Heaps1 2 65 79 © 2010 Goodrich, Tamassia. Heaps2 Priority Queue ADT  A priority queue (PQ) stores a collection of entries  Typically, an entry is a.

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Heaps © 2010 Goodrich, Tamassia

Heaps2 Priority Queue ADT  A priority queue (PQ) stores a collection of entries  Typically, an entry is a pair (key, value), where the key indicates the priority  Main methods of the Priority Queue ADT insert(e) inserts an entry e removeMin() removes the entry with smallest key  Additional methods min(), size(), empty()  Applications: Standby flyers Auctions Stock market  Time complexity of two implementations of PQ © 2010 Goodrich, Tamassia

Heaps3 PQ Sorting  We use a priority queue Insert the elements with a series of insert operations Remove the elements in sorted order with a series of removeMin operations  The running time depends on the priority queue implementation: Unsorted sequence using selection sort: O(n 2 ) time Sorted sequence using insertion sort: O(n 2 ) time  Can we do better? Algorithm PQ-Sort(S, C) Input sequence S, comparator C for the elements of S Output sequence S sorted in increasing order according to C P  priority queue with comparator C while  S.empty () e  S.front(); S.eraseFront() P.insert (e,  ) while  P.empty() e  P.removeMin() S.insertBack(e) © 2010 Goodrich, Tamassia

Two Paradigms of PQ Sorting  PQ via selection sort  PQ via insertion sort © 2010 Goodrich, TamassiaHeaps4

5  A heap is a binary tree storing keys at its nodes and satisfying the following properties:  Heap-Order: for every internal node v other than the root, key(v)  key(parent(v))  Complete Binary Tree: let h be the height of the heap for i  0, …, h  1, there are 2 i nodes of depth i at depth h  1, the internal nodes are to the left of the external nodes  The last node of a heap is the rightmost node of maximum depth last node © 2010 Goodrich, Tamassia Min heap

Heaps6 Height of a Heap  Theorem: A heap storing n keys has height O(log n) Proof: (we apply the complete binary tree property) Let h be the height of a heap storing n keys Since there are 2 i keys at depth i  0, …, h  1 and at least one key at depth h, we have n  1  2  4  …  2 h  1  1 Thus, n  2 h, i.e., h  log n 1 2 2h12h1 1 keys 0 1 h1h1 h depth © 2010 Goodrich, Tamassia

Heaps7 Heaps and Priority Queues  We can use a heap to implement a priority queue  We store a (key, element) item at each internal node  We keep track of the position of the last node (2, Sue) (6, Mark)(5, Pat) (9, Jeff)(7, Anna) © 2010 Goodrich, Tamassia

Heaps8 Insertion into a Heap  Method insertItem of the priority queue ADT corresponds to the insertion of a key k to the heap  The insertion algorithm consists of three steps Find the insertion node z (the new last node) Store k at z Restore the heap-order property (discussed next) insertion node z z © 2010 Goodrich, Tamassia

Heaps9 Upheap  After the insertion of a new key k, the heap-order property may be violated  Algorithm upheap restores the heap-order property by swapping k along an upward path from the insertion node  Upheap terminates when the key k reaches the root or a node whose parent has a key smaller than or equal to k  Since a heap has height O(log n), upheap runs in O(log n) time z z © 2010 Goodrich, Tamassia

Upheap: More Example © 2010 Goodrich, TamassiaHeaps10 Original last node Newly added node Up-heap bubbling

Heaps11 Removal from a Heap (§ 7.3.3)  Method removeMin of the priority queue ADT corresponds to the removal of the root key from the heap  The removal algorithm consists of three steps Replace the root key with the key of the last node w Remove w Restore the heap-order property (discussed next) last node w w new last node © 2010 Goodrich, Tamassia

Heaps12 Downheap  After replacing the root key with the key k of the last node, the heap-order property may be violated  Algorithm downheap restores the heap-order property by swapping key k along a downward path from the root  Upheap terminates when key k reaches a leaf or a node whose children have keys greater than or equal to k  Since a heap has height O(log n), downheap runs in O(log n) time w w © 2010 Goodrich, Tamassia

Downheap: More Example © 2010 Goodrich, TamassiaHeaps13 Move the last to top Down-heap bubbling

Heaps14 Updating the Last Node  The inserted node can be found by traversing a path of O(log n) nodes Go up until a left child or the root is reached If a left child is reached, go to the right child Go down left until a leaf is reached  Similar algorithm for updating the last node after a removal © 2010 Goodrich, Tamassia

Heaps15 Heap-Sort  Consider a priority queue with n items implemented by a heap the space used is O(n) methods insert and removeMin take O(log n) time methods size, empty, and min take time O(1) time  Heap-sort Sort a sequence of n elements in O(n log n) time using a heap-based PQ Much faster than quadratic sorting algorithms, such as insertion-sort and selection- sort © 2010 Goodrich, Tamassia

Heaps16 Vector-based Heap Implementation  We can represent a heap with n keys by means of a vector of length n  1  For the node at index i the left child is at index 2i the right child is at index 2i  1  Links between nodes are not explicitly stored  The cell of at index 0 is not used  Operation insert corresponds to inserting at index n  1  Operation removeMin corresponds to removing at index 0  Yields in-place heap-sort © 2010 Goodrich, Tamassia

In-place Heap Sort © 2010 Goodrich, TamassiaHeaps17 Stage 2: output Stage 1: Heap construction Sorted In heap

Heaps18 Merging Two Heaps  Given two heaps and a key k  Create a new heap with the root node storing k and the two heaps as subtrees  Perform downheap to restore the heap-order property © 2010 Goodrich, Tamassia

Heaps19  Goal: Construct a heap of n keys using a bottom-up method with log n phases  In phase i, pairs of heaps with 2 i  1 keys are merged into heaps with 2 i  1  1 keys Bottom-up Heap Construction 2 i  1 2i112i11 © 2010 Goodrich, Tamassia

Heaps20 Example © 2010 Goodrich, Tamassia

Heaps21 Example (contd.) © 2010 Goodrich, Tamassia

Heaps22 Example (contd.) © 2010 Goodrich, Tamassia

Heaps23 Example (end) © 2010 Goodrich, Tamassia

Heaps24 Analysis via Visualization  We visualize the worst-case time of a downheap with a proxy path that goes first right and then repeatedly goes left until the bottom of the heap (this path may differ from the actual downheap path)  Since each node is traversed by at most two proxy paths, the total number of nodes of the proxy paths is O(n)  Thus, bottom-up heap construction runs in O(n) time  Bottom-up heap construction is faster than n successive insertions and speeds up the first phase of heap-sort © 2010 Goodrich, Tamassia

Heaps25 Analysis via Math © 2010 Goodrich, Tamassia d=0 d=1 d=2 d=h-1 d=h