] [ (R);+’,*’]
Exercise: 1. Determine whether the function : Z→Z given by f(n) =2n is a ring homomorphism. 2. Let f : R→S be a ring homomorphism, with A a subring of R. Show that f(A) is a subring of S. 3. Let f: R→S be a ring homomorphism, with A an ideal of R. Does it follow that f(A) is an ideal of S? 4.Prove Theorem 6.36