Section 2.4 Exact Equations.

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Presentation transcript:

Section 2.4 Exact Equations

TOTAL DIFFERENTIAL Definition: The total differential of a function z = f (x , y), with continuous first partial derivatives in a region R in the xy-plane is

TOTAL DIFFERENTIAL AND SOLUTION TO A DE For a family of curves, f (x , y) = c, its total differential d f(x , y) = 0, and hence is a solution of the first-order differential equation:

EXACT DIFFERENTIAL EQUATION Definition: A differential equation of the form M(x, y)dx + N(x, y)dy = 0 is said to be exact if there is a function, f (x, y), whose total differential, d f (x, y) = M(x, y)dx + N(x, y)dy.

CRITERION FOR AN EXACT DIFFERENTIAL EQUATION Theorem: Let M(x, y) and N(x, y) be continuous and have continuous first partial derivatives in a rectangular region R defined by a < x < b, c < y < d. The differential equation M(x, y)dx + N(x, y)dy = 0 is exact if and only if

SOLVING AN EXACT EQUATION 1. Show ∂M/∂y = ∂N/∂x. 2. Assume ∂f/∂x = M(x, y). Find f by integrating M(x, y) with respect to x, while holding y constant. We can write where the arbitrary function g(y) is the “constant” of integration. 3. Differentiate (1) with respect to y and set equal to N(x, y). This yields, after solving for g′(y), 4. Integrate (2) with respect to y and substitute the result into (1). The solution to the DE is f (x, y) = c.

INTEGRATING FACTORS It is sometimes possible to convert a nonexact differential equation into an exact equation by multiplying it by a function μ(x, y) called an integrating factor. NOTE: It is possible for a solution to be lost or gained as a result of multiplying by an integrating factor.

HOMEWORK 1–43 odd